# 2 sequences with arduino?

I am a beginner and done a few of the beginner projects and have learned a little. My question is can you run 2 sequences at the same time with an arduino? Here is a example, I would like to run 6 leds random and the other 6 in a sequence both going on at the same time. Is that possible?
John

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4 years ago
This code works

```/*

The circuit:
* LEDs from pins 2 through 13 to ground
*/

// these constants won't change:
const int ledCount = 12; // the number of LEDs in the bar graph

int ledpins[] = {
2, 3, 4, 5, 6, 7,8,9,10,11,12,13 }; // an array of pin numbers to which LEDs are attached
//First 6 pins are the steady sequence pins
//second six are the random number pins
int Ledsequence[] = {1,2,4,8,16,32,32,16,8,4,2,1}; //This is the flashing sequence
int Randomnumber =0;
int Tseq = 0;

void setup() {
// loop over the pin array and set them all to output:
for (int thisLed = 0; thisLed < ledCount; thisLed++) {
pinMode(ledpins[thisLed], OUTPUT);
digitalWrite(ledpins[thisLed],LOW);
}

}

void loop() {

for (int ctr=0;ctr<ledCount;ctr++)
{
Tseq = Ledsequence[ctr];

if ((Tseq & 1)==1) {digitalWrite(ledpins[0], HIGH);} else {digitalWrite(ledpins[0],LOW);}
if ((Tseq & 2)==2) {digitalWrite(ledpins[1],HIGH);} else {digitalWrite(ledpins[1] ,LOW);}
if ((Tseq & 4)==4) {digitalWrite(ledpins[2],HIGH);} else {digitalWrite(ledpins[2] ,LOW);}
if ((Tseq & 8)==8) {digitalWrite(ledpins[3],HIGH);} else {digitalWrite(ledpins[3] ,LOW);}
if ((Tseq & 16)==16) {digitalWrite(ledpins[4],HIGH);} else {digitalWrite(ledpins[4] ,LOW);}
if ((Tseq & 32)==32) {digitalWrite(ledpins[5],HIGH);} else {digitalWrite(ledpins[5] ,LOW);}
Randomnumber = random (33);

if ((Randomnumber & 1)==1) {digitalWrite(ledpins[6] ,HIGH);} else {digitalWrite(ledpins[6] ,LOW);}
if ((Randomnumber & 2)==2) {digitalWrite(ledpins[7] ,HIGH);} else {digitalWrite(ledpins[7] ,LOW);}
if ((Randomnumber & 4)==4) {digitalWrite(ledpins[8] ,HIGH);} else {digitalWrite(ledpins[8] ,LOW);}
if ((Randomnumber & 8)==8) {digitalWrite(ledpins[9] ,HIGH);} else {digitalWrite(ledpins[9] ,LOW);}
if ((Randomnumber & 16)==16) {digitalWrite(ledpins[10] ,HIGH);} else {digitalWrite(ledpins[10] ,LOW);}
if ((Randomnumber & 32)==32) {digitalWrite(ledpins[11] ,HIGH);} else {digitalWrite(ledpins[11] ,LOW);}
delay(100);
}

}

```
slowguy (author) 4 years ago
4 years ago
Moral: check your simulator really is doing what you think it is.

Try the NEW version above.

Steve
slowguy (author)  steveastrouk4 years ago
no new version above
4 years ago
Below.
slowguy (author)  steveastrouk4 years ago
13 through 8 just flash together at a random rate and 9 is off, does nothing. 7 through 2 are on solid.
4 years ago
Works on my hardware. Check your wiring, write a piece of test code that chases all the leds in sequence.
slowguy (author)  steveastrouk4 years ago
one last request. could you please resend the complete code to me one more time. I would appreciate it. Thanks
slowguy (author)  steveastrouk4 years ago
here is a video
slowguy (author)  steveastrouk4 years ago
I miss ed 2 other things you tolf me to do, change the count to 12 and change the loop. Now the leds flash.
slowguy (author)  steveastrouk4 years ago
I do not know what to say. I have loaded my 12 output randonizer and 12 output sequencer and they both work on either the nano and uno.
slowguy (author)  steveastrouk4 years ago
sorry it is 12 instead of 9 and it is on dim
4 years ago
Also, there is an extra ; in the for loop here.
for (ctr=0;ctr<11;ctr++);

delete the last ;

Either change the 11 to 12 or make it
for (ctr=0;ctr
4 years ago
Corrupted by the website

for (ctr=0;ctr < ledCount; ctr++)
4 years ago
Change LEDcount to 12.
4 years ago
Try commenting out the line randomseed(analogread(0) ) - I added that after iI tested it.
slowguy (author)  steveastrouk4 years ago
still nothing
4 years ago
steveastrouk4 years ago
/*

The circuit:
* LEDs from pins 2 through 13 to ground
*/

// these constants won't change:
const int ledCount = 10; // the number of LEDs in the bar graph

int ledpins[] = {
2, 3, 4, 5, 6, 7,8,9,10,11,12,13 }; // an array of pin numbers to which LEDs are attached
//First 6 pins are the steady sequence pins
//second six are the random number pins
int Ledsequence[] = {1,2,4,8,16,32,32,16,8,4,2,1}; //This is the flashing sequence
int Randomnumber =0;
int Tseq = 0;
int ctr =0 ;

void setup() {
// loop over the pin array and set them all to output:
for (int thisLed = 0; thisLed < ledCount; thisLed++) {
pinMode(ledpins[thisLed], OUTPUT);
}
}

void loop() {
for (ctr=0;ctr<11;ctr++);
{
Tseq = Ledsequence[ctr];
if (Tseq & 1==1) {digitalWrite(ledpins[0], HIGH);} else {digitalWrite(ledpins[0],LOW);}
if (Tseq & 2==2) {digitalWrite(ledpins[1],HIGH);} else {digitalWrite(ledpins[1] ,LOW);}
if (Tseq & 4==4) {digitalWrite(ledpins[2],HIGH);} else {digitalWrite(ledpins[2] ,LOW);}
if (Tseq & 8==8) {digitalWrite(ledpins[3],HIGH);} else {digitalWrite(ledpins[3] ,LOW);}
if (Tseq & 16==16) {digitalWrite(ledpins[4],HIGH);} else {digitalWrite(ledpins[4] ,LOW);}
if (Tseq & 32==32) {digitalWrite(ledpins[5],HIGH);} else {digitalWrite(ledpins[5] ,LOW);}
Randomnumber = random (32);
if (Randomnumber & 1==1) {digitalWrite(ledpins[6] ,HIGH);} else {digitalWrite(ledpins[6] ,LOW);}
if (Randomnumber & 2==2) {digitalWrite(ledpins[7] ,HIGH);} else {digitalWrite(ledpins[7] ,LOW);}
if (Randomnumber & 4==4) {digitalWrite(ledpins[8] ,HIGH);} else {digitalWrite(ledpins[8] ,LOW);}
if (Randomnumber & 8==8) {digitalWrite(ledpins[9] ,HIGH);} else {digitalWrite(ledpins[9] ,LOW);}
if (Randomnumber & 16==16) {digitalWrite(ledpins[10] ,HIGH);} else {digitalWrite(ledpins[10] ,LOW);}
if (Randomnumber & 32==32) {digitalWrite(ledpins[11] ,HIGH);} else {digitalWrite(ledpins[11] ,LOW);}
delay(1000);
}

}
steveastrouk4 years ago
Yes.
slowguy (author)  steveastrouk4 years ago
Hi steve,
Could you write me a program to run 2, 3, 4, 5, 6, 7 in a sequence and 8, 9, 10, 11, 12, 13 as random. I am making a xmas gift for my wife and I have limit time. I would very much appreciate it as I have to construct the object the lights are going in.
Thanks,
John
4 years ago
What sequence ? Random I can handle. I'll take a look at it, but I am very busy at work at the moment.
slowguy (author)  steveastrouk4 years ago
a sequence of flash 2 then 3 then 4 then 5 then 6 then 7 and 6 and 5 and 4 and 3 and 2 and then repeat.
Thanks
4 years ago
10000
01000
00100
00010
00001
00010
00100
01000
10000
??
slowguy (author)  steveastrouk4 years ago
that is correct, then repeat
4 years ago
What kind of speed are you looking for ?
One change a second ? Or what ?
Steve
slowguy (author)  steveastrouk4 years ago
yes, that will be good.
4 years ago
Is this all it needs to do ?
slowguy (author)  steveastrouk4 years ago
yes, while 6 leds, 8 through 11 outputs blink randomly, the other 6 leds , 2 though 7 outputs blink in sequence, 2 through 7, then 7 through 2 and repeat continuiously.
Thanks
4 years ago
Which Arduino version ?
slowguy (author)  steveastrouk4 years ago
Nano, V3
frollard4 years ago
Since at a beginner level you cannot have multiple processes or timers to increment your random values, you need something a bit more complex to do 'independent' actions. There are a couple methods for this,
You need to use ARRAYS -- learn them. An array is a series of variables that share a name, and each individual element can be addressed with an index number.
for example
int leds[6] = {3,4,5,6,7,8};

This will declare an array of integers called leds, with 6 elements, and their initial values will be 3, 4, 5, 6, 7, 8. Those values can be any integers. These would make good pin numbers (with leds attached)

Later, if I use the variable
leds[x] in a function, it will pull the VALUE of that number, the indexes start counting at zero.
i.e.
leds[3] == 6.
If they update at the same time, its easy, you just loop through your leds with something like
(pseudocode explaining thought process)
for i = 0, 0 <7, i++
turn all leds off;
IncrementalLed[i] = on //list of leds in order
RandomLed[random(0,5)] = on //list of leds that don't matter what order
delay(100)
end for i