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if you use a resister to lower the voltage out of the capacitor will it have a higher f or amp hour?
There are many theoretically oriented people who want to be more exact than necessary. The person asking wants simply to replace the battery with charged capacitor. The answer is:
so: if you have 1,2V battery with 0,27mAh capacity, than you can replace it with the capacitor of 1F charged to let's say 2V. Your circuit should cope with it. After consuming 0,27mAh from the capacitor it will get discharged down to 1V which should be also ok for your circuit.
* check the minimum and maximum voltage for your circuit. Take the difference between those two,
* multiply it by 0,2777 per each needed mAh
and you will get needed capacity in F.
And remember to start with fully charged capacitor up to the maximum possible voltage.
sorry one correction:
*check the minimum and maximum voltage, take the difference
* divde 0,277 (not multiply) by the min/max voltage difference
you will get number of F.
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Posted:Mar 18, 2011
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