Step 3Mount the LEDs and the resistors on the CD
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subtract from the 53v source
divide with the LED current , most LEDs have 20mA so it is .02 A
so
R=(V1-V2)/.02A
but i connected all the led in series
but the pro is i get a notice on my pc
power serge on usb ...
whts to do with tht ??
So : 7 LEDs 20 mA each, 3.5 V each to run, 5 V usb max.
R = (5 - 3.5) / (0.02 * 7) = 10.71 Ohms near value = 12 Ohms. Which is far away from 68 Ohms resistor.
Can you give me your trick? :)
Have a great day! :)
I'll quote from The Electronics Club:
Connecting several LEDs in parallel with just one resistor shared between them is generally not a good idea.
If the LEDs require slightly different voltages only the lowest voltage LED will light and it may be destroyed by the larger current flowing through it. Although identical LEDs can be successfully connected in parallel with one resistor this rarely offers any useful benefit because resistors are very cheap and the current used is the same as connecting the LEDs individually.
thank you!
CYa!
Its NOT a generally accepted rule. Its a waste of parts, and there's no logical justification for it.
I will say that as a design rule, simpler is better.
Here's a link that discusses LED wiring more fully and accurately than the Electronics Club.
From circuitry 101:
http://www.theledlight.com/ledcircuits.html