solid state relay information

Do I need to apply voltage to pin 5 for it to switch on chip Vishay VO14642AABTR?

No, to switch the device, turn on the LED on pin 1 and 2.
Its just like any LED, it needs a current limiting resistor.

Pin 5 is an OUTPUT !
jbaker22 (author)  steveastrouk1 year ago
What is pin 4 then?
Part of the output circuit. The datasheet clearly shows how it should be wired.
jbaker22 (author)  steveastrouk1 year ago
So, I would not need it for DC purposes?
Look at the circuits that Iceng posted !!! Pin 4 IS used as part of the output in DC cases. Its linked to pin 6.
jbaker22 (author)  steveastrouk1 year ago
Hope it will work out like this.
You have the battery in the wrong way round for the device. Pin 6 should be connected to the positive supply. Pin 4 should connect to pin 6, and pin 5 to the motor, and the motor to the battery -ve terminal.
jbaker22 (author)  steveastrouk1 year ago
Thanks, I swapped it around and saved what I think you meant.
jbaker22 (author)  steveastrouk1 year ago
You got it
WHOA. Add a nice big diode across the motor ! Put the band end aWAY from the battery.
iceng1 year ago
You need to understand MOSFETS have Intrinsic Parallel Diodes

See my picture.

iceng iceng1 year ago
But even though they are as fast as the MOSFET,  I would put a pair
of 1N4006 in parallel in the AC/DC configuration which is half the
current of the plain DC configuration where both fets are in parallel.

Link doesn't work. Post the device number.
jbaker22 (author)  steveastrouk1 year ago
I just edited it, sorry.