How can I use a 9volt charger on a 3.6 battery 700 mA?

So Im doing this project where I have a 9 volt charger and I need to charge a 3.6 volt 700 ma battery. How would i go about charging this battery? I tried to use one resistor but it got extremely hot, hot enough to melt plastic. 

That's a lithium battery. Build a lithium battery charger, and be careful. You may have been lucky not to explode the battery.

Steve
jnajmy (author)  steveastrouk4 years ago
What size regulator would I need to use to bring the voltage down from 9 volts to 3.6 volts at 600 mA?
This is the battery I want to use:
http://www.amazon.com/gp/product/B003LMOVQS/ref=ox_sc_sfl_image_7?ie=UTF8&psc=1&smid=A2220UWPX1VUDX

Can I use this to charge the battery?:
http://www.amazon.com/gp/product/B0030862XI/ref=ox_sc_sfl_image_4?ie=UTF8&psc=1&smid=AM0TJKCE8MD21

If not can anyone help me figure out whats the best way to charge that battery?

thanks for the help!!
It;s best that you don't try to use that charger on any battery other than what it was designed to charge. Find the correct charger and use that.

BTW, a resistor alone isn't going to bring the voltage down. A resistor will restrict current flow. You need to use a voltage regulator in order to bring voltage down. Yes a pair of resistors set up as a voltage divider will reduce both voltage and current but it's best to use a regulator.
V=IR, of course it will bring the voltage down. That said, a regulator at the very very minimum is needed here.