# Given the derivative of a function, how would you find the original function?

^{(n-1)}) to guess that the original function was x

^{2}, but what would you do if you were told that x

^{2}itself was the derivative of another function? Please help me. Note that I am NOT someone asking for homework help, my homework from school is not calculus.

The integral of (x

^{n})= (x^{n+1})/(n+1))So in the case of x

^{2}. You would have, (x^{2+1})/(2+1) which is (x^{3})/3 + C. I added a (C) because C is any integer, and when the derivative is taken of an integer, it would = 0. So then when you check, the derivative of (x^{3})/3 , it would equal x^{2}.This concept does get more challenging, when you have definite integrals, radicals, or when you need to integrate through substitution.