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active| newest | oldest^{2}= 10x solves for the non-zero solution x=1.25.8x

^{2}+ 2x = 12x8x

^{2}^{ }= 10x8x * x= 10 * x (This step isn't necessarily, it's just illustrating the previous step)

8x = 10

x = 5/4, or 1.25

I never claimed algebra was my strong suit. It's been awhile since I used this stuff.

Sorry for the inconvenience.

http://www.graphcalc.com/what_is_graphcalc.shtml

http://en.wikipedia.org/wiki/GraphCalc

Looks interesting. Thanks for the reply.

^{2 + 2x - 12x = 0<br /> 8x}2 -10x = 0<br /> x(8x - 10) = 0<br /> <br /> x = 0<br /> <br /> 8x-10 = 0<br /> x = 10/8 = 1.25<br /> <br /> <strong>x = 0, 1.25</strong><br /> <br /> Check the solutions:<br /> <br /> 8(0)^{2 + 2(0) = 12(0)<br /> <strong>0 = 0 </strong><br /> <br /> 8(1.25)}2 + 2(1.25) = 12(1.25)<br /> 12.5 + 2.5 = 15<br /> <strong>15 = 15</strong><br /> <br /> For a graphical solution, graph the parabola 8x^{2 + 2x and the line 12x, their intersections are the solutions to the problem. <br /> <br /> The degree of the equation -- the largest power of x -- states the number of zeros the equation will have. If the largest power of x is 2, then there are two solutions to the equation.}Incidentally, this editor requires a caret before

andafter the superscript text...temporaryhold-over from the old text-based markup system, and will disappear soon, once the I'bles servers have completed running through and converting all of the old comments in the database to the new format.At that point, the "extended markup" (sub- and superscript, big and small text, etc.) will be available only to paid account. A group of us users are advocating with Eric to change that policy (so that pre-existing markup is available to all users), but no decision has been made yet.

some polynomial in x= 0Like this: 8x

^{2}-10x +0 =0Now factor it:

8x

^{2}-10x +0 =08x(x -10/8) =0

x(x-5/4) =0

And you can see the answer, x=0 or x=5/4, from inspection.

Check your work using Octave or Matlab. Write the poly as a vector of its coefficients, then feet that to the

roots()function.feedthat, not feet that.XD

Well done logangina for even attempting it!

^{2 + 2x =12x<br /> 8x times 8x+2x =12x<br /> 64x+2x=12x<br /> 66x=12x<br /> which makes no sense<br /> <br /> i believe you need a number that is not an "x" number to solve this<br />}