# Using a clinometer to measure height

In this Instructable, I'll show you how to use a clinometer to measure the height of a tall object (for help constructing your own clinometer from basic classroom materials, click here).

What you will need;

Clinometer
Tape measure
Paper
Pen or pencil
Assistant
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## Step 1: Pick a spot

Pick a spot to measure your object (I measured a telephone pole).  You should be far enough away from your object that you can see the top of it, and you need to be on level ground with the base of the object.  I like to set something down by my feet once I've picked my spot, so that I can easily come back to it.

## Step 2: Measure angle

Here's where we bust out our handy clinometer.  Look through the straw of your clinometer at the top of the light pole (or whatever object you're measuring).  The weighted string should hang down freely, crossing the protractor portion of the clinometer.  Read the angle shown, and subtract from 90° to find your angle of vision from your eye to the top of the pole (it can be helpful here to have an assistant to read the measurement while you look through the straw).  Record your results on your paper.

From my spot, my clinometer (read by my assistant) showed 55°.  Subtracting from 90°, that indicated that I looked at an angle of 35° to the top of the telephone pole.

## Step 3: Measure distance

Once you have your angle of vision, use your tape measure to find the distance from the spot you're standing to the base of the object you're measuring (an assistant comes in handy here, too).  We must know how far away you are to accurately calculate the height.

My spot was 15.6 meters from the base of the telephone pole I measured.

## Step 4: Find your eye-height

My eye height was recorded for this example as 1.64 meters.
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use pithogres thrim a2+b2

shantilasya3 months ago

Fantastic! Thanks a lot!

hspangler97044 months ago

I used this in class with my students it worked great!

DemolisionWolf1 year ago
Great instructable. im glad to see this tool on the site.
People have been mentioning the BSA method, which is fine, but the accuracy compared to a protractor and tape measure will be much less. And if you don't need accuracy, why even use the stick, just eye-ball it. (My two cents)
brojer1 year ago
BSA handbook has an easier method that doesn't require an assistant or math or a protractor. Just cut a stick at eye level push stick into ground and lie down with feet against stick. When top of object is level with top of stick, mark where you eye is and measure to base of the tall object.
1 year ago
Ok great, make an instructable.
clazman1 year ago
(removed by author or community request)
1 year ago
There is a little mistake in your logic , formula
4. must be H=P(sin phi)
5. mus be X=P(cos phi )

try it with a value phi = 85 and you will see when you trace it on scale
w9vhe1 year ago
Shows how long it's been since I used any algebra on purpose, but how did you get the 35 degrees for the angle?
T_TX1 year ago
I'm not seeing where you used the eye height in your calculations. Did I miss something?
dmuldoonlla (author)  T_TX1 year ago
We added the eye-height to the height (x) we found in the Tangent calculation to get the final height.
dmuldoonlla (author)  dmuldoonlla1 year ago
Check out step 8.
1943casey1 year ago
If you are in Britain, the clinometer shown here is called a protractor available at most stationers, this method only works on level ground, more maths if your on a slope
dmuldoonlla (author)  1943casey1 year ago
The green plastic protractor is the main piece of equipment here, but clinometer is the name we used for the entire device when assembled (made up of protractor, straw, string, and weight).
mwacuff1 year ago
A few years ago (taking a Trig review course at the time) I did something similar. My approach was more expensive than yours; my goal was best possible accuracy.

Coincidentally, I measured a telephone pole too.

Rather than making eye-level measurements, I made ground-level measurements, and measured the angle of elevation at night (since I was using a laser pointer for aiming).

The attached photo shows a level with integrated laser pointer, and a 360-degree protractor.
windbag1 year ago
What if it is a very distant object (radio tower on a hill)? How would you get the horizontal distance and thus complete the calculation for its height?
How would one go about doing this without a calculator?
1 year ago
To do this without a calculator, it'd be handy to remember that a 45º right triangle has equal sides, and a 30-60-90 triangle has a 1:2 relationship between the sides opposite the 30º and the 60ºangles.

1) Focus on a point on the object (let's call it point A) and walk back from the object until the inclinometer reads 45º.  The horizontal distance from the point on the ground directly under Point A to where you are standing, PLUS the height of your eye-level (because that's where the inclinometer is measuring 45º from) is the height of the point you are measuring.

2) Do the same thing, but at 30º, multiply the ground distance by 2 and at 60º divide the ground distance by 2.  (Add the "eye level height" BEFORE you multiply/divide)
1 year ago
I miss the EDIT function... the 30-60-90 part is incorrect.
dmuldoonlla (author)  jongscx1 year ago
You're right about the 45º triangle, but the 1:2 relationship in the 30-60-90 triangle is between the short leg and the hypotenuse. To use that triangle, you would have to multiply the ground distance at 60º by sqrt(3), and divide by sqrt(3) at 30º, neither of which is easy without a calculator.
1 year ago
dmuldoonlla's sketch of the 60 30 right angled triangle should show the root3 on the hypotenuse. Root 3 is 1.732
On 45 degree triangle it works out at root 2 which is 1.414.
So, soon as you see a 45 triangle you know instantly that the hypotenuse is 1.414 (whatever units you are using) long
same with a 60 - 30 being 1.732 units long.
Ratio of sides....had it drilled into us in technical college, can't seem to forget it now.
dmuldoonlla (author)  Jugfet1 year ago
I'm afraid you're incorrect. The sqrt(3) term is on the long leg, not the hypotenuse (I'm a geometry teacher, I go through this every year)

http://mathworld.wolfram.com/30-60-90Triangle.html

http://en.wikipedia.org/wiki/Special_right_triangles

.
dmuldoonlla (author)  dmuldoonlla1 year ago
If you're interested to see why the hypotenuse is 2* the short leg, begin with an equilateral triangle (all three sides the same). If you then cut this triangle in half vertically and look at just one half, you will have a 30-60-90 triangle, in which the hypotenuse (one of the original sides) is twice as big as the short leg (half of one of the original sides).
1 year ago
Yep, you're correct. I got that and the 3-4-5 triangle confused... 45-45-90 it is.
1 year ago
The trigonometric functions (like any other function) can be drawn and measured physically with a ruler. If you draw a line at ßº in a circunference of radius=1, the segment that is tangent to the circle in the x axis and reaches that line is the tangent function (green). The bigger you draw the circle the more accurate result you will get.
KROKKENOSTER1 year ago
Very interesting now to get Pythagoras straight in my brain after half an cetury
ElectroFrank1 year ago
Now teamwork is good, but how can I accurately read the clinometer without an assistant ?
1 year ago
Look through the clinometer until you see what you're supposed to see, wait for the string to stop moving, then pull the string tight against the protractor, turn it, and look at it.
Rangemaster421 year ago
Or, you could adjust your position until you get a 45° reading and then, the measured distance on the ground plus the height of the observation point would give you the height of the post without needing a scientific calculator or a sine table. This is an old, established method taught to boy scouts.
1 year ago
Agreed. Learned this when I was 9 or 10... And I HATE math.
Bill WW1 year ago
Love your Instructable! I am going to use it today to measure height of a broken tree limb in our back yard. Nothing wrong with your math now, you must have made some changes. The one thing I remembered from my geometry class was "the side opposite a 30 degree angle is 1/2 the hypotenuse." Interesting that this was caught by the world's greatest living physicist, Stephen Hawking (post below).
u2att1 year ago
Interesting, but it gave me a headache
stephenhawkes1 year ago
It looks to me from your diagram as though the side opposite the 30 deg angle has a 1:2 relationship not with the side opposite the 60 deg angle but with the hypotenuse.
eschneck1 year ago
Well, if it isn't my old nemesis math .. we meet again!
85rocco1 year ago
This takes me back, I can remember doing something like that in grade 9 or 10 math class. The teacher threw in a bit of a twist, the object whose height we we measuring, a tall chimney, was inaccessible inside a fenced off area so there was no way to measure ones distance from the base of the chimney. The teacher asked us to calculate the height of the chimney and it's distance from the fence. This required us to take sighting from two spots outside the fence a measured distance apart. Then use the law of sines to calculate the length of the hypotenuse of the more distant sighting then use that to calculate the height and length of the base.
totally_screwed1 year ago
There is a simple method to measure heights. Needs an assistant and a 12 inch ruler or 30 cm ruler.
Using a twelve inch ruler held at arm's length, align the 12 inch mark with the top of the object and zero inches with the ground level at the foot of the object (adjust distance as required). Now get your assistant to mark the object with chalk or similar, or hold their finger at height of the one inch mark (commands such as up a bit, down a bit may help). Measure the height of the chalk mark or finger in inches, this is the height of the object in feet. Clearly only works to heights that one's assistant can reach, so around 80 feet or so. For taller trees, use the half inch point, this gives half the height in feet. For users of the metric system, a 30 cm rule and 3 cm would give one tenth the height at the mark.
opsimath1 year ago
There is also the Boy Scout - "stick and thumb" method: From where you are standing, take a stick and view the object so you have the top of the object at one end and your thumb marking the base... then turn the stick sideways so the stick now measures to an identifiable object on the ground... now walk off the distance between the base of the object to be measured and the 'target'...
kp911 year ago
I had a toy that did this in the late '70s, it even had a chart on the back for the trig.
my good compass has cotangent tables on the back for navigation purposes, same thing but on the horizonatl plane
the rocket1 year ago
nice idea bro :)
vincent75201 year ago
Nice !

Also note that fzumrk and hlanelee are elegant solutions.

Would the three of you be kind enough to post more for those of us who lost all those school applied maths somewhere in adulthood ??
It is so much fun to feel one can be (somewhat) clever again …

Thank you again !!!…
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