LED Cube Using 4020 Ic and 555 IC

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Introduction: LED Cube Using 4020 Ic and 555 IC

This circuit drives a 3x3x3 cube consisting of 27 white LEDs. The 4020 IC is a 14 stage binary counter and we have used 9 outputs. Each output drives 3 white LEDs in series and we have omitted a dropper resistor as the chip can only deliver a maximum of 15mA per output. The 4020 produces 512 different patterns before the sequence repeats and you have to build the project to see the effects it produces on the 3D cube.

in 4020 IC the reset pin should not be left free it must be connected to the ground with 100 nf capacitor.If it is not connected the IC will reset again  and  again there will be no output in the output pins.

The speed of the LEDs is controlled by a 10k variable resistance connected to the 555 IC
And the capacitor connected to the 555 IC is 22 uf .

http://www.youtube.com/watch?v=yvYjAe-EuiQ&feature=youtu.be

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15 Comments

where is the 3rd terminal 10k pot connected

It is being used as a variable resistor so only sweep arm and one fixed terminal are used

This is a blant copy from this website.

Even the text is just copied.

At this stage I assume it to be a fraudulent copy with no credit given to the original author as I don't think Colin Mitchell would use Ahimadu as a username...

It was a great little project.

hello I have a problem, I rode the original circuit but do not know what goes into the cube are to be switched on and off like a flip flop

someone help me?

thank you

check the connection. and check 10 k variable resistor...

its a live thank you very much

Hey can u say that in diagram the desired pin shown should correctly to that ic pin only or I can connect all anodes on different pin shown in diagram please reply quick waiting.....

sorry for late reply..

refer the new image ..