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Step 3Factoring binomials
Binomials are expressions with only two terms being added.
2x^2 - 4x is an example of a binomial. (You can say that a negative 4x is being added to 2x2.)
First, factor out the GCF, 2x. You're left with 2x (x - 2). This is as far as this binomial can go. Any binomial in the form 1x +/- n cannot be factored further.
When you have a binomial that is a variable with an even exponent, added to a negative number that has a square root that is a natural number, it's called a perfect square.
x^2 - 4 is an example of this. It can be expressed as the product of the square root of the variable plus the square root of the positive constant, and the square root of the variable minus the square root of the positive constant.
Huh?
Basically, take the square root of the variable. You'll end up with x. Then square root the 4. You'll end up with 2. If you add them together, you'll get x+2. Subtract them, and you'll get x-2. Multiply the two, and you'll get (x+4)(x-4). You've just factored a perfect square.
If you multiply (x+2)(x-2) together using FOIL, you'll end back up with x^2-4.
(FOIL: First Outer Inner Last, a way of multiplying two binomials together. Multiply the first terms of the binomials (x and x in this case), then the outer two (x and -2), then the inner two (2 and x), then the last terms (2 and -2), then add them all up. x^2 - 2x + 2x - 4 = x^2 - 4.)
This can be done again if one of the binomials is a perfect square, as in this instance:
x^4 - 16 = (x^2 + 4) (x^2 - 4) = (x^2 + 4) (x + 2) (x - 2).
This can be factored further if you bring in irrational numbers, see step [9].
How to factor binomials in the form of (x^3 + b^3):
Just plug into (a - b) (a^2 +ab + b^2). For example, (x^3 + 8) = (x - 2) (x^2 + 2x + 4).
How to factor binomials in the form of (x^3 - b^3):
Plug into (a + b) (a^2 - ab + b2). Note that the first two signs in the equation are switched.
(x^3 - 8) = (x + 2) (x^2 - 2x + 4).
Both examples can be factored further once you learn how to factor trinomials in step [4].
2x^2 - 4x is an example of a binomial. (You can say that a negative 4x is being added to 2x2.)
First, factor out the GCF, 2x. You're left with 2x (x - 2). This is as far as this binomial can go. Any binomial in the form 1x +/- n cannot be factored further.
When you have a binomial that is a variable with an even exponent, added to a negative number that has a square root that is a natural number, it's called a perfect square.
x^2 - 4 is an example of this. It can be expressed as the product of the square root of the variable plus the square root of the positive constant, and the square root of the variable minus the square root of the positive constant.
Huh?
Basically, take the square root of the variable. You'll end up with x. Then square root the 4. You'll end up with 2. If you add them together, you'll get x+2. Subtract them, and you'll get x-2. Multiply the two, and you'll get (x+4)(x-4). You've just factored a perfect square.
If you multiply (x+2)(x-2) together using FOIL, you'll end back up with x^2-4.
(FOIL: First Outer Inner Last, a way of multiplying two binomials together. Multiply the first terms of the binomials (x and x in this case), then the outer two (x and -2), then the inner two (2 and x), then the last terms (2 and -2), then add them all up. x^2 - 2x + 2x - 4 = x^2 - 4.)
This can be done again if one of the binomials is a perfect square, as in this instance:
x^4 - 16 = (x^2 + 4) (x^2 - 4) = (x^2 + 4) (x + 2) (x - 2).
This can be factored further if you bring in irrational numbers, see step [9].
How to factor binomials in the form of (x^3 + b^3):
Just plug into (a - b) (a^2 +ab + b^2). For example, (x^3 + 8) = (x - 2) (x^2 + 2x + 4).
How to factor binomials in the form of (x^3 - b^3):
Plug into (a + b) (a^2 - ab + b2). Note that the first two signs in the equation are switched.
(x^3 - 8) = (x + 2) (x^2 - 2x + 4).
Both examples can be factored further once you learn how to factor trinomials in step [4].
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Know how to "factor" Binomials:
Problem: -3x^2 + 7x
Answer: 0, 7/3
I thought the obvious answer is pulling out the x for the original binominal which would result in x (-3x+7)
Although I haven't seen this before, I could take each of the factors and have them equal 0 to come up with the answer. Am I missing something?
Example: x = 0 and -3x + 7 = 0
Solve for x, x = 0 and x = 7/3
Hope this explains it, if not, reply to me
Square root both of the terms in the function. You'll end up with 2v and 9t.
Then, plug it in to the set pattern, (x + y)(x - y).
(2v + 9t)(2v - 9t)