**The Big Idea:**If you shot a bullet perfectly horizontally, and at the exact time that the bullet exited the end of the barrel you dropped another bullet from the same height, which bullet would hit the ground first? Answer: They would hit at the same time!

*I'll prove it...*

**Summary:**By the end of this instructable you will be able to teach your students the ins and outs of two-dimensional trajectory problems in a fun and engaging manner. This project allows a shooter to hit a falling stuffed toy every time without missing, like magic! Additionally, you will be able to explain

*why*this happens and your students will be able to solve all of the math themselves. You'll have to excuse the lack of set up pictures as I do not have a classroom available for the set up at this time.

**Educational Concepts:**

* Two-dimensional trajectory

* Basic equations of motion (position, velocity, and acceleration)

* Two body collisions

* Directional forces and acceleration

**Equipment Needed:**

This instructable is very versatile. I will present alternatives to my options as we go along. However, here are the materials I used:

1) 4 feet of 1/2 inch diameter PVC piping

2) 2x Chemistry ring stand

3) 2x Burette clamp

4) 1x C-cell battery holder (4 batteries)

5) 1x Marble

6) 1x Electromagnet --> See link on the circuit building page for the one I use.

7) 1x Stuffed toy (I use a stuffed monkey)

8) Spool of small gauge wire

Now before we start we must develop the physics and math behind our project...

## Step 1: Trajectory Theory

The math and the physics behind this project are fairly simple. First I will develop all the math and theory you need to know, in its most basic form, to teach this lesson (I'm assuming you know basic physics). Then I will go into some more complicated options for advanced students. I recommend briefly reading this section, viewing the rest of the instructable, and then returning to this page once you have a solid idea of what is happening in the experiment.

There are two bodies in motion in this project. The first is the bullet (the marble) and the second is the monkey (or other stuffed toy). A volunteer shooter stands on one side of the room and shoots the marble out of the end of the PVC tube like a spitball. On the other end of the room hangs a stuffed toy from an electromagnet. As the marble exits the end of the tube, it breaks a small wire contact. When the wire contact is broken, the electromagnet shuts off, dropping the toy. The marble will hit the falling toy every single time, no matter the speed of the ball bearing. Students are always amazed by this.

(Forgive me for the length of this explanation) In the 2D plane there are obviously 2 directions: the x and the y. Therefore, in order to accurately describe a body's position and motion in the plane, you must describe its x position, velocity, and acceleration, as well as its y position, velocity, and acceleration. Since this experiment does not occur when the bodies are in equilibrium, it will be necessary to also describe the body's position, velocity, and acceleration at different

If you are familiar with physics you should know the equations of motion (with constant linear acceleration):

Position: s(t) = s0 + v0*t + 1/2*a*t^2 , where s = position (x or y), v = velocity (x or y component), a = acceleration (x or y component)

Velocity: v(t) = v0 + a*t

acceleration: This will be either 0 for horizontal directions or the acceleration due to gravity in vertical directions.

We have two different bodies so we'll have to look at each one separately.

The marble's "initial state" will be the state it is in when it leaves the end of the barrel. Therefore, it will have only an x component of initial velocity. If we neglect air resistance and friction, it will not have an x component of accleration. So, our x-component of position for the marble looks like this: x(t) = x0 + v0*t. If you assign your coordinate system such that the initial x-position of the marble is zero (as in my figure), the equation is simply

Since we want to know the time and position the two bodies will collide, and since the monkey is dropping straight down (no change in x-position) that means we want to know the time at which the x-position of the marble is equal to the x-position of the monkey. You'll have to measure this distance when you set it up in your classroom. Let's say you measured it to be 25 feet and that the ball bearing is moving at 50 feet per second. This is what the equation would look like: 25 ft = 50 ft/s * t. Solve for t to get that the marble will be at the same x coordinate as the monkey at t = 0.5 seconds.

We now know when the marble will arrive and hit the monkey. But we need to find out where the two will be in vertical space when they collide. Take the y-position equation for the monkey: y(t) = y0 + v0*t + 1/2*a*t^2. Now in this case, y0 will be initial height that the monkey is hung at, it will not have an initial velocity, and it's acceleration is the acceleration due to gravity. So, the equation looks like this:

Ok, so we found out they will hit at t = 0.5 seconds so let's plug that in (assume the initial height of the monkey is 6 feet off the floor):

y(t) = 6 ft + 1/2 * (-32.2 ft/s^2) * (.5 sec)^2. Solving for the y-position we get y = 1.975 feet. Ta daaa! The bullet will hit the monkey after half a second and while they are 1.975 feet above the floor.

You can make this as complicated as you would like. Have the students derive the equations, or propose a scenario with non-constant accelerations and velocities (note: this no longer guarantees they will hit each other). If they know calculus, help them realize that the equations of motion are derivatives of each other.

**The Presentation:**There are two bodies in motion in this project. The first is the bullet (the marble) and the second is the monkey (or other stuffed toy). A volunteer shooter stands on one side of the room and shoots the marble out of the end of the PVC tube like a spitball. On the other end of the room hangs a stuffed toy from an electromagnet. As the marble exits the end of the tube, it breaks a small wire contact. When the wire contact is broken, the electromagnet shuts off, dropping the toy. The marble will hit the falling toy every single time, no matter the speed of the ball bearing. Students are always amazed by this.

**The Basic Theory:**(Forgive me for the length of this explanation) In the 2D plane there are obviously 2 directions: the x and the y. Therefore, in order to accurately describe a body's position and motion in the plane, you must describe its x position, velocity, and acceleration, as well as its y position, velocity, and acceleration. Since this experiment does not occur when the bodies are in equilibrium, it will be necessary to also describe the body's position, velocity, and acceleration at different

*times.*Don't worry, it's not that complicated just take it steady.**Equations of Motion:**If you are familiar with physics you should know the equations of motion (with constant linear acceleration):

Position: s(t) = s0 + v0*t + 1/2*a*t^2 , where s = position (x or y), v = velocity (x or y component), a = acceleration (x or y component)

Velocity: v(t) = v0 + a*t

acceleration: This will be either 0 for horizontal directions or the acceleration due to gravity in vertical directions.

**Using the Equations:**We have two different bodies so we'll have to look at each one separately.

*Body 1, the marble:*The marble's "initial state" will be the state it is in when it leaves the end of the barrel. Therefore, it will have only an x component of initial velocity. If we neglect air resistance and friction, it will not have an x component of accleration. So, our x-component of position for the marble looks like this: x(t) = x0 + v0*t. If you assign your coordinate system such that the initial x-position of the marble is zero (as in my figure), the equation is simply

**x(t) = v0*t.**You can use a photogate at the end of the barrel to get the bullet's exact velocity, or you can make it up for the sake of illustration.Since we want to know the time and position the two bodies will collide, and since the monkey is dropping straight down (no change in x-position) that means we want to know the time at which the x-position of the marble is equal to the x-position of the monkey. You'll have to measure this distance when you set it up in your classroom. Let's say you measured it to be 25 feet and that the ball bearing is moving at 50 feet per second. This is what the equation would look like: 25 ft = 50 ft/s * t. Solve for t to get that the marble will be at the same x coordinate as the monkey at t = 0.5 seconds.

*Body 2, the falling monkey:*We now know when the marble will arrive and hit the monkey. But we need to find out where the two will be in vertical space when they collide. Take the y-position equation for the monkey: y(t) = y0 + v0*t + 1/2*a*t^2. Now in this case, y0 will be initial height that the monkey is hung at, it will not have an initial velocity, and it's acceleration is the acceleration due to gravity. So, the equation looks like this:

**y(t) = y0 + 1/2*(-32.2 ft/s^2) * t^2. Note that if you did the y-position for the marble you would come up with the exact same equation. This means that they will always be at the same y-position!!!**Ok, so we found out they will hit at t = 0.5 seconds so let's plug that in (assume the initial height of the monkey is 6 feet off the floor):

y(t) = 6 ft + 1/2 * (-32.2 ft/s^2) * (.5 sec)^2. Solving for the y-position we get y = 1.975 feet. Ta daaa! The bullet will hit the monkey after half a second and while they are 1.975 feet above the floor.

**For the advanced students / educators:**You can make this as complicated as you would like. Have the students derive the equations, or propose a scenario with non-constant accelerations and velocities (note: this no longer guarantees they will hit each other). If they know calculus, help them realize that the equations of motion are derivatives of each other.

## Step 2: Set Up the Gun

1) Attach a small metal contact to one side of the barrel at the "exit" end. You can use drops of solder, a small metal plate, another wire, etc. Then attach a wire to this contact (notice in the picture I just use a loop in the opposite wire).

2) On the opposite side of the barrel, secure a piece of wire such that the end is stripped of the insulation and it is able to gently lay in contact with the metal from step 1. Realize that you can use any sort of electrical contact here as long as two things happen: first, it transmits electricity from one side of the barrel to the other and second,

3) Use the ring stands and the burette clamps to position the PVC tube horizontally on a table. You may need to use a level. Having the final position of the tube be around 6 feet off the ground is a good height for someone standing on a chair to blow in the end of the tube.

2) On the opposite side of the barrel, secure a piece of wire such that the end is stripped of the insulation and it is able to gently lay in contact with the metal from step 1. Realize that you can use any sort of electrical contact here as long as two things happen: first, it transmits electricity from one side of the barrel to the other and second,

**that it does not divert or inhibit the marble when it comes racing through the exit.**3) Use the ring stands and the burette clamps to position the PVC tube horizontally on a table. You may need to use a level. Having the final position of the tube be around 6 feet off the ground is a good height for someone standing on a chair to blow in the end of the tube.

## Step 3: Set Up the Rest of the Circuit

1) Take the opposite end of the bare wire that is laying across the end of the barrel and run it to the electromagnet.

2) Take the opposite end of the wire that is attached to the metal contact on the end of the barrel and run it to one side of the C-battery holder.

3) Run another wire from the opposite side of the C-battery holder to the electromagnet.

Your circuit is complete! You may have to play with switching the wires at the electromagnet of the battery holder if you find the electromagent is repelling instead of attracting.

Here is the link to the electromagnet I use:

http://www.google.com/products/catalog?q=electromagnet&hl=en&prmd=imvns&bav=on.2,or.r_gc.r_pw.,cf.osb&biw=1680&bih=935&um=1&ie=UTF-8&tbm=shop&cid=4524455083853831860&sa=X&ei=oS8fT4C9N4rv0gHT08AH&ved=0CK0BEPMCMAc

2) Take the opposite end of the wire that is attached to the metal contact on the end of the barrel and run it to one side of the C-battery holder.

3) Run another wire from the opposite side of the C-battery holder to the electromagnet.

Your circuit is complete! You may have to play with switching the wires at the electromagnet of the battery holder if you find the electromagent is repelling instead of attracting.

Here is the link to the electromagnet I use:

http://www.google.com/products/catalog?q=electromagnet&hl=en&prmd=imvns&bav=on.2,or.r_gc.r_pw.,cf.osb&biw=1680&bih=935&um=1&ie=UTF-8&tbm=shop&cid=4524455083853831860&sa=X&ei=oS8fT4C9N4rv0gHT08AH&ved=0CK0BEPMCMAc

## Step 4: Set Up the Target and FIRE!

1) Hang the portion of the electromagnet from which wires are running to the ceiling.

2) Attach the other portion of the electromagent to the target. You can use hot glue, sew it, staple it, any way you wish.

3) Make sure when the target is hanging from the electromagnet that the spot you want to hit on it is perfectly level with the end of the barrel on the opposite side of the room.

That's it! Now when the marble exits the barrel, it will break the electrical contact, thus shutting off the electromagnet and dropping the target. The two will collide everytime and your students should now be able to explain why!

(Again, sorry I couldn't set this up and demonstrate it at this time but I hope you get the picture!)

Enjoy!

2) Attach the other portion of the electromagent to the target. You can use hot glue, sew it, staple it, any way you wish.

3) Make sure when the target is hanging from the electromagnet that the spot you want to hit on it is perfectly level with the end of the barrel on the opposite side of the room.

That's it! Now when the marble exits the barrel, it will break the electrical contact, thus shutting off the electromagnet and dropping the target. The two will collide everytime and your students should now be able to explain why!

(Again, sorry I couldn't set this up and demonstrate it at this time but I hope you get the picture!)

Enjoy!

It is a good idea Thank's )

Fantastic project. As an Aerospace Education officer in a Civil Air Patrol Composite Squadron, I plan on using this project in some of my classes! Keep up the good work!