Yesterday, I was post an instructable about DC current limiter. Today, I'll post about short circuit protector with current limiter.

I'm about to make a heavy duty lab bench power supply for my project. It's can provide up to 108W and it is really, really bad if I accidently short it out. The circuit must be simple, effective, fast respond to the short and reliable. The circuit also must work at low output voltage.

At first, I use a relay to cut off the current the it shorted. It's simple and effective but slow respond and only operate at pretty high voltage. Later on, I think up a perfect circuit

Step 1: Understand the Circuit

Right at first, I know that I need 2 things in this circuit: it must have reset button (to cut off the current until the short is fixed) and to do it i will need a logic gate

To easy to understand, I'll call the (out) positive is A, negative is B, High means 2,7v to 5v, Low means 0,7 or lower

The logic gate need to cut off the current when it short but also act normal when no short happen. It's mean when A reach Vcc (High) and B is ground (Low), the output is High. When shorted, A=B=Low, the output also be Low. From this basic state, I choose OR logic gate IC for this circuit (see in image). In future, I'll make a power supply with multi output voltage so I'll need multi OR gate IC. Then I choose 74HC32 IC

How can the current stay off after shorted? Without reset button, the current stay shorted until no current pass through or it is un-shorted. But how and where to place this button? Obviously a simple button can't help anything at all. I need another IC, the PC817 or PIC817 opto-coupler

The opto-coupler is used to isolate 2 different voltage stage, use one to control another and this is what I want. Using OR gate, reset button and opto-coupler, I made this circuit

Step 2: How It's Operating?

At the begining, the power is turned on but no current pass through because the LED in the opto-coupler haven't lighted up

When reset button is pressed down, the cureent start to flow from the battery to output voltage. This voltage make 5v regulator work, create 5v source for OR gate IC to operate, also feed 5v to input terminal (High), make output sate is High. High output voltage make the opto-coupler start to conduct, current can pass from collector to emitter. The transistor is added to drive higher current. After release button, the current can pass through opto-isolator to output voltage. Note: the image in previous step using voltage divider to feed input terminal; you can use voltage divider for feedback voltage if voltage source is 10v or lower

When current accidently shorted, the output voltage is zero, the voltage regulator moake output is Low, feed into logic IC and make output is Low. Low output make opto-isolator stop conducting, cureent stop flowing from source voltage. The logic IC respond to the short in 6 ns. It will save your life and the circuit that you applying current

After the short is cleared, press the reset button to reset the circuit.

Step 3: Some Word for You

The logic IC need 5v to operate (5v is max) so i recommend using a voltage regulator. You still able to use voltage divider to feed its input terminal. This circuit should be built inside the power supply. You can add a toggle switch as below circuit to drive the output at maximum current (use a 220ohm to avoid burn out the LED inside)

My instructable is ended. Hope it's helpful for you (I think it really helpful). Comment what you think bellow.

This instructable was inspired by Julian Illet's video about his invention: DCOI logic.

<p>Thank you.</p>
<p>And the list of components?</p>
<p>You could see the hint in the instruction. They are 74HC32 IC, PC817, a push button switch and a power transistor</p>

About This Instructable




Bio: I am thankful for all of those who don't do anything at all. It’s because of them I do it myself. And I ... More »
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