OK , Hi all ..
This my First Project in Instructables ^_^
I am from Indonesia , Here was held 26th SEA Games 2011... GO Indonesia !!!
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Ok check this out ,
This is 10 watt amplifier and LoudSpeaker,
Let me tell you how I make this thing
Part List :
# acrylic
# Loudspeaker
# PCB
# Some Wire
# 9Volt battery Connection
# Unbalance Jack Female
# Power Jack Female
# Potensiometer
# Capacitor ( 2.2uF ; 470uF ; 100uF ; 0.1uF ; 1000uF )
# Resistor ( 220R ; 2.2R ; 1R )
# IC Tda2003
# Heatsink
This my First Project in Instructables ^_^
I am from Indonesia , Here was held 26th SEA Games 2011... GO Indonesia !!!
=============================================================
Ok check this out ,
This is 10 watt amplifier and LoudSpeaker,
Let me tell you how I make this thing
Part List :
# acrylic
# Loudspeaker
# PCB
# Some Wire
# 9Volt battery Connection
# Unbalance Jack Female
# Power Jack Female
# Potensiometer
# Capacitor ( 2.2uF ; 470uF ; 100uF ; 0.1uF ; 1000uF )
# Resistor ( 220R ; 2.2R ; 1R )
# IC Tda2003
# Heatsink
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Signing UpStep 1: Build Loudspeaker Box
Tools I use :
# Saw
# Drill machine
# Melting Glue
I think the result is not bad ,
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...
...
Ok its bad but not really , LOL
# Saw
# Drill machine
# Melting Glue
I think the result is not bad ,
...
...
...
Ok its bad but not really , LOL
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Please check this
Also i seem to have a problem with huge distortions on low volumes. Could it be because of the potentiometer being 10kohm?
can someone help me i built it but the output was distorted not too much but it was enough to annoy some one (when the output is at max volume) at lower volume its fine enough.
CONVERSELY
and when i short the capacitor C2(1000uF) the output gets stable and distortion is reduced (at max volume) but gets distorted at lower volume .
strange but true
anyone who has built it can try himself and what is the solution for low distortion at max and min volume simultaneously.
http://www.ziddu.com/download/17590310/10wattamplifier.rar.html
thx for your comment,
here is the design and layout I use
http://www.ziddu.com/download/17590310/10wattamplifier.rar.html
But , Power Amplifier is fixed at 10 Watt so Power Speaker should not be more than 10 Watt
Battery power > Amp power < Speaker power
Like that. Because it doesn't matter whether the battery power is higher than the speaker's rating, it's effectively regulated by the amp.
The battery power needs to be higher than the amp power, otherwise you won't get the full 10W. Also, if the amp were fixed at 10W it would be putting out a constant DC current. That doesn't happen. 10W is the maximum rated power you can put through it before you break it.
I think you are right at "10W is the maximum rated power you can put through it before you break it"...thanks
for battery power, Tda2003 have max Voltage Suplay at 18volt and each IC having different max voltage , u can see it at datasheet...
But I have question, how amplifier can amplify something bigger than itself ???
Thank you for your comment ^_^
The amplifier is amplifying the input signal, not the power from the battery, that'd be impossible. The simplest way of looking at it is that it's a switch, and the trigger is the signal. It's switching the battery power on and off which is used as an output.
And they're not necessarily amplifiers, you can make signals smaller with them too, or keep them the same size. Any signal can go in, within reason.
The following doesn't take into account the maximum ratings of any particular i.c. or other circuit, which may be lower than these figures.
For a 9V supply, the p-p voltage is, depending on the actual circuit, about 8.
With an 8Ω load that translates to a power of 1W, in a 4Ω load 2W, and in 2Ω 4W.
The arithmetic for a 12V supply gives 1.56W in 8Ω, 3.12W in 2Ω and 6.35W in 2Ω.
With an 18V supply the figures are 4W in 8Ω, 8W in 4Ω and 16W in 2Ω.
Let's do the arithmetic, using the equation I gave (which is, believe me, correct.)
The equation is:
power in load = peak to peak voltage across the load divided by 8 times the load impedance
i.e. assuming an unlikely rail to rail swing, 120 x 120 ÷ (8 x 8)
14,400 ÷ 64 = 225W
P = Epp² x 8RL
In your second comment you used: P = Epp² / 8RL
I can live with the second equation just fine! It works the same as the formula I use: Pavg = (Vpeak)^2 / 2R
My amp clips cleanly and symmetrically at 120 Vp-p at 8 ohms, will not clip at 4 ohms, just blows the 8A line fuse before it gets to clipping. These tests used dummy loads, of course!
There were several questions about power so I will try to explain a bit. While the chip is rated for up to 10W output, actual power depends on several factors (supply voltage, speaker impedance, cooling of the chip and level of distortion user can tolerate).
Obviously one cannot get 10W output from 0.5W speaker. Also distortion is important so keeping it under 0.1% is a very good idea. For example rated 10W output is at massive 10% distortion which is not really usable.
Figure 7 of ST datasheet ( http://www.datasheetcatalog.org/datasheet/stmicroelectronics/1449.pdf ) shows that on 4 Ohm, good quality output can be produced only up to 4W (when powered from 14.5V). To get a bit more power (and keep distortion low) one needs lower impedance speaker and higher voltage. We could use this ratio as rule of thumb to estimate reasonable power output at low distortion to be less than half of rated (4W is close to half of 10W).
Figure 3 of mentioned datasheet shows relationship voltage/speaker impedance/maximum power. that on 4 Ohm and 9V for example, maximum output power is 2W (or about 1W if we want to keep distortion low).
Figure 11 shows efficiency of the amp with 4 Ohm speaker.
For power up to 4W or so, efficiency is under 50%.
this means that 4W on speaker,is only half (or less) of power amplifier takes from DC power source. The difference is turned into heat. One of my soldering irons is 8W so even little power can reach high temperature if concentrated in small area (this is why we need heatsinks- it is to increase cooling area). But for cooling to be efficient, it need to allow air circulation, otherwise it will only work until air inside enclosure warms up. After that, area of the enclosure and heat conductivity of the enclosure walls are another limit.
Battery operation of course limits maximum output specially since 9V batteries are only good for low current. For example one of top brands is Energizer and here is datasheet for 9V battery:
http://data.energizer.com/PDFs/522.pdf
Note that at higher current draw, capacity drops down. For example at 500mA capacity is only about 300mAh so it would drain in (300mAh/500mA)*60min = 36minutes. But look closer, the datasheet shows that this is to discharge battery down to half of rated voltage or 4.8V. For amplifier this is unusable. Probably the most one can get is discharge to say 7V which is maybe half this time. Also batteries one get may not be top brand and maybe they were sitting on the shelf for long time so capacity is lower.
My estimate is that is good for up to 0.25-0.3W in current application (which is still plenty of fun).
10 watts of audio are a lot for a so little amplifier.
Yes , it a little amplifier but I prefer look at the concept ^_^
I must learn a lot from you ...
have better idea ??
thx for your comment
maybe I will draw a mark to define it
So I use wire to make it clean and neat
because they have same pinout,
but max supply power for td2006 is 15Volt and for tda2003 is 18volt.
Power output tda 2003 is 10 W and tda 2006 is 12 W...
but I suggest you use the circuit for tda2006