orksecurity4 years ago
Actually, if you don't want to calculate this yourself, websearch "anamorphic". It's a well-known transformation.
orksecurity4 years ago
That's a geometric-projection problem -- ray tracing, essentially. You should be able to work this out by drawing a vector from the viewer's position to a point on the cylinder and figuring out where that will reflect to on the disk; the two angles relative to the normal at that point are equal and opposite. You can get an approximation by trying a number of points, or you can plug in variables and derive a formula.

I don't see how to make this into a 3D display, but that may just be because I'm missing something.
TheTechGuy99 (author)  orksecurity4 years ago
um I haven't reached calculus yet so I don't understand any of that

also I plan to have a clear cylinder that will let you see the other side

as for the specifics this is just a concept and I probably wont build this until I get older
It isn't calculus, just geometry. (Which I think I got in 10th grade, but different schools cover it at different times and to different depth.)
Re-design4 years ago
Trial and error.