DC Boost Converter

My first intention was to design a DC Voltage boost converter to convert 3vdc to 5vdc so that I could power my iPod or any other device requiring 5 volts to charge.  I read about oscillation circuits and boost converter circuits and combined the two.  My results were staggering when I was able to convert 4.5 volts to over 100 volts by accident.  I decided to post an instructable for this instead, for now. If you have any tips to increase the efficiency or output current please comment below, I appreciate any suggestions.
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Step 1: Obtain Parts

Picture of Obtain Parts
All components can be found at RadioShack.
     3 X 1.5 volt Battery Holder
     L1     RF Choke                   100 micro Henries
     R1     Resistor                      10 Ohms
     R2     Resistor                      51K Ohms
     Q1     PNP Transistor          2N3906
     Q2     NPN Transistor          2N3904
     Q3     Power MOSFET         IRF510
     C1     Capacitor                    .01 micro Farads
     C2     Capacitor                    .047micro Farads
     D1     Diode                           1N4148

Step 2: Place Components

Picture of Place Components
Arrange components as you see here or as close as possible.

Step 3: Observe Diagram

Picture of Observe Diagram
Look through the wiring diagram to see what components need to be connected to what prior to soldering.

Step 4: Solder Components

Picture of Solder Components
Solder components carefully to ensure there are no shorts, also ensure all connections are made at all points.
Madoxa1 month ago

Its a very nice circuit thank you , i have applied the schematic and built the circuit but unfortunately it won't work i do not know where the problem is following some notes regarding my circuit :

V source : 3.7v battery


PNP transistor : BC327 NPN transistor:2n2222 the rest is the same as your recommendation

Simulation results Vout = 6.7 whrer my result Vout=2.3

any Tips or suggestions


Coldwove Madoxa22 days ago


I think it's the pnp and npn transistors

PNP and NPN are different and not compatible unless you invert the current which i believe is prettey complicated to do, try to find a PNP transistor, you can search for equivalents on: if you dont have any, scrap a power supply or a radio you will normaly be able to find some on there.

hope it helps :)

To answer some questions here, even if I am a bit late:

ashot211: The reason MOSFETs heat up is mainly because the gate-source voltage (required to turn it on) is usually too low. Meaning, you likely have the wrong MOSFET. Did you specifically use the IRF510?

liamdeg: Ohm's Law says yes. However, batteries have a rating for how many milliamp-hours (mAh) they can put out - so, by using a higher current, you use up the battery faster. This is a proportional ratio.

antionlog: I use a 6V lead-acid battery, and the voltage is about 150V coming out. So, by that ratio, a 9V in would lead to about 200V out (196.51V, to be more exact). Likely, it would not actually produce such a voltage, because this is on the way-high end of most MOSFETs' capabilities.

amruth: See Ohm's Law.

Anyway, I put the diode in backwards and used the wrong MOSFET on my first try, so I plan to correct that today. The first MOSFET heated up to the point that the metal began to self-temper (turned an iridiscent sheen of colors due to oxidation by heat and air), and the voltage started at 150 consistently but dropped just as consistently. Hopefully, the IRF510 and the reconfiguring of the diode will fix things.

ashot2115 months ago
I just finished the circuit,it works but after about 2 minutes, the voltage starts slowly droping down to 4.5 v and mosfet getting hot .can you troubleshoot PLS
liamdeg5 months ago
Awesome circuit!!

Im curious about boost converters and the current they produce. Say its outputting 100v and you connect it to a 5 ohm resistor will you get a 20 amp current? or dose the boost converter affect/limit the current? thanks
liamdeg5 months ago
Awesome circuit!!

Im curious about boost converters and the current they produce. Say its outputting 100v and you connect it to a 5 ohm resistor will you get a 20 amp current? or dose the boost converter affect/limit the current? thanks
antioniog6 months ago
What would happen if i were to hook up a 9v battery to this instead of 3 1.5v batteries.
Boost converter
soufiemaak7 months ago
hey, thats a nice one,
i wanna make step up converter using 555 timer get 12v from 5v
can you send me circuit
thank you
juanjomf11 months ago
hello as I can make 12 volt dc converter to 12 volts ac ?
I am looking at taking 5v up to about 12v what resistor should I replace with a pot to find out what value of a resistor I need?
amruth2 years ago
how many amps come out from the output. Plz tell me waiting for a reply. Thx.
Umniscient2 years ago
Hi there, nice guide.
Suppose I removed the output diode. Would the modified circuit produce AC?
No, it will give the same voltage from the batteries
Zettu2 years ago
i put this schematic together with every component the same the power source is two AA's at 3v 2600mAh roughly the output voltage is 6.48v by putting potentiometer for the 51kohm resistor and turning it down slightly i was able to get 7v however the current output is really low and i'm not sure it would be effective for charging anything on usb even with a voltage regulator on the output to ensure 5volts, i was thinking of maybe experimenting with the a zener diode near the output somewhere rated at 5volts or maybe 12v and regulator 7805 on it, but i wondering how you got 100v cause i have another experiment that involves high voltage and low current for illuminating a gas tube or even a small fluorescent off of 2 AA's ,,,, let me know what you think about these ideas maybe we can collaborate on some ideas,, :)
jules153 years ago
Will this work for 350vdc to say 1000 vdc (camera tazer)? If not how can I do this?
ARJOON jules153 years ago
INSTEAD USE CAMERAs you can get approximately 60kv
jules15 ARJOON3 years ago
I don't understand.. I'm already using a camera
ARJOON jules153 years ago

on your first circuit in the camera. remove the capacitor and instead place this transformer from another camera.(must be alike)

solder pin 1 to one lead of the cap outpuit
then solder pin 3 to the other lead.

then you will get an output more than 60kv (more than enough to kill) in pins 4 and five.
i've never tried but if it works pin 4 and 5 will be arcing a lot.
I need to convert a 6v 4.5A battery into 12v that can give around 2A or more current
any schematic? Voltage doubler circuits on the web gives around 100mA which is not sufficient for motor driving. Thanks...
try using an oscillator n rewind a small 1:1 transformer to 1:2 n u may get it
Can I do this with some IC ? I don't have much knowledge of transformers.
use the so known 555oscillator. amplify through transistor or mosfet which in turn will drive the transformer to double the voltage. don't forget to rectify the other end
sir can u provide me the circuit diagram please.
u can use this circuit. but reduce the frequency to about 40-75Hz. this will enable you to use a normal transformer.
jules15 ARJOON3 years ago
Ok thanks a lot ill try it
Mudbud ARJOON3 years ago
uhm, Ive only gotten 300VDC outta camera circuits..
Wouldn’t 60kv volts arc across the transformer and destroy it. I highly doubt you can get that from a camera flash. Even a neon sign transformer can’t put out that much.
yeah i burnt mine instantaneously. that was crazy. when i opend the transformer. wire in the secondary was burnt. it was like dust.
Did you measure the voltage before it burnt out?
no i did not that was quick.
N3v3rm0r32 years ago
4.5VDC input, at what amperage? I don't want to use batteries...
gerbil_man3 years ago
Would this still be able to charge an ipod touch 3G?
The iPod's have a very weird charging system watch this video
Inducktion3 years ago
What kind of wave does it output? Square wave right?
VicentiuB3 years ago
how many amp output from this circuit ?
anvit3 years ago
How did you calculated the value of the capacitors .?
can we replace them by any other values ?
V1x0r3 years ago
Soooo...because I was having a hard time with initial directions I made this little "Solder directional based off of MOAL's pdf.

Thanks for the Tut btw!!!! I'm excited to get this finally put together!

(Q1a - L1a - R1b) --> power Input
(Q1b - Q2a)
(Q1c - C1a - R2a)

(Q2b - R1a - Q3a - C1b)
(Q2c - C2a - Q3b - R2b)

(L1b - D1a (side w/o black strip) - Q3c)

(D1b - C2b) --> power out

Please correct me if i'm wrong.

I don't know which ends connect to the grounds. >_<
V1x0r V1x0r3 years ago
(Q2c - C2a - Q3b - R2b) connect to a ground. Correct?
ARJOON V1x0r3 years ago
i messed up with datasheets on my pc that is why it got all screwed up now this new pcb design is the good one.

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