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What is the square root of -2?

 I need to prove my math teacher wrong

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Burf7 years ago
Square root (-2) = 1.41421356 i
Why is your math teacher wrong by the way ?
bendog38 (author)  steveastrouk7 years ago
 Most of us 9th graders at North Canyon HS are right about math questions and like to make argue over just about everything.
as a freshman you should be quite and try to listen to your math teacher. believe it or not he (or she) is pretty smart, probably smarter than you. show some respect, teachers are underpaid, under appreciated, and esential to society.

P.S. sorry about the mini rant
sorry I meant quiet not quite
bendog38 (author)  adam 1017 years ago
 Dude, mini-rant's fine, but you have good advice.
jeff-o bendog387 years ago
Ha, we did that in school as a stall tactic.

In retrospect, it was a stupid thing to do, and I wish we'd learned more math.
Yes, you have no understanding of complex numbers just because you can say j root (2).

If you really want to "be right", learn some more math, instead of parroting things you've picked up on internet forums. Sure as hell, if you tried it on with me in a maths class, I would ask you for a detailed explanation of your analysis.

Steve
gmoon7 years ago
You cannot do it with "real" numbers. No "real" number times itself can ever be negative, only positive.

You need to use complex or imaginary number sets to take a - SqrRt .
adam 101 gmoon7 years ago
however, keep in mind that even though they are imaginary they do exist. they are just as real as "real numbers"
gmoon adam 1017 years ago
Well, they are just a conceptual as "real" numbers... All numbers are a "construct."
the_mad_man7 years ago
 the square root of any negative number is always going to be i. this is because there is no number which you can square to get a negative number, it will always be positive.
No. i is specifically square root of -1. Square root of -2 is the square root of 2 times the square root of -1. Burf has the right answer.
lemonie7 years ago
You need to invoke i.
-2 = -1 x 2
so (root) -2 = (root) (-1 x 2),
which is (root) 2i (i being (root) -1

L
j root (2)