Wirelessly power your iDevices!

Wow, I'm really surprised at how many views this is getting! Thank you everyone for reading!

I recently made a boost converter (for those unfamiliar with them, they effectively boost the voltage up to a useable amount) to make a USB Ipod charger using 2 AA batteries.

Now that that was done and over, tested tried and true, I decided I wanted to make something a little more snazzy!



Behold, the wireless ipod charger!

Uses all 12 volts of 6 (2 in parallel for each cell) lithium batteries!

Draws under 3 amps all the time!

Perfect for kids parties!

Now in 5 new flavors!

I've searched around on this website, and noticed that almost all of the instructables on here with wireless power seem to lack a proper explanation about how to build one; Or, when they did build one, they used an inefficient method of doing so...

This transmitter works fantastic, and can run on pretty much any voltage above 12 volts, and below 24! It's also extremely efficient (little power lost) and, it generates almost no interference. (one wireless power instructable used a square wave in the primary; Square waves have a lot of harmonics, and can cause havoc on computer systems, radios, and other sensitive electronics)

I've come to solve all of these problems!

Step 1: So you want to make it, right?

You'll need some parts.

2 MOSFETS - I understand that this is a rather vague statement. You can use the IRFP250, if you want to. However, the lower the on-state resistance is, the less heat will be generated. You can get these from any ol electronics supplier. Farnell, mouser, digikey, ebay

2 10k ohm resistors. (brown black orange) You can use 1/4 watt ones. Again, you can get these at the listed ones above, and even radioshack should have these.

2 Ultrafast Diodes - They need to be above 400 volts. I used UF4007's. Farnell, Mouser, Digikey, ebay...

2 Twelve volt zener diodes - Nothing special to say here! Again, Farnell, Mouser, and Digikey.

1 7805 - I know I said I used a boost converter. However, a boost converter is a whole another instructable, and I can't explain how to build one in this. So, for now, we'll just use a 7805. Radioshack has these in addition to the places listed before!

2 18k ohm resistors - 1/4 watt (brown - gray - orange) Radioshack, and the listed places.

2 12k ohm resistors - 1/4 watt (brown - red - orange) " "

1 Ferrite toroid - it can be around 1/2 inch in diameter. Wind roughly 30 turns of enameled wire on it, and you'll be set! You can get these from old Tube televisions scrapped, ATX PSU's. Basically anything you can take apart *should* have one of these.

USB Female Port - I scavenged mine from an old adapter PCI board we had from 2000. We didn't need it, so I figured why not? If you don't know where to get one, you should be able to get them from Mouser, Digikey, Farnell, and ebay.

Two sets of tank capacitors - I used 4 1 uF capacitors for mine. You can use two 2 uF capacitors instead, if you want to. You NEED to make sure they're MKP, or a better type! Polyester ones, electrolytics, anything along those lines will not work, and will overheat! WIMA makes some nice capacitors that work fantastic for this project. You can alternatively use Farnell, Digikey, or Mouser to find some MKP capacitors to use. Ebay will have some too.

You'll also need some 14 gauge wire, and tape!
<p>hey thanks I MADE IT and won prize also ,I am still working on improving efficiency and range. HEARTLY THANKS TO INSTRUCTABLE.</p>
<p>bro, may i know how did u check whether your transmitter working??</p>
Can u please tell me which type and the gauge no of wire u have used
<p>Congrats to this success! :)</p><p>Please let us know what you changed in your optimising and what the performance-change was.</p>
Hey this is a great Ible! But I cannot read this section. BTW these are the Resistors in the sender schematic.
You gotta click on the little [i] and then the link to the original image link: <br> <br>http://www.instructables.com/files/orig/F6H/9YP2/GUKB3PNB/F6H9YP2GUKB3PNB.png <br> <br>It's 18k and 18k on the top side, and 12k and 12k on the bottom side ;-)
<p>hey, would you mind sending me more detailed pictures of the build. I'm near at building with schematics and can't really follow it that well. Thanks alberteinstine2012@gmail.com</p>
<p>Hi. Could you tell me please how much energy is wasted from the batteries when transmitting power wirelessly? </p>
<p>what should be the diameter of coil </p>
<p><strong>D</strong> = <strong><u>6.7<em>in</em></u></strong> <em>for the 7ft wire</em></p><p><strong>D = <u>8.594</u></strong><em><u><strong>in</strong> </u> for the 9ft wire<br><br>Disclaimer: If you read further please note that no part of the explanation below is written with the intent to insult anyone's intelligence but rather is aimed at being complete. It does this by not assuming that the reader intuitively knows anything about mathematics whatsoever.<br><br>Summary equation:<br><br></em><em>D = 2 <strong>x</strong> </em><strong>[</strong>[ (Length of wire) / (# of turns) ]<em> <strong>x</strong> </em>[<em>1/(</em>2&Pi;) ] <strong>]<br><br>Derivation of Diameter D equation above: </strong></p><p><em>If you know the total length of the wire L= whatever length you want<br><br>length of wire in ft * 12 = length of wire in inches I will call <strong>L</strong><br></em><em><br></em></p><p><em><strong>L</strong></em></p><p><em>c = <u> </u> <br> number of turns</em></p><p><em>plug c into: </em></p><p><em> c<br>r = <u> </u></em></p><p>2&Pi;<br></p><p>plug r into: </p><p> D= 2r </p><p><em><br><br><u><strong>Conceptual explanation: </strong></u></em></p><p><br>Notice that the length of the wire should be from <em>7 to 9 feet</em>. <br><br>This image: <a href="http://cdn.instructables.com/F6R/QHPS/GUQ4JRDQ/F6RQHPSGUQ4JRDQ.MEDIUM.jpg" rel="nofollow">F6RQHPSGUQ4JRDQ.MEDIUM.jpg</a> <br>Reveals that coil is wound <strong>three</strong> times completely and a <strong>fourth</strong> time including the open ends. <br><br>For sake of convenience let's turn <em>feet</em> to <em>inches</em>: <strong>7</strong><em>ft</em> *(12<em>in for every</em> 1 <em>ft</em>) = <strong>84</strong><em>in</em><br> or if you want 9ft instead: <strong>9</strong><em>ft</em> *(12<em>in for every</em> 1 <em>ft</em>) = <strong>108</strong><em>in</em></p><p><br>Since the coil is wound three times completely and a fourth time with open ends we can approximate that the coil is wound 4 times completely. <br><br>Now you want to take the <strong>length of the wire</strong> and<strong> divide it by the number of turns </strong>it will give you the circumference of the single circle about which all <u>4 turns</u> are wound.<br><br>For 7ft having been converted to 84<em>in</em> we take 84<em>in</em>/4 turns= 21<em>in</em> <br>circumference (which I will call <strong>c</strong>) of the circle with the 7ft long wire is = 21in <br> <strong>c</strong> = 21<em>in</em><br><em>and if you choose to go with the 9ft long wire instead:</em><br>9ft converted to 84in take 108in/4 turns= 27in <br> <strong>c</strong> = 27in<br><br>Now that we have the circumference, we can acquire the diameter. <br>You may recall from one of your classes that the circumference of the circle is &quot;2&Pi;r&quot; if you didn't- now you do. Also recall that I have said above that the letter <strong>c </strong>is set equal to the circumference ( <strong>c</strong> = 21<em>in or </em><strong>c</strong> = 27in ), knowing this we can use the identity of circumference to find the radius: <br><br>Let's start with using <strong>c</strong> = 21<em>in.<br><br>We </em>know that<strong>c</strong> = 21<em>in </em>but also <strong>c</strong> = 2&Pi;r. Now pretty much anyone can see that 1 = 1 or 2 = 2. Likewise <strong>c</strong> = <strong>c </strong><em>thus</em><strong>:<br><br></strong>21<em>in</em><strong> = </strong>2&Pi;<strong>r</strong><br><br>I am hoping you know that the diameter is twice the radius because that's where I got this relation:<br><br><strong>D </strong>=<strong> </strong>2<strong>r </strong>where<strong> D </strong>is the diameter of a circle and <strong>r</strong> is the radius.</p><p></p><p>Divide 21 by 2&Pi; to acquire <strong>r</strong>. <br><br>For the 7ft (or 84in long) wire the radius of the coil is:</p><p> <strong>r </strong>=<strong> </strong><u>21<em>in</em></u> = 3.34225380493<em>in</em> rounding <strong>r </strong>&asymp; 3.342</p><p><strong> </strong>2&Pi;<strong><br><br></strong>Now multiply by two to derive the diameter:<br><br><strong>D </strong>=<strong> </strong>2<strong>r =&gt; D </strong>= 2(3.342)<strong> =&gt; </strong><strong>D</strong> =<strong> </strong>6.684 &asymp; <u>6.7</u><em><u>in </u> for the 7ft wire.</em></p><p><strong><br></strong></p><p>Therefore the diameter is given by:</p><p>For the 9ft (or 108in long) wire the radius of the coil is:</p><p> <strong>r</strong> = <u>27<em>in</em></u> = 4.29718346348in rounding <strong>r </strong>&asymp; 4.297</p><p> 2&Pi;<br>Therefore the diameter is given by:</p><p><strong>D </strong>=2r =&gt; <strong>D </strong>= 2(4.297) =&gt; <strong>D</strong> = 8.594 &asymp; <u>8.594</u><em><u>in </u> for the 9ft wire</em></p><p><strong></strong></p>
<p>Thanks a lot!!<br><br>I was looking for a long long time something like this!<br><br>Can you help me ?? .... In the ferrite toroid we have to wind with 30 turns but I dont know what kind of gauge wire use.<br>Anybody can help me?</p>
<p>Thanks so much for this AWESOME instructable, after much headache I <br>am able to say that I was finally able to get things working. And I'm <br>an absolute beginner so that goes a lot to say about the writer, thank <br>you!! <br><br>I did run into a slight issue though and was hoping I <br>could get some guidance, granted I havent built in the connection to the<br> 7805 and have the tx built as well as the receiver built (caps and <br>rectifier), when I go to measure the dc current at the rectifier I only <br>get .08 on my multimeter... I do however get a full 12 volts at the tx <br>though... Any thoughts? <br><br>Hooked up to 12v 1.8 amp power, <br>everything is identical to instructable (it works, just low low low <br>voltage at receiver end). Only think i notice may be different is that <br>my inductor is made with 26 gauge magnet wire (30 turns) when it looks <br>like in yours you are using some thicker gauge wire. </p><p>Am i just <br>jumping the gun and needing to connect all the way through the 7805 in <br>order to see the full 5 volts? I just didnt want to solder the thing <br>until all tested, figured i would at least get 5v at the rectifier.. <br>unless i'm reading my multimeter wrong (at 20v setting reads .08 max).</p><p>Thanks for any help!</p>
<p>Can I use the powermat receivers like they have at starbucks instead of building it? You can get those for free from the powermat website and saves building that part myself. Will the transmitter work for those?</p>
<p>what use is this comment section if u dnt reply...</p>
<p>why do we require such a high frequency of operation? and what is the diameter of the turns of primary and secondary transmitter?</p>
<p>how will the mosfets get triggered?and what is the operating frequency?and y do we need a high frequency of operation?</p>
<p>bro, can drop me an email ? i want to ask about the project</p>
<p>i made it and its working.....i got 9v without using the 7805...i just wish i can increase the range of transmission</p>
Hello.<br>Can you explain making coil?<br>I cannot do this.<br>Please Can you tell me Radius and Turn of coil.'?<br>Thanks you<br>juekokohtet@gmail.com
<p>Hi, can u help me to troubleshoot my circuit.</p>
<p>ok whats the issue</p>
<p>Hi, my circuit is not working, i have used 2.2uf capacitor mkp similar type. I dont have cro to troubleshoot. </p>
does not it generate emp that harmful to electronics
<p>I dont know why but i cant get it to work. the first Mosfet gets just hot and I dont even get anything to the master coils : /</p>
Hello bro..how did u overcome this problem u faced??
<p>Hello! :) I wanted to ask(I am new to coils) if the <em>3+3 turn coil</em> is like <strong>6 turns</strong> but in the middle a stripped bit, or a <strong>3 turn</strong> coil with a stripped bit in the middle<strong>? </strong>(as it is a bit unclear in the pictures.. perhaps you can even add this to the coil step :D ) <em>Thanks in advance :D</em></p>
How this project makeing for long distance working
<p>I was very happy to uncover this site. I wanted to thank you for your time just for this fantastic read!!</p><p>I definitely enjoyed every little bit of it and I have you saved as a favorite to</p><p>see new stuff in your site. &lt;a href=http://softwarespin.com/&gt; hashmi. . . . . . .&lt;/a&gt;</p>
<p>does the transmitter have AC to DC converter and DC to AC inverter? what are the uses for MOSFET and ZENER diode? why use ZENER diode instead of ultrafast diode?</p>
<p>can i buy the kit ??? can anybody please tell me its price please</p>
<p>Hey Guys, I made it! I finally made it, thank you for your information and all the help, i used this for my college project!! </p><p>https://www.youtube.com/watch?v=rdPWNb-70tQ</p>
<p>Where is the ferrite toroid in this schematic? Also, where does the second ultra-fast diode go? It's not in the schematic. Lastly, do we need the filter cap or is it not really necessary?</p>
<p>Hello can you give me the steps of the circuit and the value of the components thanks</p>
can you please give me the steps to make this , I'm lost
Hey, whats the range you achieved? Cause my circuit works but the efficiency drops extremely fast to 0% at a distance of 4 inches or so. Do you know what I could have done wrong?
<p>One drawback to wireless chargers is that they don't achieve great distances. I'm not sure what the maximum distance is for this project, but 4 inches sounds about right.</p>
<p>Great project!Thumbs Up! :)</p>
<p>I have just made this circuit and I ran into a problem.When I connected the circuit to the power supply the wires melted. Any ideea on why that happend?</p>
<p>how can i simulate wireless power circuit please help me ..............</p>
<p>how can in simulate the circuit of transmitter and receiving circuit</p>
<p>about how much does this cost to make total?</p>
<p>a vital information is missing from this project...WHAT IS THE INDUCTANCE VALUE OF THE 3 X 3 CENTER TAP COIL....</p><p>you said the coil oscillates at 50khz</p>
Hey,can this charger will work for other phone
<p>I think you can always replace the usb cable? since USB generally tend to be 5V I dont see any reason why you should not be able to? </p>
<p>in which node have to check the square wave output at transmitter.</p>
<p>what is the resonant frequency</p>
<p>Hey! What's diameter of the primary and secondary coils? I made those circuits, but I have only 0.7 A on the receiver. </p>

About This Instructable




Bio: I'm 21, and I have a profound interest in electronics, lasers and Geology.
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