This TV-B-Gone uses a 9V battery to send its signal through a matrix of 20 IR LEDS. This extends the working range of the device to about 90ft (line of sight). Using this in a regular sized room you are pretty much guaranteed to kill the TV no matter where you point it.

Step 1: Get the Stuff

You wont need much to build this, here is a list of the materials:
1 2N3904 Transistor (experiment with what you have around, it will probably work)
1 9V battery
1 9V battery holder
20 IR LED's

As far as tools go here is what I used:
soldering Iron + solder
desoldering pump
hobby knife
wire cutters/strippers

If you dont have the TV-B-Gone already you can get one at the Make Store: http://makezine.com/store/

Step 2: Modify the TV-B-Gone

Take apart the TV-B-Gone and examine the board, you will notice it uses two sets of batteries. The two 3V batteries on top drive the LED's and the bottom 3V battery powers everything else. To save a little space we moved the 3V battery to the top holder and connected the stuff that was connected to the 6V supply to the 9V battery.

To get rid of the lower battery holder you have to use a sharp cutting tool to break the connection on the right side of the top battery holder. Then on the left side solder a wire from the big pad through the hole that is right next to it. Now you can remove the lower battery holder and move the bigger 3v battery to the top holder.

Step 3: Add Wires

Remove the IR LED that is on the TV-B-Gone and replace it with a pair of wires. Then solder wires for gnd and +9V in the two places shown in the photos below.

Step 4: Make the LED Array

Start with two LED's and decide which direction you will stitch. Bend the inside lead towards the second LED and solder it then repeat until you have a string of four LED's. Then repeat the entire process five times.

Now bend the leads of one set to the side and attach another set between the two bent leads. Repeat this until you have filled out the entire grid.

Note: Always check the polarity of the LED's you are soldering. This configuration creates five parallel blocks of four LED's in series.

Step 5: Complete the circuit

If you are looking at the flat side of a 2N3904 with the pins down the pins are called Emitter, Base, and Collector from left to right. Attach the Collector and the LED- connection from the TV-B-Gone PCB to the negative side of the LED array. Then connect the Base to the LED+ wire. Next connect the emitter to ground on the circuit board.

Now wire the positive side of the LED array to the 9V supply. Finally connect the ground and 9V wires from the PCB to the 9v Battery clip. Attach the LED array and PCB to the battery clip. You can use anything from around, duct tape will work nicely. I had some double stick foam so I used that. The End.
This project was featured in <a rel="nofollow" href="http://www.instructables.com/forum/Top-5-April-Fools-Day-Pranks-You-Can-Build-in-the/">Popular Mechanics Top 5 April Fools' Day Pranks!</a><br/>
My tv b gone is different but I went ahead and tried to mod it. I get nothing out of it. I am clueless. Can someone brainy, please, have a look and tell me what I've done wrong? This is only my second soldering project. The chip is the SE02 500 A3A3 if that is any help.<br>
<p>I see what you did wrong... you have connected one of the wires to the wrong spot (to battery) so the red and yellow wires. You need to move the wire that connected to the battery to the hole that's in Step: 5 picture 3</p>
I thank you for taking the time to reply. I had a look around but it has been so long since I posted this that I cant find the project in my pile of stuff.
<p>Hello, I have the same model. How can I fix it? </p>
Sorry, but I have several questions because I think my tv-b-gone is different. Do you not have the 100mf capacitor? Your 1st photo in step 3 shows you without one. Did you remove it? Both of my coin cells are 3v? Do you really have a 6V coin cell? In step 2, pic 3- It says "break connection here" but I really don't see anything at the box, on the pcb to break. Did you mean to break the connection to the pcb and the coin cell batter at this connection. In step 2, pic4, what does this accomplish. Is this suppose to short the circuit, because when I do this, my red LED turns on? Is your led always on? I see that a blue led is "on" in several of your pictures.
<p>Hi you have either the gen 4 or gen 6 model... i have the same problem aswell. I really hope someone can make a tutorial about doing this with a gen 4 or 6</p>
no for the 6v coin cell. it means only the two of them combined.
<p>What kind of wires should you use?<br></p>
Would these LEDs work? If so, this would be very cheap. http://www.taydaelectronics.com/sensors-transducer/optical-sensor/infrared-led-940nm-5mm-tsal7400.html
Hi, <br><br>Perhaps my TV B Gone unit is different but as standard the IR LED positive terminal is connected to the positive of the battery and it appears to be the negative side of the IR LED that is switched to turn it on and off.<br><br>If as you suggest the positive side of the IR LED is connected to the base of a 2N3904 (npn transisotor) with the emitter connected to 0V there willl be 9V across the base-emitter junction. It will therefore be on all the time or at least until it blows which shoudn't take long as a typical npn can only support about 0.7V (one diode drop) across the base-emitter.<br><br>Am I missing something??<br><br>Dave.
Hey Dave, I think your tv-b-gone is different than the on described here. Maybe you can use an PNP transistor instead of the NPN described in the instructable. <br> <br>Jordy.
because infrared light is picked up by digital cameras, would this work as a night vision light?
You dont even need the tv be gone! Just search up infra red night light, or some such :) <br> <br>what you do is that you make a ring of thes irleds in a ring around the camera
it would probably blink though
not if you just connect it to 3 volts, i have done it and it dosn't blink
Um Does This Destroy Ur Tv So It Wont Work Again?
You only capitalize the first word in a sentence.
My question is why the hell someone Would Take The Time To Press The Shift Button For Every Single Word.<br>My pinky is tired.
derin, This Is Not Craigslist, No Spelling Or Grammar Nazis Allowed Here,
no .....silly, it just sends a signal (just like a regular remote) telling the tv to turn off.
it has a program that has all the tv remotes "off" pattern. Each tv is different ( different modle) and has a special inferad signal which turns it off. The tv-be-gone knows and plays one by one, so it may take a few seconds for the tv to turn off.
no it wont...it just sends some sort of signal (not sure) that turns the tv off...it doesn't kill it
so im trying to find someone legit can i make it with a ir detector and emitter or do i have to get something diffrent<br>
Do you think its possible to build your own TV?
someone said their dad made one. don't remember who, but it would not be a project for people with limited supplies equipment or tools.
ok...next step is to gather over 9000 ir leds and do this. lets turn off the tv's in a town....
Ok i have the tv b gone from thinkgeek that i got on march 22 i opened mine and it has a couple extra things and don't know if this is compatible with the one i have or if you can make one for the newer tv b gone it would be very appreciated.
here are some pics of the tv b gone i have so u can tell me if this mod will work on it.
I also would like to know the answer to your question. This is the gen 4 TV-B-Gone. I have made the IR LED array. From what I understand the bottom battery powers the micro controller so I am leaving that in place. The thing that stumps me is the capacitor. So being the curious person I am, I will eventually just solder the negative wire from the 9v battery pack to the negative side of the capacitor pad. The positive to the pad of the existing battery case just below the capacitor. At this point I imagine you all can guess I really don't have a clue what I am doing. Please correct me. Then I will house it all inside of a tic tac 100 plastic box. Like it says on the packet 'Refreshing little lifts'.
get an old video camera with night vision and turn it on then point it at the tv b gone with night vision on and see what happens, it is cool
I love huge matrices of LEDs and I cannot lie.
good work
&nbsp;lol, why bother with 20 little IR LED's when you can buy 3W star LED's? :D<br /> <br /> I built a TV-B-Gone using an Arduino and 6 3W IR star LED's with lenses. I could turn off TV's from down the street if they happened to have their windows open :D<br />
<br> LOL classic.....<br> <br> Drive by TV shootings......<br>
Could you please tell me how you did it?? Seems really interesting.. A circuit diagram and the necessary components would also be of much help..<br /> Whats a 'Star LED' btw?<br />
The 3W IR LED's &quot;things&quot; is talking about pump out a tremendous amount of Infra Red light. Since the 3W's take up more space all you have to do is accommodate space on your bread board or circuit board.<br> <br> And of course you can always ask Google for more info on the 3W IR LED's<br> <br> CE<br>
LEDs in parallel is no good - they never get exactly the same current each. one might get some more current, maybe too much -> it'll die, and in chain reaction the others will die, too
Yea, it isn't the best electronic design. Given that most that do build it won't have a multi-year device, I still think this is a great hack. Normally, putting a resistor at the end of each 'string' of LEDs to keep the current in check is the 'right' way, then you can run the 'strings' in parallel. That way if one 'string' dies, it all won't come tumbling down.
the design eliminates the need for a limiting resistor by putting groups of four LEDs in series. these groups are then connected in parallel. connecting the LEDs in series effectively adds their resistance in series with the other three LEDs in that group. so in effect, they do have the protection of a limiting resistor.
this will work, but it's not true. except you use an high accurate voltage supply ;) 1mV more or less for a diode will cause many mA more or less current. that is what diodes for and LEDs are diodes <sup></sup><br/>
i'm sorry, but this post makes absolutely no sense.<br/>first of all: &quot;this will work, but it's not true.&quot; what does that mean?<br/>second, i have no idea what you are trying to say diodes are for, so i'll tell you. they are mainly used to allow current in one direction and not the other.<br/>as for the 1mV thing, i'm not sure what you're trying to say here either. but i am aware that diodes follow ohm's law.<br/><br/>infrared LEDs typically have at least 1.2V required to forward bias. so by putting four of them in series: 1.2 x 4 = 4.8V your voltage drop is around 4.8V. a 9volt battery minus 4.8V = 4.2V. so the LEDs are seeing 4.2V each. <br/>i've measured the internal resistance of two IR LEDs. one had 81ohms, the other had 82ohms. lets even play it safe and say they are only 50 ohms each. 4.2V going in to four 50ohm LEDs in series = 21mA. that's low enough right there. but when you consider that they were closer to 80ohms, you get only 13mA. <br/><br/>in short, you are in absolutely no danger of melting an LED if you follow the instructions that m_jake gives for this project. <br/><br/>as a side note, <em>IR</em> LEDs have the lowest internal resistance. as you move up in hertz, you get higher forward bias, and higher internal resistance. so blue LEDs are the highest. (i've never seen a purple LED.)<br/><br/>have fun<br/>
i have bought a few purple and pink LED's . red seems to be the strongest current hungry roundup of LED ( i'm refering to those transparents glass on top ones ) Purple seems to be on par with Green , Red &amp; blue two colour LED's aren't really current hungry , but it is power hungry when it switches colours ( as my name implies , i'm really not having much knowledge about diodes , etc. ) that's all i know ( I'm a grade 10 singaporean )
p.s.<br/>when i say internal resistance i'm including effective resistance as a result of voltage drop. i found it by connecting them to a 4.94V source in series with a 219ohm resistor. current was 16.44mA and 16.41mA.<br/><br/>4.94V / 16.44mA = 300.5ohms.<br/>300.5ohms - 219ohms = 81.5ohms<br/>
I tried to say, that the diode-resistance is not linear. so you can NOT use Ohm's law for them you can't say "50ohm LED"
there it is
i measured my LEDs at 4.94V. so the 4.2 or so that these see will cause them to have an even higher resistance than i measured. meaning they will have to sink less current. all the better.
no it won't. all branches always get the same amount of current (ignoring manufacturing imperfections). besides, even if they did get more current, it wouldn't damage them (see my reply to servant74).
&nbsp;I would love to have an ULTIMATE tv b gone!&nbsp;How can I buy one?
you could use this to cheat with the havoc heli battle set.

About This Instructable


326 favorites


More by m_jake: Ultra TV-B-Gone Tv-B-Gone Hat Wire Dispenser
Add instructable to: