As electronics technicians, we may be asked to construct a circuit to a certain specification. For this lecture we will learn how to design a series circuit with certain specifications. We will use Ohm's Law to aid us in doing so.

Exercise 1: Design a series circuit with three resistors, where two of the resistors are 4kΩ. The total circuit current is 1mA, and the applied voltage is 12V.

First we must list the known values;

VT = 12V ...............R1= 4kΩ.................VR1=.......................IR1 = ....................PR1=

IT = 1mA..................R2= 4kΩ.................VR2=.......................IR2 = ....................PR2=

RT =........................ R3= .........................VR3=...................... IR3=...................... PR3=

PT =

So far we only have the values of VT, IT, R1, and R2. By using our knowledge of Ohm's Law and the Power Formulwe can find the unknown values.

Exercise 1: Design a series circuit with three resistors, where two of the resistors are 4kΩ. The total circuit current is 1mA, and the applied voltage is 12V.

First we must list the known values;

VT = 12V ...............R1= 4kΩ.................VR1=.......................IR1 = ....................PR1=

IT = 1mA..................R2= 4kΩ.................VR2=.......................IR2 = ....................PR2=

RT =........................ R3= .........................VR3=...................... IR3=...................... PR3=

PT =

So far we only have the values of VT, IT, R1, and R2. By using our knowledge of Ohm's Law and the Power Formulwe can find the unknown values.

Step 6 Diagram mistakes <br>Voltage at point A = 100V <br>Voltage at point B = 60V <br>Voltage at point C = 0V <br>

You are absolutely correct, good catch! <br> <br>Since the voltage flowing AFTER R1 (10kΩ) would only be a total of 100V. Therefore, <br>VR2 = (120*20)/60 = 40V <br> <br>THEN, Voltage at V2 after Voltage Drop is: <br>V2= V1-VR2 <br>V2= 100-40 <br>V2= 60V <br> <br>Correspondingly, the voltage flowing between R2 and R3 is 60V. Hence the equation must follow: <br> <br>VR3 = (120*30)/60 = 60V <br> <br>Then the voltage after passing through R3 (30kΩ) is: <br>V3 = V2 - VR3 <br>V3 = 60-60 <br>V3 = 0V

<p>I have 23 - 15 = 8 volts ? anybody else ?</p>

<p>Keep it up!</p>

<p>I thought current flows from negative to positive, not positive to negative....</p>

<p>hello sir</p><p>please post chapter four</p>

<p>very comprehensive. Thx</p>

thanks alot i'm a beginner.. waiting for chapter 4 :)

<p>thank you for your feedback.</p>

Once when you wright your set of the equations, you can calculate it online on: <br> <br>http://www.cirvirlab.com/simulation/kirch_2_real.php

geeks and company,<br><br>i have been busy with work and my car lately. my next chapter will cover parallel circuits. i should be able to publish it by the end of january.<br><br>kareen.

I have some complaints about the clip art I used and was asked to revise them to something related to electronics.<br><br>I think it is a reasonable request, so I shall work on finding relevant clipart for this chapter. I value all of your comments, questions and suggestions highly, and I take them all in consideration.<br><br>If you don't understand something and need further explanation, please don't be timid with your questions, i will try to answer them to the best of my knowledge.<br><br>Thanks, <br>Kareen

Ladies and gentlemen, I am done updating the images. You will find these images helpful in understanding the concepts introduce in this Chapter.<br><br>Thanks