Does anyone know how to make a homemade mechanism for a rotisserie that would turn a 125 pound hog?
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Answer it!
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Thanks so much for that idea.
Ok it took awhile but check out this youtube link this is what i cme up with
just did a test with it today , I think it will work just fine over my fire pit
Shows his home made hog roasting set up..\
Hope it helps you.
I understand this doesn't answer your question directly, but thinking outside the box sometimes is a good thing!
We regularly do a couple of sheep in our 'Mandela Microwave'. Regardless of how many we put in (up to 3) they all cook in about 3 hours!
We have taken an old 'leakey' 2000 liter overhead fuel storage tank and cut it in half along it's 'length'. Then at one flat end we made a couple of hinges outta pieces of pipe so that it can be opened and shut. like a drum barbecue. A couple of bits of pipe welded in place serve as feet to stop it from rolling.
But in essence, we 'spatchcock' the sheep and tie it onto a flat frame and then just by turning it over like a piece of steak on a regular barbie, the meat cooks in quick time.
The fire is made outside of the unit and the hot coals fed into the bottom with a shovel as needed. The lid is kept closed whilst cooking and it forms a sort of oven effect which speeds things up!
Just a thought for you!
BTW, the actual number for this torque will probably never be greater than the weight of the hog times one half its width. e.g. 120 lb * 0.5 ft = 60 ft*lb That's sort of the worst case, the most unbalanced you could get with the hog still touching the spit.
So you need torque. How do you get torque? Answer: mechanical advantage, something "geared down". a lot. The goal is to trade speed for torque, and the actual speed at which the spit will rotate will be very slow, ~ 1 rpm.
My intuition says to go with bicycle gears and chain, and then drive that with an old power-car-window actuator.
I'm glad you know how to weld, as I was imagining this whole thing made out of steel.
Regarding the question of how fast it should go, recall that power is torque times angular speed. P = τ * ω Convert the English units to metric first. Convert ft*lb to N*m and convert RPM to rad/s
1* ft*lb = 0.3048 m * 4.4545 N = 1.358 N*m
1 rev/minute = 2*pi/60s = (pi/30) rad/s = 0.1047 rad/s
The product of N*m and rad/s is power in Watts.
For the hypothetical example of 60 ft*lb * 1 RPM get
60 * 1 * 1.358 * 0.1047 = 8.5 W
And I think ~10 W is a good ballpark estimate of how much power you can get from your drill motor. So I think my earlier guestimate of 1 RPM for the angular speed of the spit is still a good goal to work towards.
I imagine gearing down the output from the drill with bicycle gears, and I have drawn a crude picture of this. I drew two gear sets, but you might be able to get away with one... or three... dunno that's for you to figure out.
It seems you need a lot of power to turn the spit. You would have to gear it up or use a belt drive with pulleys. Hook it up to an exercise bike. Good luck.
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