I love this instructable. How do I figure out how much power my LED's will need? I want to do four times the amount you have here... Could I just repeat the LED corn rows a few more times before I run it to the 12v ? (That idea doesn't seem right some how...)
I'll assume you're using the same kind of LEDs and resistors that are specified then for every veroboard you've got 84 LEDs in bundles of three connected in parallel. Thus for every bundle you've got a forward current of:
I_f = (12V - 3x3.4V)/75ohm = 1.8/75 =24mA
So one veroboard, with 84 LEDs, will draw a current of
I_vero = (84/3)x24mA = 672mA
So if I've understood you correctly you wish to have 8 veroboards of UV LEDs then after you've connected them in parallel the total power drawn from the source would become:
P_total = 12Vx(8x672mA) = 12Vx5.375mA = 64.5W
So you'd need a 12V 65+W power supply, though to be on the safe side I'd personally use a 75W. Though as I said, you might be using LEDs with a different forward voltage so here's a formula where V_f is the forward voltage of your diodes:
You're welcome, and I hope it works out for you :D. Though as with all such things, take care that everything is unplugged when you're working on it. 5 amperes are quite the punch if they ever decide you're the path of least resistance.
Just out of curiosity, what kind of setup needs that big an exposure surface?
The box I have is big and I want to be able to make stencils for screen printing, as well as other things like guitar amps and synthesizers in the future... :) oh summer!
I'll assume you're using the same kind of LEDs and resistors that are specified then for every veroboard you've got 84 LEDs in bundles of three connected in parallel. Thus for every bundle you've got a forward current of:
I_f = (12V - 3x3.4V)/75ohm = 1.8/75 =24mA
So one veroboard, with 84 LEDs, will draw a current of
I_vero = (84/3)x24mA = 672mA
So if I've understood you correctly you wish to have 8 veroboards of UV LEDs then after you've connected them in parallel the total power drawn from the source would become:
P_total = 12Vx(8x672mA) = 12Vx5.375mA = 64.5W
So you'd need a 12V 65+W power supply, though to be on the safe side I'd personally use a 75W. Though as I said, you might be using LEDs with a different forward voltage so here's a formula where V_f is the forward voltage of your diodes:
P_total = 2304(4-V_f)/25 W
Just out of curiosity, what kind of setup needs that big an exposure surface?