how to make a dsi porable charger??

hi there i want to make portable charger to charge my dsi

i first thing of using 4aa rechargable batterys but those batterys put out 5.3volts and my dsi only need 4.6volt so if anyone knows please help me!!!

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Andrew_48 (author) 4 years ago
will this work???
nope, it will die, then explode, causing it to die again because the explosion brought it to life for a second, then itle unexplode, and die , comeback to life, then die form cancer, then a necromancer is spain will revive it again, then the necromancy dsi will kill you because its what they do, then itle die because thats what necromancies do when fulfill their ambitions!

it needs to go through a balancing charger , or else it will damage the lithium ion battery . duh.
ill post up a crude schematic tommorrow which would work
Andrew_48 (author)  jpoopdog4 years ago
ok i will wait!
in this crude diagram, you connect the 4 AAA batteries together, or at least start out with AAA, as they generate less current. If all goes fine, then use 4x AA.

also, im not exactly sure if that resistor 4.9 ohms will work.
a resistance calculator told me that it would take a 4.9 ohm resistor to lower 6v to 4.9v at 1000ma.
and quite frankly i dont trust it.

but essentially it will work as set out, just dont have the batteries connected with the switch while it is plugged in.
Andrew_48 (author)  jpoopdog4 years ago
yes but the 4aaa rechargable batterys together put out 5.3v

and also what is the "balancer" in the diagram?
i just realised that i was once able to charge my old ds lite using a 4 AA pack when my charge broke back when i was 12 and i couldnt find my second one (i had a second one from a friend who sold their ds).
anyways, it charged up fine, and i kept doing that for about 3 weeks, and i was a heavy ds player, so i charged it up about 20 or so times, and the battery was fine.

just in case, try and use a resistor that will restrict the voltage from going beyond 5v, but just in case.

lastly, where your dsi says it takes 4.6v, it means the battery. all batteries require a voltage higher than itself to charge. in thye case of a 1.5 nimh battery, i can get away with using 3.2v and it is stil fine. with lithium ions as in the ds, that threashhold is smaller due to their low internal resistance.
meaning that 5.3v is fine, just dont get the polarity wrong
Andrew_48 (author)  jpoopdog4 years ago
oh and thats mean that my diagram is right?
if the balacner is inside the dsi, then yes, otherwise it will destroy the battery.
the balancer is a regulator.

mine is how it could be set up so that you dont need to destroy a dsi charger to get the plug.

all the same

by blocking diode i asume you mean a resistor right?
Andrew_48 (author)  jpoopdog4 years ago
blocking diode i mean

with this the power goes only from one way (batterys----->dsi ) and protect the device from reverce power (dsi----->batterys)

oh and also some diodes drops down the voltage for about 0.4v
Andrew_48 (author)  jpoopdog4 years ago
Andrew_48 (author)  jpoopdog4 years ago
most likely yes, i have charged my dsi on my laptop many a time, so i know it works.

keep in mind a usb port gives out +5v

the resistor in the diagram is there to keep down the voltage, cutting it from 6v to 4.9v, which is more suitable.

the balancer, is just a chip that controls the electricity going into the ds. ever wonderd why it is that the charger eventually turns off?, its because the balancer detects that there is now enough current comming from the ds to indicate that it is fully charged, however, considering that ds usb cables have no such things on them, i think that the balancer might be inside the dsi.
also i just checked my ds charger, it says it pumps out 5.2v, which says to me that the batteries you tested before would have been fine
jpoopdog4 years ago
simple answer to simple question

you will need a dsi charger , which you can afford to lose.

locate the dc output on the transformer cable, and using a multimeter, get its voltage. this is the voltage that the balancing charger circuit inside the charger uses.
if your a bit confused as to how it all works, heres how it goes

AC socket --> charger (240/120v in --> transformer--> 4.6v@1000ma--> charging circuit/regulator ) --> controlled charging current--> DSi

Ac socket --> charger --> dsi

you need to replace the voltage out, of the transformer, with a portable power supply of equal value, e.g. a battery .

keep in mind that voltage is always higher than the charger specifies. if it says it makes 4.6v , then it most definately will be making +5v.
now, using 4xAAA to begin with, use these on the +/- correspondingly, on the +/- of the transformer output, essentially doing what the transformer does when tis plugged in, which is making an output.

you have to do this right where the transformer is linked to the balancing charger that regulates the power, if it isnt in the charger, meaning its in the ds,
but if it is in the charger, put the batteries behind it, between the transformer and the balancer, or else youll damage the dsi's battery.

if youre careful, you may be able to have both the batteries and the transformer connected (be sure to seperate one while the other is in use or one will damage the other, preferable with a dpd switch).

meaning that you can charge your dsi by either putting batteries into the battery clip, or by plugging in the charger.

never plug it in while batteries are in or they will get charged with more current than they can handle (if they are rechargeable), and they will die

ill post a crude schematic later
cengel14 years ago
It appears you are trying to make the charger being sold at eBay here: http://cgi.ebay.com/Nintendo-DSi-XL-AA-Battery-Pack-/320654169213?pt=LH_DefaultDomain_0&hash=item4aa87a547d

This is a 4-battery pack, but the battery compartment has extra space in it, suggesting that there's some circuitry in there that may be changing the voltage. I don't know much about designing circuits, but it seems to me that a knowledgeable person could use the specs of the AC charger's output (4.6vDC, 900mA) to design a circuit to convert 4 AC batteries' output to match.

I need this precise sort of solution as well, but I don't want to pay $25 for it.
orksecurity4 years ago
Are you measuring those batteries open-circuit or under load?

4.6 volts would be pretty close to 4.5 volts, or three fully-charged Lithium AA's -- though their voltage drops over time. You might want to just try three batteries and see if that will work for you.

Otherwise, you're looking at using a regulator circuit (see the many power-supply-related Instructables; there's probably something there you can swipe fairly easily).

Unless you want to gamble that the DSI will tolerate the higher voltage. It might, or it might not, depending on what the designers decided to do.