Before I get too far in this instructable, I would like to say that this was not my original idea. You can see two implementations of this idea already on Flickr. The links are:

On with the instructable! This documents how to turn a regular disposable camera into a high voltage power supply capable of driving 2 or 3 medium-sized nixie tubes, for roughly $8.

This instructable works with voltages in excess of 250V. This is more than enough to give you a potentially fatal electric shock if handled incorrectly. If you are unfamiliar with how to work with high voltage, please refrain from performing this instructable. Exercise caution throughout the following steps to avoid electrical dangers. If you choose to undertake this instructable, you do so at your own risk.

This instructable involves soldering. A soldering iron becomes very hot during its use, to the point where it can cause instant second-degree burns. Exercise caution throughout the following steps to avoid burns. If you choose to undertake this instructable, you do so at your own risk.

Step 1: Gather Materials and Tools

For this instructable, you will need:

A disposable camera
A potentiometer of 100Kohms or higher
A resistor of 50Kohms or higher
Wire cutters
A small screwdriver (may not be needed, depends on your camera)
A multimeter
A soldering iron
Red wire
Black wire

Step 2: Disassemble Camera

This step is going to vary depending on the camera you choose to take apart. I will post a pictorial description of how I took mine apart, but know that not all cameras are alike.

Also, this step is probably one of the more dangerous steps, because you do not know if the capacitor is charged currently. Do not touch the capacitor or the flash circuit at this point, it may still have energy stored that could electrocute you. Being electrocuted is a bad thing.

Once you expose the capacitor, I highly recommend discharging it. This can be done by touching both wires coming out of the bottom of the capacitor with a screwdriver or other metal object. Make sure the object you use to discharge with has an insulated handle, and only use one hand to minimize risk of electricity flowing across your chest. I also recommend wearing safety goggles, because if the capacitor is charged, sparks will fly, and you don't want one of those sparks in your eye. (sparks can also known as superheated airborne metal fragments)

Step 3: Attach Wires.

To make this circuit more convenient to use, it is time to add some wires. Notice the capacitor has a stripe on it. The black wire will connect to the lead beneath the stripe, and the red wire will connect to the other lead.

Step 4: (optional) Make It Safer

This step is optional, but I highly recommend it.

Solder a resistor across the leads of the capacitor. This will enable it to self-discharge in a controlled manner. You can use any resistance over 50Kohms, but the lower the resistance, the faster the circuit will decrease to a safe voltage. I clocked mine, at 100Kohms, the circuit went from full power (about 230V) to a more reasonable 20V in about a minute. 50Kohms makes the circuit safe in about 30 seconds.

Alternatively, you can completely remove the capacitor and never need to worry about stored charge again.

Step 5: Case It Back Up.

In the interest of maximizing safety, I chose to put the circuit back into the camera's shell. I ran the wires out of the rear viewfinder window, so I had to poke a little piece of plastic out of the window.

Step 6: Create the Circuit and Use.

Now, wire up the circuit for the nixie tube. Put the potentiometer in between one of the leads and the nixie tube, and adjust as needed. With my IN-12A tubes, 200Kohms pass about .3 mA, which is enough to illuminate the tubes, but is not very bright. Experiment with your own tubes (use the multimeter here). Sorry for not showing pictures of the calibration process, but this circuit blew out my multimeter when I accidentally created a short circuit. Like I said, be careful.

When the camera is on, the high voltage is present, so please exercise caution when using this.
<p>The capacitor just blown up in my face :S </p>
<p>What would be the easiest way to step this (mine outputs ~260V) down to 200V? I am looking to drive 3 IN-1 (ИН-1) tubes.</p>
<p>Easiest: increase the series resistance. I don't know the properties of your tubes in particular, but if you model them as a 200V ideal voltage sink, then use Ohm's law to find the resistance needed to get your tubes rated current at 60VDC.</p><p>Is it elegant? No. Not at all. Will it work, sure!</p>
<p>Thanks, that was helpful, but it turns out the power supply is so piss-weak it steps down to below 200V as soon as you hook anything up to it. No adjustment required!</p><p>P.S. You could also just use a trimpot as a quick-and-dirty voltage divider, if needed.</p>
ive accedentialy shorted one of those caps with my finger.<br><br>i guess as long as its on the same hand, theres no worry (not across the heart) but it HURTS LIKE HELL
I was burned by a transformer from a scanner fluorescent lightbulb. Luckily it was just across my finger. Hooked up to a computer power supply, ouch... I had charred spots on my finger.
I only got shocked by a small transformer, nothing big, it was the transformer that comes with the &quot;Radioshack Learning Lab&quot; kit.
Hey! I have that kit. It's pretty useful. I'm still learning from it. I also made a shocking circuit from it and you could adjust how much the shock hurt. I don't think that kit is still being sold, is it?
Its true, if you only work with one hand, and zap yourself only through that one hand, you are less likely to stop your heart via electrocution.<br><br>That being said, enough of a zap can create internal burning, putting the victim into shock, so there is always the chance of a fatal shock when working with voltages above 36V (some sources say as low as 12V).<br><br>Always remember, electricity is our friend, and just like any friend, you better treat it with respect, or else you will get burned.
I got a shock of a car battery once, despite my beliefs that there isn't enough potential difference to across our body
All depends on the person, some can feel shocks from sources as low as 10V, some don't notice till much higher.
I got shocked by an EL wire inverter and it wasnt pretty. It's output was 200 volts ac but it only ran off 2 AA cells. So, i guess it is a matter of current, not volts. My slayer exciter outputs 4000 volts and it burns my finger!
Current and voltage play parts in how dangerous it is, but current is the main factor.
Yes. If you don't have enough voltage, you cant pull the current needed, however high voltage doesn't meen that it will pull a large current. the power supply high not provide enough of a puch.<br><br>U=R*I<br><br> so if R is high and U is low, I needs to be low or the math wouldn't add up
Pretty much any wall wart can kill you, hence why GFIs trip at about 4 milliamps (but wont work unless current isnt returning, like using two hands to stick two bare wires into the hot &amp; neutral of a GFI, it wont ever trip if Iin=Iout).<br><br>Higher voltage makes the current able to travel along or penetrate your skin.
While that's true voltage is not what kills you. Tazers operate at 1mill+ volts! It's the amperage that is dangerous.
A few people have been killed in my old line of work, 48v DC systems in telecom offices.<br><br>I only got ring voltages on my forearm when reaching in to hook up wirewrap connections on the AT&amp;T switch.<br><br>You dont always know that cap energy wont go in your finger, up a nerve of vessel and navigate its way to a vital organ and not right out again.
you could DIE <br>
Um... its not the voltage that kills its the amps... and realistikly think about it. Can u touch both ends of the 1.5V battery with out dying? V=ir therefore if you increase the voltage u decrease the current thus making it not deadly. HOWEVER THIS DOES NOT APPLY IF U HAVE A PACEMAKER!! That zap can stop it... basicly: Yes use caution when working with electricity No u wont die if you touch the cap. It will hurt a LOT tho. BTW a car battery can kill even if it only has 12V because it can out put MASSIVE amout of current!
What you said does not make sense. &quot;V=ir therefore if you increase the voltage u decrease the current thus making it not deadly.&quot; Basic algebra states that increasing V while holding R constant will result in an increasing I. <br> <br>You are correct, that it is current that kills, not voltage. However, the human body has a skin resistance of approximately 47kOhms, when dry, so you need a reasonably high voltage to generate a dangerous amount of current across the chest. Basic V=IR shows you only need about 1V of potential difference to generate the generally regarded to be &quot;lethal&quot; current of 10uA across the chest, but don't forget the cross-section of the chest is rather large in comparison to the heart, so not all of the current flows through the heart. <br> <br>Once you exceed about 36V though, that cross section difference is not always enough to prevent a lethal current from flowing through the heart. Some people are more sensitive to it than others (some people can feel a jolt with as little as 10V), sure, but you won't see me grabbing two terminals at a 36V potential difference with opposite arms. Because these capacitors can let out a jolt at upwards of 300V, you see how they can be dangerous; only one pulse of &quot;enough&quot; current is needed to do very weird things to the heart. <br> <br>This is why when working with high voltage, you want to use only one hand, and pocket the other. This way, current is not inclined to flow through the chest; it will stay in the arm, maybe cause external and/or internal burns, but that's a far better fate than stopping the heart. <br> <br>It is actually known that a 9V battery can kill; if you manage to pierce the skin with both terminals in such a way that the current chooses to flow through your bloodstream into one arm, across the chest, and out the other, enough current is generated to stop the heart. This is because blood is rather low-resistance, so a high current is generated. Without your skin acting as a safety resistor, even surprisingly low voltages can be very dangerous.
tl;dr <br>Current is the killer, but you need sufficient voltage to overcome resistance to cause harm. <br>Low voltage is dangerous in *some* cases. <br>High voltage is dangerous in *all* cases. <br>(The above is only true when working with DC.)
I see. Well i always thaught that because the power needed came from a 1.5V battery ment that no matter what it should not kill you but Its good to know now that I am wrong as im starting work with el wires. Wouldn't wana make this my last project! Thanks!
if used (in)correctly energy from a 1.5 volt battery may be able to do some harm, however if you remove the capacitor all you can get is a painful shock, the capacitor on the other hand could probably do quite alot of damage, i have been working on something a bit similar today.
Also worth noting: the 47kOhms of dry skin resistance generally will completely overwhelm the internal resistance of a battery. That is why you can take (usually) 12V worth of AAA batteries, or a 12V car battery, and touch across the terminals with dry skin, and you won't know the difference; the current that will flow is almost identical, despite the car battery's significantly lower internal resistance. <br> <br>Assuming a car battery to have an internal resistance of 0.2Ohms, and AAA batteries to have a series resistance of 100Ohms, we get: <br>12V / (47k + 0.2) = 255uA <br>12V / (47k + 100) = 254uA <br>Not much difference! <br> <br>Of course, with wet skin (or in the case of pierced skin), this story changes dramatically. Let us assume we're talking pierced skin, so only the blood is providing resistance, and let us assume blood provides 10Ohms of resistance: <br>12V / (10 + 0.2) = 1.17A (yes, Amps...you'd be good and fried) <br>12V / (10 + 100) = 109mA (still very dangerous) <br> <br>Our friend the capacitor, as discussed above, has a resistance similar to the car battery, extremely low, and therefore extremely dangerous when at high voltage.
dude take the batterys out first &gt;.&lt; derp &gt;.&lt;
You can take the battery out (there is only one), but the capacitor will remain charged. Only taking the battery out and failing to discharge the capacitor is a great way to get yourself electrocuted.
You are exactly right! Except I was trying to repair a digital camera and one of the caps lit me up! I didn't know that cameras had components that required such high voltages and amps.<br><br>It is much worse than grabbing AC wires! Always discharge any cap before working on any circuit. I do now!
This just saved me A LOT of time! Thanks!<br><br>(When I was younger, I was messing with one of these boards. I knew better than to touch the large menacing cap, what I didn't think about was avoiding the solder points it of which it was attached to other parts of the board. Lesson learned.)
I always thought that these circuits provide around 300 volts. How did you get it to be around 180? Voltage divider? If so, can I use 1/4 watt resistors?<br> <br> I presume you shorted your multimeter with connecting it directly to the output? I didn't know these can provide currents over 200mA (these usually have fuses rated at 200mA).<br> <br> Other than that, it's a nice instructable you've got there!<br>
Yes, I had a 200k ohm potentiometer in series with the nixie, so the nixie would drop 180V, and the pot would drop the rest. It seems these circuits have a fairly high internal resistance, so they cannot output very much current. In fact, if we take a look at step 4, we can somewhat figure out the internal resistance!<br><br>If we assume that the circuit will output 300V open-circuit, and by putting a 50k ohm load across the voltage source, the output then sags to 230V, you should be able to use ohm's law to figure out the internal resistance. (230V / 50k = current; 70V / current = internal resistance). Obviously this is flawed because we don't know if the open-circuit voltage is 300V, but its the best I've got for now.<br><br>As for my meter, I did connect it across the output with a fully-charged capacitor in place. While the circuit itself can probably only supply 10mA or so short-circuit, the capacitor can dump a fair amount of current, which it did.
Thanks for a fast response!<br>I did exactly the same thing a couple years ago. Fuse in the meter blew so hard that I could see a huge spark flash through the nontransparent meter casing! But fuses are quite cheap, so thats not a problem.<br><br>Also, do you think a 1/4 watt resistor can do? Im not sure, coz, lets say the current is 10mA, voltage drop on a resistor 120V, so that's 1.2W.<br>Or am I wrong here?
Depends on what you're trying to power. If you're going to max out the supply, then in theory, yes, a 2W resistor is needed (though I feel like the camera might burn out first). If you're just trying to light a nixie or two, I've only needed to pass about 2mA, which is 230V (voltage source after adding safety resistors) - 180V (nixie tube voltage) = 50V * 2mA = .1W, so well within the abilities of a 1/4W resistor.
Okay, thanks for your time!
Does the charge button need to be shorted?
This camera actually had an on-off switch for the flash, rather than the more common &quot;button&quot; design. I didn't have to short anything, but rather used the on-off switch as a power switch for this power supply. I liked having that feature rather than having an &quot;always on&quot; supply that would've resulted from shorting the charge button.
I had to solder the charge button closed to get my Nixie to light up, i dont think you mentioned that. Maybe yours doesnt use a charge button? I got some modern Kodak ones from Walgreens' recycle box.
So I can just discharge the cap and then cut it off as long as the wires are connected to the circuit?
Sure, that is probably a much safer way to use this circuit.<br />
Wouldn't holding the shutter button down for a few seconds be enough to discharge the cap so that it would be safer to open?
Not always. The gas discharge tubes that make up a camera flash work on the same principle as the nixies in that they will operate down to a certain voltage, then stop conducting. The point where they stop conducting will often leave a fairly high voltage still in the capacitor.
I've heard rumor that replacing the cap with a diode is a preferred solution, but I don't actually know why, nor what orientation to place the diode in. Thoughts?
You would want a diode rated for 200V reverse breakdown voltage, connected &quot;backward&quot; so that it would not normally conduct.<br>Why?<br>Well, the diode would prevent current from flowing as the circuit powers up. However, nixie tubes like to be driven around 180V, more than that and you might put too much power through them, shortening their lifespan. The diode will start conducting backward when the circuit is at 200V, ensuring the circuit stays at or below 200V. This does improve safety somewhat as well.<br><br>Now, with this circuit's approximate internal resistance of 15k, that means the internal resistance must dissipate 100V (the diode drops the other 200), for about 6mA of current. This results in the diode dissipating 200V * 6mA ~ 1.3 W of power, so get yourself a diode rated for 2 or more Watts of power dissipation, and you'll be set!
<p>Alright, i'll try it sometime.</p>
What was the uF (capacity) of the capacitor. I want to know so I can crunch some numbers and figure this out.
Well, I no longer remember where I put this circuit, so I don't really know. Going by the pictures, I'd say this is a 330V, 80uF capacitor.
This is a fantastic ible rated 4.5* Maybe you would like to have a look at my ibles as well<br>
how long did the battery last? and have you given any thought into how to power this system from a wall wart?
I believe the original battery that came with the camera lasted about 12 hours. Not the most impressive battery life, but its also only $8. I think I once measured the efficiency to be 70%, though don't hold me to that. As for wall wart power, you'd have to find some way to get the voltage down to 1.5V. Since this is a pretty simple power supply, the voltage of the battery is proportional to the output voltage, so feeding the camera 5V directly could very well turn into about 700V (untested, so it might not). I suppose you could get a 5V wall wart, then run the power through a few diodes, taking advantage of their forward voltage drop to get the voltage down to what it needs to be. I think when running an IN-12A tube at its rated current of 2mA, the current draw on the battery was about 350mA, so that also needs to be considered when choosing a wall wart, as well as if you are going to try to use two or more nixies off of one camera, since those would increase the current as well.
and then you could just go and get an adapter for the proper voltage of the Nixie and be done with it.
Going to step-up 120v to 250-300v, huh? I doubt you can find one of those real cheap, if you could at all. I think you miss the ENTIRE point of the instructable.<br><br>

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