Power Electronics: power converter
My lecturer gave us the solutions and a few steps between beginning and end to get to the solution so we could work it out. However, as you can see the picture below I got 30.6A whereas she wrote 54.2 down.
The problem is to "Find the maximum values of the average" (done this bit) "and rms thyristor currents for any firing angle, alpha.". The values of R and Vs are in the diagram. Alpha is assumed to be 0 since then the thyristors will conduct for the greatest possible length of time.
I think she may have got to the end then forgotten to square root of Pi before multiplying Vm/2PiR by it. Does anyone agree?
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steveastrouk
says:
Jun 4, 2010. 6:55 AMReply
Jayefuu (author)
in reply to Jun 4, 2010. 7:00 AMReply
steveastrouk
in reply to Jun 4, 2010. 7:08 AMReply
Jayefuu (author)
in reply to Jun 4, 2010. 8:33 AMReply
kelseymh
says:
Jun 4, 2010. 10:03 AMReply
steveastrouk
in reply to Jun 5, 2010. 7:41 AMReply
kelseymh
in reply to Jun 5, 2010. 1:08 PMReply
steveastrouk
in reply to Jun 5, 2010. 2:07 PMReply
Jayefuu (author)
in reply to Jun 4, 2010. 10:56 AMReply
Jayefuu (author)
says:
Jun 4, 2010. 6:47 AMReply
kelseymh
in reply to Jun 4, 2010. 2:35 PMReply
kelseymh
in reply to Jun 4, 2010. 11:10 AMReply
















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