My first intention was to design a DC Voltage boost converter to convert 3vdc to 5vdc so that I could power my iPod or any other device requiring 5 volts to charge.  I read about oscillation circuits and boost converter circuits and combined the two.  My results were staggering when I was able to convert 4.5 volts to over 100 volts by accident.  I decided to post an instructable for this instead, for now. If you have any tips to increase the efficiency or output current please comment below, I appreciate any suggestions.

Step 1: Obtain Parts

All components can be found at RadioShack.
     3 X 1.5 volt Battery Holder
     L1     RF Choke                   100 micro Henries
     R1     Resistor                      10 Ohms
     R2     Resistor                      51K Ohms
     Q1     PNP Transistor          2N3906
     Q2     NPN Transistor          2N3904
     Q3     Power MOSFET         IRF510
     C1     Capacitor                    .01 micro Farads
     C2     Capacitor                    .047micro Farads
     D1     Diode                           1N4148

How can i make boost converter using 9V battery? Nd what are the ratings of all components?plz rly me
<p>If I use a Peltier Cooler attached to processor in my laptop and mix it with this booster, will it charge the battery(currently using 19v 3.42a charger, total 65W).</p>
<p>lushprojects DOT com/circuitjs/circuitjs.html</p><p>IMPORT FILE IN CIRCUIT APPLET </p><p>pastebin DOT com/kf67QtMA</p><p>Tweek it and lets make this work! I tried and get 0 volts out.</p>
<p>I think the issue you are having is that lushprojects cannot properly model the power mosfet. Also, I believe you inserted a P-channel mosfet, and have the source and drain backwards for an N-channel.</p>
<p>I found a 12V to 15V step up converter on Ebay. It has a +/- input and a +/- output wires. If I were going to use this on a car, how would you wire it up having four wires? Could you connect both the negatives to the car's chassis and feed 12V to the converter and 15V to the accessory then ground the accessory to the chassis? Or does it have to be grounded back through the converter? </p><p>This would be used to speed up a wiper motor.</p>
<p>There's a very big chance both negative IN and negative OUT are already connected on the PCB. If so, you can indeed connect GND to the chassis without using extra wires. Be sure you're not driving some special ancient car, which has +12v connected to the chassis though.</p>
<p>where can I get 100uH RF Choke??</p>
<p>How can i boost 9VDC-350ma to 9VDC-2ampre</p>
<p>Next Level impossible bro. use less resistance in your circuit and you will get more amps out of your battery or whatever you need to do. </p>
<p>You can't get more power out than you put in. </p>
<p>You're trying to change 3.15 watts (V*A) of power into 18 watts of power which is impossible. You'll need a power source that can supply at least 18 watts of power.</p>
<p>Hi, can you help us convert an input millivolts to a higher voltage (around 9v)? Please, it would be a big help. Thank you very much!</p>
<p>This same circuit will probably not work because (just a guess) the transistor will probably need 500 millivolts to 1 volts to turn on. (idk this is what the base-emitter voltage is on some general purpose transistors) Depending on the use, you may want to use an opamp to achieve this. Could we have some more information to help you?</p>
<p>Nice work! Also try using electrolytic capacitor for C2 and a schottky-barrier diode like 1N5822 or 19 for better results. I once accediently made a similar circuit(joule thief) which flashes a 12V10W power LED from a single 1.5v cell.</p>
<p>hey, how can i achieve very high dc voltage like in kv</p>
<p>if i am not wrong, you could use a transformer for that purpose :)</p>
<p>transformer with dc i dont think so </p>
<p>It is very possible. The inductor in this circuit is creating a high voltage from a low voltage because it is being fed pulsating DC from the MOSFET that is fed from the two transistor oscillator circuit.</p><p>Replace the simple induction coil with a transformer that has a very high turn-count secondary, and you'll get much higher voltages. Use an ignition coil, and you'll have exactly what creates a spark in your car. In my 1951 Chevy, an ignition coil, otherwise known as an autotransformer, since the primary and secondary are connected together at one end, creates a very high voltage spark with from 5 to 7.4 volts, depending on whether the car is being started, or the generator is running. A while back I fitted the car with a 'Blaster' brand coil, which only requires about 3 volts to create a good spark, and so I wired it with a relay so that it receives a direct feed from the battery when the starter motor is activated, and then receives reduced voltage through a resistor once the engine is running. </p><p> You could very easily achieve thousands of volts with the 4.5 volts specified above and an ignition coil.</p>
I have some question it is the thing. Can my power amp rates 16 volt can power it by your design??? Pls answer me
Can I use this circuit to obtain 8v700ma from 3.6v2600ma bettery. How can I do this
<p>How can i boost 9VDC-0.35ma to 9VDC-2ampre</p>
<p>It's watts that kill you, or more precisely, Joules(energy), which is current*voltage*time. As long as the voltage is high enough to overcome your resistance, you're toast.</p>
<p>Hi! everyone i have a problem cause i use BC249 for NPN and BC259 for PNP and a mosfet IRF630 and a source of 5vdc but why the output is just 4.87vdc. i do know where i got wrong. somebody can help me please.. </p>
<p>hi. thank you for your info. i change R2 by variable resistor bot out put voltage did not change . i need 500v dc for out pot may i have this voltage in this circuit.?</p><p>thanks</p>
<p>hi. thank you for your info. i change R2 by variable resistor bot out put voltage did not change . i need 500v dc for out pot may i have this voltage in this circuit.?</p><p>thanks</p>
<p>hi . it is great. thank you</p>
<p>what is the use of transistor,diode,mosfet and capacitor in this setup...</p>
<p>i need the whole working of this project so that i able to make my report .can anyone help me plzzz..</p>
<p>Its a very nice circuit thank you , i have applied the schematic and built the circuit but unfortunately it won't work i do not know where the problem is following some notes regarding my circuit :</p><p>V source : 3.7v battery</p><p>MOSFET : IRF530</p><p>PNP transistor : BC327 NPN transistor:2n2222 the rest is the same as your recommendation</p><p>Simulation results Vout = 6.7 whrer my result Vout=2.3</p><p>any Tips or suggestions</p><p>Thanx</p><p></p>
<p>Hi</p><p>I think it's the pnp and npn transistors</p><p>PNP and NPN are different and not compatible unless you invert the current which i believe is prettey complicated to do, try to find a PNP transistor, you can search for equivalents on: <a href="http://alltransistors.com/" rel="nofollow">http://alltransistors.com/ </a> if you dont have any, scrap a power supply or a radio you will normaly be able to find some on there.</p><p>hope it helps :)</p>
<p>To answer some questions here, even if I am a bit late:</p><p>ashot211: The reason MOSFETs heat up is mainly because the gate-source voltage (required to turn it on) is usually too low. Meaning, you likely have the wrong MOSFET. Did you specifically use the IRF510?</p><p>liamdeg: Ohm's Law says yes. However, batteries have a rating for how many milliamp-hours (mAh) they can put out - so, by using a higher current, you use up the battery faster. This is a proportional ratio.</p><p>antionlog: I use a 6V lead-acid battery, and the voltage is about 150V coming out. So, by that ratio, a 9V in would lead to about 200V out (196.51V, to be more exact). Likely, it would not actually produce such a voltage, because this is on the way-high end of most MOSFETs' capabilities.</p><p>amruth: See Ohm's Law.</p><p>Anyway, I put the diode in backwards and used the wrong MOSFET on my first try, so I plan to correct that today. The first MOSFET heated up to the point that the metal began to self-temper (turned an iridiscent sheen of colors due to oxidation by heat and air), and the voltage started at 150 consistently but dropped just as consistently. Hopefully, the IRF510 and the reconfiguring of the diode will fix things.</p>
I just finished the circuit,it works but after about 2 minutes, the voltage starts slowly droping down to 4.5 v and mosfet getting hot .can you troubleshoot PLS <br>
Awesome circuit!! <br> <br>Im curious about boost converters and the current they produce. Say its outputting 100v and you connect it to a 5 ohm resistor will you get a 20 amp current? or dose the boost converter affect/limit the current? thanks
Awesome circuit!! <br> <br>Im curious about boost converters and the current they produce. Say its outputting 100v and you connect it to a 5 ohm resistor will you get a 20 amp current? or dose the boost converter affect/limit the current? thanks
What would happen if i were to hook up a 9v battery to this instead of 3 1.5v batteries.
Boost converter
hey, thats a nice one, <br>i wanna make step up converter using 555 timer get 12v from 5v <br>can you send me circuit <br>thank you
hello as I can make 12 volt dc converter to 12 volts ac ?
I am looking at taking 5v up to about 12v what resistor should I replace with a pot to find out what value of a resistor I need?
how many amps come out from the output. Plz tell me waiting for a reply. Thx.
Hi there, nice guide.<br>Suppose I removed the output diode. Would the modified circuit produce AC?
No, it will give the same voltage from the batteries
i put this schematic together with every component the same the power source is two AA's at 3v 2600mAh roughly the output voltage is 6.48v by putting potentiometer for the 51kohm resistor and turning it down slightly i was able to get 7v however the current output is really low and i'm not sure it would be effective for charging anything on usb even with a voltage regulator on the output to ensure 5volts, i was thinking of maybe experimenting with the a zener diode near the output somewhere rated at 5volts or maybe 12v and regulator 7805 on it, but i wondering how you got 100v cause i have another experiment that involves high voltage and low current for illuminating a gas tube or even a small fluorescent off of 2 AA's ,,,, let me know what you think about these ideas maybe we can collaborate on some ideas,, :)
Will this work for 350vdc to say 1000 vdc (camera tazer)? If not how can I do this?<br>
INSTEAD USE CAMERAs you can get approximately 60kv
I don't understand.. I'm already using a camera
<br>on your first circuit in the camera. remove the capacitor and instead place this transformer from another camera.(must be alike) <br> <br>solder pin 1 to one lead of the cap outpuit <br>then solder pin 3 to the other lead. <br> <br>then you will get an output more than 60kv (more than enough to kill) in pins 4 and five. <br>i've never tried but if it works pin 4 and 5 will be arcing a lot.
I need to convert a 6v 4.5A battery into 12v that can give around 2A or more current<br>any schematic? Voltage doubler circuits on the web gives around 100mA which is not sufficient for motor driving. Thanks...
try using an oscillator n rewind a small 1:1 transformer to 1:2 n u may get it

About This Instructable


109 favorites


More by krmartin3: Portable Speaker LM386 Audio Amplifier Full Spectrum Flashlight
Add instructable to: