Volume of a Sphere

A sphere is nothing but a three dimensional circle. If you can imagine a smooth ball, suspended in mid-air, perfectly round... then you get a sphere.

All of you have seen spheres...They're everywhere!
If you've seen the solar system, you've seen spheres..If you've played ping pong, or golf or soccer...even basketball or cricket and hockey...you've seen spheres. If you are a housewife, you'll see spheres in the fruit basket... And if you are in kindergarten...they're in your abacus set!
Spheres are very common shapes, one encounters in everyday life.

This instructable will show you "how" and "why" to calculate the volume of a sphere.
I have explained every concept and every formula in great detail. Also , I have filled up this instructable with a lot of practical examples which will help you understand me

Step 1: Your Toolbox

If you're planning to do some real-time calculations, here's what you will definately need:
1) A good ruler.(Or if you have a good vernier calliper in the local store, that would be excellent!).
2) A long piece of thread( Extremely useful in finding the circumference!)
2) A good and reliable calculator.
3) A pencil or marker of some sort.
4) Paper on which you can do your calculations.

Comments

[GASSYPOOTS]

easiest way= make a 2 piece mold of the sphere in clay hardden it fill both halves with water 1ml=1 cubic cm so measure how much water it takes :D

[knektek]

you are supposed to do area=pi X (radiusXradius) ,
not area = pi X radius X radius.

[totos]

it's the same

[PKTraceur]

Cant that be 3.14 * diameter?

-PKT

[Yashknowsbetter]

diameter is nothing but twice the radius...so you can write any equation in terms of diameter as well...if i'm not mistaken, you've written the equation of circumference of the circle...it's right...

[PKTraceur]

So, i'm right? -PKT

[Yashknowsbetter]

yes...circumference=pi*diameter.

[Yashknowsbetter]

Yeah...scotty3785 is right.. When multiplication signs are the only signs in an equation, parenthesis rarely matter. Although the issue with matrices is different...

[scotty3785]

Try that on a calculator.. pi x 10 x 10 is the same as pi x (10x10)

[GASSYPOOTS]

its one of the properties of multiplication

[tsaffert]

water displacement FTW

[SubFusion]

V =  d x d x d / 1.91

[mathman47]

You did a nice job of explaining a hard concept. Now explain integration.

[Yashknowsbetter]

integration would be harder to actually explain..but i'll definately try!

[66411]

You could try to explain how to find the area of two intersecting spheres then you would need integration and several years differential calculus.

[Xellers]

You could just use the disc method to integrate the portions of the intersecting spheres and then add the results. Its not very difficult.

[Yashknowsbetter]

I know.....im really perplexed as to how i can explain the concept of Integration itself ...any suggestions.???

[mathman47]

Let's see. Take 3 years and 4 to 5 1,000 page textbooks. Seriously, I think graphing is the way to go. Find the area under a curve using smaller, and smaller (eventually an infinite number of) rectangles. I can't get to my books right now, but I think that's how I was taught. Good luck.. We're all rooting for you.

[Yashknowsbetter]

yaa..thats right i guess that's the simplest way to get it done...i'll try my best...

[Xellers]

Why don't you just prove that an integral is an antiderivative? I think its the most straightforward way.

[kourpas]

(removed by author or community request)

[Re-design]

I don't mow my garden, I harvest my garden. I mow the grass around my garden.

[vic587]

ease up with the exclamation marks :)

[Yashknowsbetter]

Yeah i know i've put too many in there, but dont worry they wouldnt hurt ne1

[vic587]

ya I know :). Hey just wanna say thanks a lot. Your instructable helped me out a lot for a project I had to do for school. thanks! I appreciate it.

[Yashknowsbetter]

Wow! dat's made my day!

[lock]

Cant you just get the volume by multiplying pi by radius by radius by height of a cylinder of the same dimensions (lets say 2 height and 2 radius) then cut it in half (or third I can't remember) then multiply it by two? I am pretty sure that gets the volume of a cylinder.

[GlueyMcGee]

Volume of a sphere, the simple way: 4πr² OR four times pi times radius times radius...just find the radius! easy isn't it?

[azice]

Couldn't you just put it into a graduated flask with water in it and subtract the difference? I think I'm missing the point, sorry.

[Yashknowsbetter]

Yeah...thats right!

[Foaly7]

A hockey puck is a flat circle, not a sphere.

[SamuelAaronWard]

A hockey puck is technically a right-circular cylinder, not a circle or a sphere.

[lake75]

It is a sphere if you spin it! GO CONDORS! LOL

[SamuelAaronWard]

I'm not trying to be jerk here,... but it's not even a sphere if you spin it. Yeah, it looks a lot like a sphere, but it's still not. Only a circle rotated about a radial axis will result in a sphere. A right-circular cylinder (a circle extruded through some depth along a line perpendicular to the plane of the circle) rotated about a radial axis will result in something different than a sphere.

[Yashknowsbetter]

There are two kinds of hockey played around the world, ICE hockey is played with a puck, which is as you said , a flat disk. But the other kind, played on a turf field uses a round white colored ball ( which is very much, a sphere)!!!

[Dragons]

knektek pi x radius x radius is the same as pi X (radius X radius). It is the associative property.

[Yashknowsbetter]

If it was'nt the associative property...it would've been called common sense!.

[Dragons]

Yeah I know, I didn't want to be mean.

[mattduvall]

for measuring the volume of things like golfballs or a small sphere its easier to use water displacement, measure how much water u have in a measuring cup, put in the sphere, measure how much you have after. the difference = the volume, more accurate for things like golfballs which are not perfect spheres

[Yashknowsbetter]

True... very correct...i've explained only the theoretical ways of determining volume.