This instructable will take you through the process of making a variable power supply (voltage regulator really) that is able to output 1volts to 17volts from 12volts 1000mA input (standard dc adapter).
The main schematic isnt mine but other than that its all my work, i also replaced the 1N5402 with 1N4007 since i didnt have the first available, the 4007 is much power full than the 5402 and it can handle up to 1000mA (which is our current rating), other than this diode every thing else is easy to find and available in most electronics shops.
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Signing UpStep 1: Materials
1x LM317 regulator
2x 1N4001 diode
1x 1N4007 diode
1x 1k resistor (for the led)
1x 220R resistor (R stands for 0 right hand zeros i.e. ohms)
1x 18k resistor
1x 470uF 40+ v electrolytic capacitor (minimum rating is 40v any thing higher is ok)
1x 470nF ceramic capacitor
1x 4.7uF 40+ v electrolytic capacitor
1x 10uF 40+ v electrolytic capacitor
1x 100n ceramic capacitor
1x LED (i used 5v blue LED so any thing between 1.5 and 5 will work and any color of course)
1x ON-ON switch (3 legs)
1x DC adapter jack
1x 10k potentiometer !!!LINEAR!!!
1x 4x7 cm blank PCB
Others:
Ferric Chloride etchant
Acetone
Glossy paper
I used some old computer screws to make stands for the board, so u r free to either use the idea or just get creative :)
Tools:
Water resistant marker (for fixing broken traces)
Laser Printer
PCB Drill
Solder iron
Solder
Cloth Iron

































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might be what your looking for
1. An LM317T is nominally rated for 1.5 Amps only. This means the maximum you can draw is 1.5A.
2. The regulator has an overhead voltage of about 3V. Running from a 12V supply, you'd be able to get an adjustable range of 1.2V to 9V
3. Be careful of the Total Dissipated Power(TDP). If regulated to say 5V, there is 7V dropped across the regulator. Now say that you are running a light bulb consuming 800mA. The TDP for the regulator is 7V x 800mA = 5.6Watts. This will require a heatsink to get rid of the heat generated.
Hope this helps.