continuous shocker without capactior

i need help. i want to make a shocker without the capacitor. on the camera circuit board. do i just touch the two + and - sign where the capacitors ar charged?? i tried and it didnt work. i know plasma has one but it tried and i cant get those damn parts soldered. is it possible to do this> i have been shocked before doing this, but i dont remember how i did it.

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Plasmana8 years ago
I have an idea, but it still requires a capacitor... What you can do is desolder the electrolytic capacitor and the little yellow capacitor from the camera's board. Then solder in the yellow capacitor where the electrolytic capacitor was. When you turn it on, the yellow capacitor should charge up less than a second and can make a unpleasant shock.
guyfrom7up8 years ago
did you get shocked direct from the transformer, or from an electrolytic cqpacitor. One time I got shocked by a photoflash, it hurt pretty badly and my arm was cramping up for like 10 seconds Not fun...
NachoMahma8 years ago
. Sorry
you kinda got it right. in a car,the ignition coil operates off of 12 volts. Unlike normal transformers an ignition coil is 1 piece of wire. the "primary" is fatter, and branching off of it is a hair thin (I hate it when people say hair thin for wire, I use 38 gauge wire and it's not so bad) "secondary. When you apply 12 volts to the "primary" it creates a magnetic field. When you take away the power the magnetic field collapses really really fast on the secondary, and since it has like 2000 times more turns it produces something like 20,000 volts
. It's still two coils. They just share a connection point on one end. See this
NachoMahma8 years ago
. Maybe a little theory will help you out. This is from what I know of automotive ignitions, but the it's the same principle. . At it's simplest, all you need is a switch and a transformer. . When you close the switch, you apply power to the primary winding. This generates a magnetic field that interacts with the secondary winding and produces an EMF. Once the field builds to it's maximum, no EMF is produced (the field has to change to do any work; a steady field does nothing). When you open the switch, the magnetic field collapses and once again produces an EMF in the secondary. . For reasons I don't understand, the magnetic field collapses much faster than it expands, so you get a bigger "kick" when the switch opens. . In a car, the capacitor (often called a condensor) acts somewhat like a clamping diode, in that it absorbs excess counter-EMF to prevent burning out the points (switch). Not sure what the cap does in your circuit.
guyfrom7up8 years ago
the cap goes from the anode of the diode and the +1.5 volt
guyfrom7up8 years ago
everything the same without the capacitor lol
guyfrom7up8 years ago
well, without the capacitor you get pulsed dc, I guess it should still work, I dunno.
guyfrom7up8 years ago
do you want a buzzer shocker type of thing, or do you want an arc?