Instructables

solid state relay information

Do I need to apply voltage to pin 5 for it to switch on chip Vishay VO14642AABTR?

http://www.alldatasheet.com/datasheet-pdf/pdf/443188/VISHAY/VO14642AABTR.html

No, to switch the device, turn on the LED on pin 1 and 2.
Its just like any LED, it needs a current limiting resistor.

Pin 5 is an OUTPUT !
jbaker22 (author)  steveastrouk1 year ago
What is pin 4 then?
Part of the output circuit. The datasheet clearly shows how it should be wired.
jbaker22 (author)  steveastrouk1 year ago
So, I would not need it for DC purposes?
Look at the circuits that Iceng posted !!! Pin 4 IS used as part of the output in DC cases. Its linked to pin 6.
jbaker22 (author)  steveastrouk1 year ago
Hope it will work out like this. https://www.circuitlab.com/circuit/99eua9/rc/
You have the battery in the wrong way round for the device. Pin 6 should be connected to the positive supply. Pin 4 should connect to pin 6, and pin 5 to the motor, and the motor to the battery -ve terminal.
jbaker22 (author)  steveastrouk1 year ago
Thanks, I swapped it around and saved what I think you meant.
https://www.circuitlab.com/circuit/99eua9/rc/
CONNECT PIN 4 to PIN 6
jbaker22 (author)  steveastrouk1 year ago
Okay
https://www.circuitlab.com/circuit/99eua9/rc/
You got it
WHOA. Add a nice big diode across the motor ! Put the band end aWAY from the battery.
iceng1 year ago
You need to understand MOSFETS have Intrinsic Parallel Diodes

See my picture.

A
SSRFET1.png
iceng iceng1 year ago
But even though they are as fast as the MOSFET,  I would put a pair
of 1N4006 in parallel in the AC/DC configuration which is half the
current of the plain DC configuration where both fets are in parallel.

A
Link doesn't work. Post the device number.
jbaker22 (author)  steveastrouk1 year ago
I just edited it, sorry.