FREE Hidden Electricity!





Introduction: FREE Hidden Electricity!

This Instructable will show you how to tap into a FREE source of electricity! All you need is a phone line! All phone lines have a constant flow of voltage, around 40-70 volts (up to 100 volts when it rings!), but you can't just plug stuff into it and expect it to work. You can really mess with your phone system by doing that. I discovered how to do it the right way!

Step 1: What You Need...

1. Small project enclosure
2. (1) 240ohm resistor
3. (1) 510ohm resistor
4. (1) LM317L Regulator
5. (1) KBP210 Bridge Rectifier
6. (2) Phone line cables

Step 2: The Schematic...

I connected the Positive end to one line of the female phone jack and the negative to the other. You could wire it directly to your light but I chose to do it this way so I could test other sources with just a phone jack interface cable. The Red and Green go to corresponding colors on the phone line that plugs into the wall.

Step 3: Final Steps...

Mount the circuit in the project box and run your wires through two small drilled holes. Be sure to tie knots in the wires inside the box to prevent them from pulling out.

Step 4: Interface Cable...

I made an interface cable from an old wall adapter and phone line to connect the light to the box.

Step 5: Test It Out!

After wiring the LED's in parallel, I plugged everything in and it worked great! It even powered off when the phone was picked up and flashed when it rang. While this won't power your new 60" HD Plasma TV, it will power small amperage electronics and could come in handy if the power goes out! Enjoy your FREE source of power.



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    Hello, Like the work you've done. But i would like to know how you wired up the working components after you realized the is no need for bridge retifier. Just wonder if you could post a skematic like you have done with the corrections you mentioned.

    Thank yo.


    If you do this don't be surprised if the phone company finds out about it. But I want to offer a couple corrections.

    First, don't use the KBP210 Bridge Rectifier. That's used to convert AC to DC but the voltage on the phone line is already DC so all it does is waste 1.4V of your power source (when current has to flow through diodes it burns up extra power). You can tell he has his multimeter set on DC voltage in the video, this verifies that's what's coming out of his wall jack. I guess it would save you if you accidentally connected the green and red wires backwards but just don't do that.

    Second, if you already have DC, figure out what voltage you need for your device and use the LM317L or another adjustable regulator. He has the resistor network connected incorrectly so refer to the datasheet from Texas Instruments. What you need to do is hook up the resistors so when you get your desired voltage on the Output pin, the Adj pin sees 1.25V. The way he shows it hooked up it looks like the circuit will just output 1.25V (the Adj pin draws so little current it's at effectively the same voltage as the output it's hooked to through a resistor). You need one resistor going from the output to the Adj pin, and one going from the Adj pin to your ground.

    Anyways, check your output with your multimeter before you hook it up to your valuable electronics.

    i found out that the phone line contains 50-60V dc and a 110Vrms sine superimposed on it so u will need a rectifier ic too .....

    i wonder why he isn't using filter capacitor? ???

    by the way nice hacking :)

    It makes no sense to me that the voltage would be DC. You can't transmit DC over very long distances.

    That's a very large misconception. In fact you'll find that for high power long distance transmissions DC is far more cost effective.

    Actually, for anything over more than a few metres, DC power transmission has massive losses. High voltage + low current = much less resistance.

    One if the main reasons cities went with AC was that DC system designs needed a power station almost every other block. Modern high-rise structures would need piwer stations part-way up the building.

    AC can be sent through a transformer, which will trade volts for amps. That's why power transmission is accomplished with AC. Your goal is to transmit power, that is, watts. (W=VxA) But the more amps you carry, the larger the wire you need.

    You can distribute power using high voltage (and low amps) requiring a smaller cross-section area wire for the same wattage. Then, near the point of use, the AC can be sent through a step-down transformer converting the power to low voltage (and high amps).


    Transmit 1,000V at 1A. This is 1,000 watts.

    1A requires a small wire.

    Near the point of use, convert the 1,000 watts with a transformer to 100V at 10A. This is still 1,000 watts.

    The wire near the point of use is a bigger one (one capable of carrying 10A), but it is only used for a short distance.

    (In reality there are line loses, but I ignored them for illustration.)

    The amusing thing is, I'm currently teaching this to one of my physics classes...

    kiteman, it is not amusing as you are teaching the wrong stuff to the physics class.

    Umm... I don't.

    That's why my classes tend to come out at the top in exams...