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Really basic Resistance / Amperage question:

before I begin: yes, I should know this already, but I'm really sleep deprived right now, and therefore slightly muzzy on my electronics knowledge... My circuit has two loops running in parallel off one, limited, 18v power supply: [*] Loop 1 requires the majority of the supply's power to run [*] Loop 2 is simply a 7805 voltage regulator supplying 5v to an analog input on an Arduino, so needs almost no current running through it. [*] when Loop 1 and Loop 2 are both active, Loop 1 does not get enough power. if I place a resistor in Loop 2, in series with the 7805, will it increase the amperage to Loop 1? I think the answer is yes, but, once again, I'm MASSIVELY sleep deprived. any help is appreciated.

7 comments
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Nov 4, 2008. 2:33 PMpyper says:
I'm guessing your using 9v batteries, in which case your supply impedance (internal resistance of the battery) is probably quite high and that's what's causing your trouble. Try buying better batteries, or switching to rechargeable (Ni-MH) 9v batteries.
Nov 2, 2008. 9:02 PMgmoon says:
Try running the 7805 off the "center tap" of the two batteries (i.e., off of 9V.) The higher the voltage you supply to a 7805, the more current is wasted in the regulation process. Or try a decent switching regulator in place of the 7805 (or double your batteries, as NM suggested.)
Nov 2, 2008. 8:22 PMNachoMahma says:
. It will reduce the current in Loop 2, which should allow more to go through Loop 1 (assuming you're overloading the PS). Just make sure you don't drop so much voltage across the R that the 7805 isn't getting enough V (calc using L2 I, not total I). . Probably help to reduce I in 5V sensing line (if it's a switch closure, R can be usually pretty high)
Nov 2, 2008. 8:52 PMNachoMahma says:
. I'd try four 9Vs (2x2). If the voltage still drops too far, you're probably SOL.
.
. No idea how to size R for L2 w/o knowing current. Yeah, "guess and check." I'd start at 10K, but that's probably too high. A volt meter on 7805in should tell you a lot.
Nov 2, 2008. 8:55 PMNachoMahma says:
. Just noticed that the uC input is analog. Probably can't do much with that, but I'm no expert.

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