What resistor(s) would I use for this LED?
Thanks!
5
answers
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Answer it!
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Each didoe acts to drop the voltage in subsequent devices...
The datasheet specifies a nominal Vf of 3V...worst case 2.8
for three of the UV LEDs in series at a source voltage of 9VDC, and presuming worst case,
the drop voltage for the resistor is 9-(2.8*3 ) = 0.6V
Assuming IAF of 30mA, the resistance required is
R = V/R = .6/.03 = 20ohms
I'd just toss 100 ohms on it and be done.
<-------------------------9V------------------------>
<---Vr---><---Vd---><---Vd---><---Vd------>
---\/\/\/\/\---------|>------------|>----------|>--------
Frankly, I'm not even sure you need a resistor...
The graph on page two of the datasheet says it all...
see:
http://www.vcclite.com/Customized/Uploads/SpecSheets/VAOL-5GUV0T4.pdf
current thru one of these LEDs is 5mA @ 3V and 30mA @ 3.6V
Since you have three LEDs and a 9V source, I don't think you can pull enough current to exceed max specs, even without a limiting resistor.
(and assuming LED current of 20mA per leg)
you'll need (9-3.5)/0.02 = 275 ohm per leg
now, while I'm still thinking about this, if you want to maximize the output intensity for each, I'd be inclined to run them in parallel from a fixed voltage source like an adjustable voltage regulator
(see http://datasheets.maxim-ic.com/en/ds/MAX603-MAX604.pdf)
set it for 3.3 V out and you're done..8-pin dip, requires a couple caps and that's about it.
It will calculate everything for you, and even spit out a diagram to hook everything up.
It will solve everything for you. Understanding why leds need resistors is also quite important...
http://led.linear1.org/why-do-i-need-a-resistor-with-an-led/
Explanation:
Generally, you want to try to get close to 20mA of current for leds and the data sheet for this one seems to indicate the same. According to Ohm's Law R=V/I so 9/.020 = 450 ohms of total resistance. Now, thats for one and optimal operating conditions. Its not important to be too exact, but just get close and the circuit will work without shorting out the leds too fast.
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