Or better yet what would be the formula when the angle of incline, cart weight and hanging weight vary?

Removing an alternator Pulley!

by
Mjtrinihobby

How to Change the Speed of a Drill Press

by
newdetroiter

Replacing the engine Water Pump and Tensioner Pulley (Honda Civic D15B).

by
Mjtrinihobby

Transmission Belt / Fan Replacement Cub Cadet LTX1045

by
brakeman22

Calculate Drill or Lathe Speed

by
djpolymath

How to replace a power steering pump

by
marksatterfield

Turn off your light switch from bed with pulleys.

by
icerc

THE INTERNET'S CHEAPEST MOTORIZED, BELT DRIVEN, 48" DIY CAMERA SLIDER

by
stereoghost

Let your inbox help you discover our best projects, classes, and contests. Instructables will help you learn how to make anything!

active| newest | oldestThen the hanging block would rise ΔL vertically, and the rolling block would move upward by (sin(21.8 deg))*ΔL.

So the work it takes to make these blocks move upward against their own weight is :

W = (50 lb)*ΔL + (165 lb)*(sin(21.8 deg))*ΔL

Next I am going to naively assume none of your rope-pulling work is lost to friction, so that:

W = F*ΔL = (50 lb)*ΔL + (165 lb)*(sin(21.8 deg))*ΔL

where F is the force with which you pull on the rope, and with which the rope pulls on you, at that place in the diagram labeled, "?? lbs to pull".

Divide both sides by ΔL, and get :

F = (50 lb) + (165 lb)*(sin(21.8 deg)) = 111.28 lb

Fp = W h/l

= W sin α

where:

Fp = pulling force (N, lbf)

W = m g = weight of body (N, lbf)

h = elevation (m, ft)

l = length (m, ft)

α = elevation angle (degrees)

m = mass of body (kg, slugs)

g = acceleration of gravity = 9.81 (m/s2) = 32.174 (ft/s2)