ANSWERS : Technology

Do I need to apply voltage to pin 5 for it to switch on chip Vishay VO14642AABTR?

http://www.alldatasheet.com/datasheet-pdf/pdf/443188/VISHAY/VO14642AABTR.html

Comments

[steveastrouk]

No, to switch the device, turn on the LED on pin 1 and 2.
Its just like any LED, it needs a current limiting resistor.

Pin 5 is an OUTPUT !

[jbaker22]

What is pin 4 then?

[steveastrouk]

Part of the output circuit. The datasheet clearly shows how it should be wired.

[jbaker22]

So, I would not need it for DC purposes?

[steveastrouk]

Look at the circuits that Iceng posted !!! Pin 4 IS used as part of the output in DC cases. Its linked to pin 6.

[jbaker22]

Hope it will work out like this. https://www.circuitlab.com/circuit/99eua9/rc/

[steveastrouk]

You have the battery in the wrong way round for the device. Pin 6 should be connected to the positive supply. Pin 4 should connect to pin 6, and pin 5 to the motor, and the motor to the battery -ve terminal.

[jbaker22]

Thanks, I swapped it around and saved what I think you meant.
https://www.circuitlab.com/circuit/99eua9/rc/

[steveastrouk]

CONNECT PIN 4 to PIN 6

[jbaker22]

Okay
https://www.circuitlab.com/circuit/99eua9/rc/

[steveastrouk]

You got it

[steveastrouk]

WHOA. Add a nice big diode across the motor ! Put the band end aWAY from the battery.

[iceng]

You need to understand MOSFETS have Intrinsic Parallel Diodes

See my picture.

A

[iceng]

But even though they are as fast as the MOSFET,  I would put a pair
of 1N4006 in parallel in the AC/DC configuration which is half the
current of the plain DC configuration where both fets are in parallel.

A

[steveastrouk]

Link doesn't work. Post the device number.

[jbaker22]

I just edited it, sorry.