Introduction: Single LED on 230V


A interesting montage is driving a led with main supply 240V.

Be careful because the LED powered at main supply 230V/50Hz

Here is a simplest LED AC mains Circuit

Step 1: Base Schematic

Schematic has few pieces:

we will use only 4 components:

1. 100nf Capacitor

2. 1K ohm Resistor

3. LED's * 2

4. 1N4004 diode.

Step 2: Practical Steps


3366carlos made it!(author)2017-03-05

the resistor and capacitor are for keeping the LED on when the voltage swings low? And the diode to protect the LED? Thanks

Omnivent made it!(author)2017-01-31

H Erici,

While I don't quite agree on the component selection (or the overall circuit), there's a couple of your statements which are a bit out of synch with present day reality and since the circuit is potentially lethal (like all stuff running on mains), here's a bit of updating...

First of all, there MUST be a fuse in the circuit!

The dropper capacitor MUST be an X-class (or X2-class) self-healing cap.

Current days 0.25W resistors are usually from around 350V max. working voltage (check datasheet for the specific resistor in hand), with tolerated over-voltages of around 500V and with short term intermittent over-voltages to 750V. It has long been good practice to use 2 resistors of half the value (in series) on 230VAC (a few decades ago, normal working voltage for 0.25W resistors was only 200V).

Please read up on AC theory before a statement like "3.45Wh * 24h * 365day, or 30.2kWh." - a capacitive dropper consumes only negligible amounts of power, due to the phase difference between voltage and current, so the power is taken by the LED and the resistor (which really should be of a much lower value to save power) almost exclusively. That is the sole reason to use a capacitive dropper in the first place.

The thundering lack of a bleeder over the cap is a definitive no-no and I hope that only people well trained in some form of electric trade will attempt this build.

Danger aside... Have a nice day :)

About This Instructable




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