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. It's been a lonnnggg time ago for me, but I think the "something slightly interesting" will be the LED getting brighter as the cap charges. . R is just for limiting current thru the LED and cap.
Jun 6, 2007. 8:24 AMschorhr
says:
http://falstad.com/circuit/
The java circuit simulator will open.
File - import
Now watch out, after the switch closed and re-opened the first time, the result will be different, since the LED will not allow the capacitor to completely discharge; Diods allways need a certain voltage to conduct, and so the capacitor cant discharge completely.
The java circuit simulator will open.
File - import
$ 1 5.0E-6 10.391409633455755 50 5.0 50162 272 144 368 144 0 1.0 0.0 0.0w 272 144 272 192 0w 368 144 368 192 0w 272 192 192 192 0r 192 192 192 304 0 100.0w 192 304 272 304 0v 368 304 272 304 0 0 40.0 5.0 0.0c 272 192 368 192 0 5.549999999999999E-4 1.9011007901132215w 368 192 432 192 0w 432 192 432 304 0s 432 304 368 304 0 true false
Now watch out, after the switch closed and re-opened the first time, the result will be different, since the LED will not allow the capacitor to completely discharge; Diods allways need a certain voltage to conduct, and so the capacitor cant discharge completely.
Jun 6, 2007. 12:25 AMVIRON
says:
It depends on the values but assuming they are reasonable, the "result" will be the LED lighting up. BUT, something slightly interesting will happen first. Try a 4700 uF cap and a 470 ohm resistor and 9 or 12 volts.
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