Introduction: Quadratic Equation Solver in C
A quadratic equation is 2nd order polynomial equation that comprises of one variable.
Here is the form of a quadratic equation: ax^2 + bx + c = 0
Note: a, b, c are constants.
It is crucial to note that the coefficient a cannot equal to zero, because a quadratic equation is a 2nd order polynomial. Finding the solutions of a quadratic can be achieved by completing the squares. Also, the solutions of a quadratic equation can either be real or complex. The attached figure shows the quadratic formula and the formulas needed to find its roots (solutions).
We only need a computer and a compiler.
Recommended free compilers:
For Mac: Xcode
For Windows: Microsoft Visual Studio
Step 1: The Code & Testing Various Scenarios
The code is pasted below, and its original file is attached above. Also, the attached figures show the results of various scenarios.
// Copyright © 2016 Talal. All rights reserved.
// this library must be included in order to use built in mathematical functions
//remind the user of the quadratic equation format
printf("Quadratic Equation format: aX^2 + bX + c \n");
// declare inputs and outputs and their types
float a, b, c, determinant, x1, x2, realSolution, imaginarySolution;
// take the inputs from the user
printf("Enter the coefficients a, b, c respectively seperated by a comma \n");
scanf("%f, %f, %f", &a, &b, &c);
if (a == 0)
printf("This is not a quadratic equation \n");
// calculate the determinant to determine the number and the type of the solutions
determinant = ((b*b) - (4 * a* c));
printf(" Determinant = %f \n", determinant);
if (determinant == 0)
// if the determinant is zero, then there will be one solution
x1 = x2 = (-b)/(2*a);
printf("One real solution and it is %0.1f \n", x1);
else if (determinant > 0)
x1 = ((-b) + sqrtf(determinant))/(2*a);
x2 = ((-b) - sqrtf(determinant))/(2*a);
printf("Two distinct real solutions and they are %0.1f, and %0.1f \n", x1, x2);
// finally, if the determinant is negative, then the solutions will contain an imaginary part
realSolution = -b /(2*a);
imaginarySolution = sqrtf(-determinant)/(2*a);
printf(" Complex Solutions, and they are %0.1f + %0.1fi and %0.1f - %0.1fi \n", realSolution, imaginarySolution, realSolution, imaginarySolution);
Step 2: Conclusion
YOU MADE IT!
We have successfully written the C code to solve any quadratic equation.
Please feel free to post any questions regarding this instructable in the comments section below.
Also, here are the links to some of my other instructables:
Feel free to check them out.
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