HOW TO LIGHT 40 LEDS WITH A DEAD 'AA BATTERY'.
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The working of the circuit is based on the legendry 'joule-thief' circuit.
Step 1: Materials Needed
Resistor 1 kilo ohms
A ferrite torroid (circular metal disc-like thing YOU CAN FIND THIS IN OLD CFL LAMPS)
Led's (i used 40 of them!!!)
a dead battery
Step 2: Start Winding the Torroid.
●STEP 1 - ( SEE THE IMAGES )Take your torroid and start winding it with a single round of copper coil or coated wire.
●STEP 2 - Twist the '2 ends' of the wire so that you don't get confused.
●STEP 3 - Again repeat the winding of the coil as in step 1
●STEP 4 - Twist the '2 ends' of the wire so that you don't get confused.
Your coil is ready.
REMOVE THE THIN COATING OR ENAMEL FROM THE COIL BY BURNING ITS ENDS OR SIMPLY RUBBING THEM WITH A SANDPAPER.
Step 3: CIRCUIT DIAGRAM
Step 4: Lets Begin With the Wiring.
Step 5: Wiring Connections
●STEP 1- Solder the base of the transistor to the 1 kilo-ohm resistor.
●STEP 2- Solder the other end of the resistor to any end of the the torroid
●STEP 3- ( AS IN THE CIRCUIT DIAGRAM ) Join the 2 different ends of the torroid together
and solder the possitive terminal of the dead battery to it.
●STEP 4- Solder the possitive terminal of the led to the collector of the transistor.
●STEP 5- Solder the negative terminal of the led to the emmiter of the transistor.
●STEP 6- Solder the left-out wire of the torroid coil to the emmiter of the transistor.
●STEP 7- Solder the negative terminal of the battery to the
collector of the transistor.
you have made the circuit.
Step 6: Now See the Circuit Play
Each led used above requires 3 volts
40 × 3 = 120 volts!!!
But i am only supplying 0.3 volts to it.
THE CIRCUIT MAKES 0.3 VOLTS INPUT DO A JOB REQUIRING 120 VOLTS!!!
Step 7: THIS CAN BE USEFUL IN CAMPING AND BIKE-LIGHTS AS IT USES DEAD BATTERIES.
Step 8: ALSO IT CAN POWER ALL YOUR HALLOWEEN STUFF TOO !!
HAVE A NICE DAY