let's have a view on circuit diagram

## Step 1: Components Required

1) Diode 2
2) Capacitors 2
3) Connecting wires
5) Multimeter
6) ac source 12 v

## Step 2: Description

give the connection as per the circuit diagram, the two violet wires are used to check the output.

## Step 3: Testing

We got the doubled output..
hope you guys enjoyed..

if you guys have any doubts comment below..!
<p>hey dude.. can u explain how i can get 15v from dc motor using voltage tripler or voltage double.my dc motor produce 5v only..can u sent circuit at andy89_tgkk@yahoo.com</p>
<p>what capacitor rating would i need to go from 6v to 12v</p>
Dude, this circuit is of ac full wave rectifier. I wonder how you are getting &quot;voltage doubled&quot; that to in AC??
<p style="color: black;">You might wanna mention that you need large capacitor values to get a decent output current with this configuration. It can be used for low current bias and such, but if you need a higher voltage, it's generally better to use another transformer.</p><p style="color: black;">Here is the correct schematic.</p>
<p>Positive output labeled &quot;V-&quot;</p><p>:(</p>
<p>Good!</p>
<p>Sometimes pixels disappear on the thumbnails - Open in full size, and you'll see it's a plus sign.</p>
thanks for mentioning Omnivient
<p>Buddy of mine who is 'into wires' made one of these for me to power an electric fence with an automotive coil. It worked great. We plugged an electric drill into it and the drill would twist out of my hand when the trigger was pulled. Fun stuff!!!!</p>
<p>That must have been a very different circuit.</p>
<p>Something tells me that neither ccarpenter8 nor his buddy have ever been out of Mom's basement ...</p>
<p>The schematic diagram shows both sides of the output coming from the same node. The output voltage will be zero volts. The photos of the breadboard do not match the schematic. The breadboard photos show the output coming from only one capacitor. The output will be sqrt(2)* input voltage and it will be DC, not AC. The correct circuit takes the output from the cathode of the upper diode and the anode of the lower diode. It will be 2* sqrt(2) * input voltage and it will be DC.</p>
ehacker this circuit is an ac boosting circuit. with which we can only boost the ac supply. if you wanna check DC it will be in vain. this is not an rectifier circuit to get dc.
<p>It's not an AC boosting circuit. Here are several ways you can verify this.</p><p>1. I suspect your voltmeter responds to DC even though it's set to the AC range. What does the voltmeter show if you measure &quot;AC volts&quot; of a 9V battery?</p><p>2. You're an electronics student? Do you have access to an oscilloscope? An oscilloscope will tell you the true story.</p><p>3. Try actually putting 33 VAC across an inexpensive aluminum electrolytic capacitor. For that matter, try just putting your 12 VAC directly across one of those capacitors. See what happens.</p><p>4. Ask one of your instructors if you don't believe Omnivent and I.</p>
thanks hacker for your valuable comment.. you er right ma mm respond to ac even it is a DC source. sure I will check it with oscilloscope once ma semester holidays over. could you explain what the above circuit is.? plz
<p>It is a voltage doubling rectifier. Not seen a lot these days. They used to be common in the front end of switching power supplies. The supply could be configured for non-doubling rectification if the AC source was 240V or doubling with a 120V input. In this way, the rest of the supply had a more or less constant DC source to work from. Largely replaced by active PFC circuits now. Omnivent has shown the correct schematic in his reply 2 days ago.</p>
<p>Well, yes, it most certainly is a rectifier and you really should change the schematic. As is, you claim a voltage over a dead short.</p><p>Try looking at your schematic with Kirschoffs spectacles, or just trust me - I posted the correct schematic in another comment.</p>
Thanks for this... tutorials with so many mistakes actually annoy me
<p>Then post some yourself - and make sure to sift out any mistakes ;)</p>
I just used this to charge my car batt. thanks man, now I can get to work. had a crapy day. woke up found I left my car lights on AGAIN but I took hope in this and mAde it, charged my car batt. and now off to work.
<p>Besides the fact that you shouldn't charge a 12V lead-acid battery with over 30V, at least it was safe due to the extremely low output current. Even a very small car battery is at least 40Ah, so to charge it from flat using 1000&micro;F caps for around 100mA output, it would have taken:</p><p> 40Ah x 1.5 (charge loss compensation) / 0.1A = 600 hours (25 days)</p><p>Probably a lot longer due to the low charge. C400 isn't a realistic charge, as it's under the normal termination current. Further, a 60..90Ah battery is probably more likely in a current car model, so looking at C600 to C900 and hence 900..1350 hours (37.5 days to 56.25 days) - you must have a very forgiving employer ;)</p><p>If you regularly forget to turn off the lights, perhaps you should build a circuit to do it for you, either when you cut the ignition or after a delay from this (to allow you to find and unlock your front door).</p>
<p>No doubt, this is a very known and old schematic. Doesn't work with a significant load !</p><p>You can add several stages, this is how work the high voltage generators.</p>
<p>respected sir,</p><p>i have successfully verify the input and output voltage with the above guide. thanks for it.</p><p>-------&gt;&gt; favour needed.: i have measured high voltage with the resistor range..by mistake and results in tosted my multimeter..my resistance R17 and R18 are destroyed..now I have the same model of multimeter you are using. so can you please tell me the resistors ..</p><p>I FOUND OVER INTERNET BUT DID'NT WORKS.</p><p>PLEASE SIR HELP ME ..:(</p>
kavish you should measure it in ac voltage mode, not at resistance mode. <br>hope I solved your doubt. if not you can contact me personally over fb or whatsapp. ma number is 9600594859. thanks for trying
<p>ok.i will contact you. via whatsapp..:) </p>
I apologize if this is a dumb question or answer is obvious but, how do you get a 12 volt AC source
here I used 12v ac adaptor. you can also use transformer.
<p>A 12V transformer.</p><p>It's only dumb if you ask the same question once more... First time's always a freebie :)</p>
<p>Great project! Thanks for sharing and welcome to the community! </p>
?thank you