Introduction: Paper Transistor Hack

Working principal
• As we know the resistance across the paper transistor when we power the circuit by DC voltage to the paper circuit the LED gets positive supply from battery directly and negative supply via paper transistor from emitter to collector and ultimately LED switch ON immediately
• When we connect an positive end to an base terminal the positive potential at the base is much higher than the negative so the negative supply is interrupted and LED will switch OFF
• The only difference between real transistor and paper transistor is it normally ON
• When applying base trigger it goes OFF

https://www.youtube.com/watch?v=EtKarQ8ivDc

Comments

MichaelM5100 (author)2016-04-08

Tested it with 5V using the computer USB hub, result (with 5V), not good.

tyu123456789 (author)2013-12-30

i'll try it!

WacoRadioWeirdo (author)2013-08-15

theres nothing to see with yr video, if only it was that simple to make a transistor , the trick would be known and used since a long time :/

karthick robo (author)2013-08-14

see the video link pls

rickharris (author)2013-08-13

A transistor in the manner in which you are using it acts as a switch - The LED would be OFF until the base was connected when current would flow through the transistor to light the LED.

As your connecting the positive to the base then your suggesting this is acting as an NPN junction.

Just to prove the point connecting the base to the emitter will turn a transistor OFF.

Try this, because in your case it won't make any difference the LED will remain ON and may even get slightly brighter.

efahrenholz (author)2013-08-13

I'm afraid your transistor is nothing more than a short to ground. This is not how a transistor functions, and what you are illustrating is an illusion of a transistor working, but this is not what occurs in a PNP transistor.

domints (author)2013-08-13

Lol it doesn't even use same effect as transistor. You just use this your 'base' is closer to the led than 'emmiter', and when you connect positive to 'base' and negative to 'emmiter' you make voltage divider, and you then don't have negative on led, but just 50 - 60% of positive. And in this circumstances led cannot work.

efahrenholz (author)domints2013-08-13

This is just a short to ground. It bypasses the LED because the direct short to ground poses the least amount of resistance.

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