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How High can a fishtank air pump pump water?

video How High can a fishtank air pump pump water?

I have used an air pump for a fish tank to pump water fairly high but I am curious about how much higher you can pump.
If you have a suitable site and you are curious too, maybe you can answer the question.
16 comments
Mar 10, 2012. 1:14 PMpbates123 says:
I responded to you awhile back and had another thought. By the way sorry I saw the comment about this being a doing not thinking challenge although I have not tried this for what ever reason.

Have you or anyone ever tried cascading and using the same pump with a splitter to power the subsequent airlift section. It seems to me that using the numbers you show in your video 22inches of submergence with 13 feet is about 15% of the head total submergence.

I also saw the comment from Shascho re the Geyser pump but haven't found any real good schematics or video that really show how they go together.

Any way just a thought - has anyone improved on you numbers that you achieved?
Dec 23, 2011. 1:34 PMshascho says:
Great challenge.
Have you considered the Geyser pump?
It's the basis of an entire industry.
It allows the air to accumulate at the bottom of the pipe
and by additive increase of its force,
accelerate a smaller 'plug' faster and higher.

I've never seen one in operation,
but here is a good explanation.

http://www.airliftpump.com/index.htm

Keep up the good work, partners!
Sep 11, 2011. 11:33 AMjimbo13 says:
maybe try a check valve at the bottom to stop the air and water from going out the bottom but it lets water in.
Jul 6, 2011. 7:59 AMitsandbits1 says:
the part of the plug flow that you may be missing in your explanation is the airlift effect. If you take your 1 meter high water column and inject air plugs in equal amounts all the way up the column, you still have the same amount of water but the air is seperating it and you can end up with a lot higher column just because of thisbut the fact that there is a pressure differential between the air you put in and the ambient air will cause the higher pressure air in the system to keep pushing the plug of water higher and higher to get out and is supported on the bottom by the higher pressure air that keeps entering the system from below
Jul 11, 2011. 9:13 PMitsandbits1 says:
I managed to get 16ft with 24inch submergence using the small plastic drip irrigation hose. I actually had to go sideways a couple of places which made it more difficult because the water created air locks in the flat spots that had to be broken to keep the flow going but it managed with 35 feet of hose at very minimal flow and pressure.
Apr 9, 2011. 10:38 PMancienthart says:
A quick back-of-the-envelope calculation would consist of attaching a pressure gauge to the output of the pump and blocking the output off somehow.

Then (In Standard International Units) from the maximum pressure that the pump can exert,

p = rho g h

rho = density of water = 1000 kg/m^3
g = acceleration due to gravity = 9.8 m/s^2
p = pressure in Pascals
h = height of water column in metres.

The height will be a little less than this, due to pipe friction, but assuming that you're after only a little trickle at the end of the pipe, it should be pretty close.
Apr 11, 2011. 11:02 AMWalScrap says:
Theoretically, using formula given by ancienthart, that I agree on ;-)
it means that having water at ground level (p=10e5 Pascal), you can lift water with a pump that creates depression at a maximum of 10meters.

A good estimation of your pump pressure can be calculated following this.
Bernouilli's principle tells you that :
1/2mV^2 + mgz + P = Constant
which means fluid speed, elevation and pressure are kept along a circuit (forgetting about friction losses, compressible fluids hypothesis, ...)
Fluid Flow (mV) can be estimated counting the time required to fill a known container. (for ex. 4liter bottle is being filled in 30sec : mV=4/30=0.13 kg/sec)
V can be determined as you know m fluid mass (which is easy for water : 1L=1kg)
You can then determine your Constant in your Bernouilli formula.
Given the relevant hypothesis that you are not moving up or down, z in that Equation becomes 0, and therefore the constant gives you the P, which is the pressure at the exit of your pump, when speed is estimated to be zero.
I am using Bernouilli when Pressure is 0 and speed maximum, and Pressure maximum with speed V=0. Overall Energy (the Constant) is being kept.
Although I am not sure the pressure at pump exit will be the same as the pump entry, this can give you an idea.

Let me know if you attempted it...
Apr 12, 2011. 7:56 AMWalScrap says:
Introducing Bernouilli's principle was to estimate pump output pressure...

This 10 meter limit exists in the case your pump is higher than the water you want to pump. Theory tells you it is impossible to ''suck'' water from an altitude over 10m. If your pump is at water level, then your pump is pushing the water up, which is a different story.

The thing that I do not understand is that your 98 millibar pump should be able to ''push up'' water up to +-1 meter (using formula given by ancienheart). When you have this water column of 1 meter, the pressure it gives you at the bottom will be equivalent to the pressure of the pump (98 millibar in your case), and therefore, pump pressure would need to be higher to continue to push water. I do believe you but then I am lost with what I understood from the theory... I am probably missing something...

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