The receiving end is less complex. Make sure you use the same capacitor value, as well as following the USB pinout as I have written in the schematic.

You can try and experiment with different turns ratio's of the coils and see what kind of performances you get! This has to do with resonance, and step-up / step-down ratios.

Try adding more voltage, and see if you get more distance; another way of possibly increasing distance is to increase the resonant frequency a bit. Increasing the frequency should give you more distance, with additional current draw.

To increase the frequency, just lower the capacitor values. Personally, the lowest I'd go would be around 1 uF. Make sure when you lower the cap value, you do it for both the receiving, and the transmitting ends!

Also, remember, the idea does not have to apply only to USB. I've noticed that due to resonant rise, the filter capacitor charges to the peak of the output sine wave....

At 12 volts into the transmitter, I was getting around 24 volts at the receiver end! (this isn't the effective voltage however; once you put a load on it, it drops a bit) At 15 volts in, I was getting 35 volts on the receiver! (wow, that's quite a bit of a jump, huh?)

This means that you should be able to power other things as well. Use whatever your mind comes to!

You can try and experiment with different turns ratio's of the coils and see what kind of performances you get! This has to do with resonance, and step-up / step-down ratios.

Try adding more voltage, and see if you get more distance; another way of possibly increasing distance is to increase the resonant frequency a bit. Increasing the frequency should give you more distance, with additional current draw.

To increase the frequency, just lower the capacitor values. Personally, the lowest I'd go would be around 1 uF. Make sure when you lower the cap value, you do it for both the receiving, and the transmitting ends!

Also, remember, the idea does not have to apply only to USB. I've noticed that due to resonant rise, the filter capacitor charges to the peak of the output sine wave....

At 12 volts into the transmitter, I was getting around 24 volts at the receiver end! (this isn't the effective voltage however; once you put a load on it, it drops a bit) At 15 volts in, I was getting 35 volts on the receiver! (wow, that's quite a bit of a jump, huh?)

This means that you should be able to power other things as well. Use whatever your mind comes to!

<p>hey thanks I MADE IT and won prize also ,I am still working on improving efficiency and range. HEARTLY THANKS TO INSTRUCTABLE.</p>

<p>bro, may i know how did u check whether your transmitter working??</p>

Can u please tell me which type and the gauge no of wire u have used

<p>Congrats to this success! :)</p><p>Please let us know what you changed in your optimising and what the performance-change was.</p>

Hey this is a great Ible! But I cannot read this section. BTW these are the Resistors in the sender schematic.

You gotta click on the little [i] and then the link to the original image link: <br> <br>http://www.instructables.com/files/orig/F6H/9YP2/GUKB3PNB/F6H9YP2GUKB3PNB.png <br> <br>It's 18k and 18k on the top side, and 12k and 12k on the bottom side ;-)

<p>Hi. Could you tell me please how much energy is wasted from the batteries when transmitting power wirelessly? </p>

<p>what should be the diameter of coil </p>

<p><strong>D</strong> = <strong><u>6.7<em>in</em></u></strong> <em>for the 7ft wire</em></p><p><strong>D = <u>8.594</u></strong><em><u><strong>in</strong> </u> for the 9ft wire<br><br>Disclaimer: If you read further please note that no part of the explanation below is written with the intent to insult anyone's intelligence but rather is aimed at being complete. It does this by not assuming that the reader intuitively knows anything about mathematics whatsoever.<br><br>Summary equation:<br><br></em><em>D = 2 <strong>x</strong> </em><strong>[</strong>[ (Length of wire) / (# of turns) ]<em> <strong>x</strong> </em>[<em>1/(</em>2Π) ] <strong>]<br><br>Derivation of Diameter D equation above: </strong></p><p><em>If you know the total length of the wire L= whatever length you want<br><br>length of wire in ft * 12 = length of wire in inches I will call <strong>L</strong><br></em><em><br></em></p><p><em><strong>L</strong></em></p><p><em>c = <u> </u> <br> number of turns</em></p><p><em>plug c into: </em></p><p><em> c<br>r = <u> </u></em></p><p>2Π<br></p><p>plug r into: </p><p> D= 2r </p><p><em><br><br><u><strong>Conceptual explanation: </strong></u></em></p><p><br>Notice that the length of the wire should be from <em>7 to 9 feet</em>. <br><br>This image: <a href="http://cdn.instructables.com/F6R/QHPS/GUQ4JRDQ/F6RQHPSGUQ4JRDQ.MEDIUM.jpg" rel="nofollow">F6RQHPSGUQ4JRDQ.MEDIUM.jpg</a> <br>Reveals that coil is wound <strong>three</strong> times completely and a <strong>fourth</strong> time including the open ends. <br><br>For sake of convenience let's turn <em>feet</em> to <em>inches</em>: <strong>7</strong><em>ft</em> *(12<em>in for every</em> 1 <em>ft</em>) = <strong>84</strong><em>in</em><br> or if you want 9ft instead: <strong>9</strong><em>ft</em> *(12<em>in for every</em> 1 <em>ft</em>) = <strong>108</strong><em>in</em></p><p><br>Since the coil is wound three times completely and a fourth time with open ends we can approximate that the coil is wound 4 times completely. <br><br>Now you want to take the <strong>length of the wire</strong> and<strong> divide it by the number of turns </strong>it will give you the circumference of the single circle about which all <u>4 turns</u> are wound.<br><br>For 7ft having been converted to 84<em>in</em> we take 84<em>in</em>/4 turns= 21<em>in</em> <br>circumference (which I will call <strong>c</strong>) of the circle with the 7ft long wire is = 21in <br> <strong>c</strong> = 21<em>in</em><br><em>and if you choose to go with the 9ft long wire instead:</em><br>9ft converted to 84in take 108in/4 turns= 27in <br> <strong>c</strong> = 27in<br><br>Now that we have the circumference, we can acquire the diameter. <br>You may recall from one of your classes that the circumference of the circle is "2Πr" if you didn't- now you do. Also recall that I have said above that the letter <strong>c </strong>is set equal to the circumference ( <strong>c</strong> = 21<em>in or </em><strong>c</strong> = 27in ), knowing this we can use the identity of circumference to find the radius: <br><br>Let's start with using <strong>c</strong> = 21<em>in.<br><br>We </em>know that<strong>c</strong> = 21<em>in </em>but also <strong>c</strong> = 2Πr. Now pretty much anyone can see that 1 = 1 or 2 = 2. Likewise <strong>c</strong> = <strong>c </strong><em>thus</em><strong>:<br><br></strong>21<em>in</em><strong> = </strong>2Π<strong>r</strong><br><br>I am hoping you know that the diameter is twice the radius because that's where I got this relation:<br><br><strong>D </strong>=<strong> </strong>2<strong>r </strong>where<strong> D </strong>is the diameter of a circle and <strong>r</strong> is the radius.</p><p></p><p>Divide 21 by 2Π to acquire <strong>r</strong>. <br><br>For the 7ft (or 84in long) wire the radius of the coil is:</p><p> <strong>r </strong>=<strong> </strong><u>21<em>in</em></u> = 3.34225380493<em>in</em> rounding <strong>r </strong>≈ 3.342</p><p><strong> </strong>2Π<strong><br><br></strong>Now multiply by two to derive the diameter:<br><br><strong>D </strong>=<strong> </strong>2<strong>r => D </strong>= 2(3.342)<strong> => </strong><strong>D</strong> =<strong> </strong>6.684 ≈ <u>6.7</u><em><u>in </u> for the 7ft wire.</em></p><p><strong><br></strong></p><p>Therefore the diameter is given by:</p><p>For the 9ft (or 108in long) wire the radius of the coil is:</p><p> <strong>r</strong> = <u>27<em>in</em></u> = 4.29718346348in rounding <strong>r </strong>≈ 4.297</p><p> 2Π<br>Therefore the diameter is given by:</p><p><strong>D </strong>=2r => <strong>D </strong>= 2(4.297) => <strong>D</strong> = 8.594 ≈ <u>8.594</u><em><u>in </u> for the 9ft wire</em></p><p><strong></strong></p>

<p>Thanks a lot!!<br><br>I was looking for a long long time something like this!<br><br>Can you help me ?? .... In the ferrite toroid we have to wind with 30 turns but I dont know what kind of gauge wire use.<br>Anybody can help me?</p>

<p>Thanks so much for this AWESOME instructable, after much headache I <br>am able to say that I was finally able to get things working. And I'm <br>an absolute beginner so that goes a lot to say about the writer, thank <br>you!! <br><br>I did run into a slight issue though and was hoping I <br>could get some guidance, granted I havent built in the connection to the<br> 7805 and have the tx built as well as the receiver built (caps and <br>rectifier), when I go to measure the dc current at the rectifier I only <br>get .08 on my multimeter... I do however get a full 12 volts at the tx <br>though... Any thoughts? <br><br>Hooked up to 12v 1.8 amp power, <br>everything is identical to instructable (it works, just low low low <br>voltage at receiver end). Only think i notice may be different is that <br>my inductor is made with 26 gauge magnet wire (30 turns) when it looks <br>like in yours you are using some thicker gauge wire. </p><p>Am i just <br>jumping the gun and needing to connect all the way through the 7805 in <br>order to see the full 5 volts? I just didnt want to solder the thing <br>until all tested, figured i would at least get 5v at the rectifier.. <br>unless i'm reading my multimeter wrong (at 20v setting reads .08 max).</p><p>Thanks for any help!</p>

<p>Can I use the powermat receivers like they have at starbucks instead of building it? You can get those for free from the powermat website and saves building that part myself. Will the transmitter work for those?</p>

<p>what use is this comment section if u dnt reply...</p>

<p>why do we require such a high frequency of operation? and what is the diameter of the turns of primary and secondary transmitter?</p>

<p>how will the mosfets get triggered?and what is the operating frequency?and y do we need a high frequency of operation?</p>

<p>bro, can drop me an email ? i want to ask about the project</p>

<p>i made it and its working.....i got 9v without using the 7805...i just wish i can increase the range of transmission</p>

Hello.<br>Can you explain making coil?<br>I cannot do this.<br>Please Can you tell me Radius and Turn of coil.'?<br>Thanks you<br>juekokohtet@gmail.com

<p>Hi, can u help me to troubleshoot my circuit.</p>

<p>ok whats the issue</p>

<p>Hi, my circuit is not working, i have used 2.2uf capacitor mkp similar type. I dont have cro to troubleshoot. </p>

does not it generate emp that harmful to electronics

<p>I dont know why but i cant get it to work. the first Mosfet gets just hot and I dont even get anything to the master coils : /</p>

Hello bro..how did u overcome this problem u faced??

<p>Hello! :) I wanted to ask(I am new to coils) if the <em>3+3 turn coil</em> is like <strong>6 turns</strong> but in the middle a stripped bit, or a <strong>3 turn</strong> coil with a stripped bit in the middle<strong>? </strong>(as it is a bit unclear in the pictures.. perhaps you can even add this to the coil step :D ) <em>Thanks in advance :D</em></p>

How this project makeing for long distance working

coooooooooool

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<p>does the transmitter have AC to DC converter and DC to AC inverter? what are the uses for MOSFET and ZENER diode? why use ZENER diode instead of ultrafast diode?</p>

<p>can i buy the kit ??? can anybody please tell me its price please</p>

<p>Hey Guys, I made it! I finally made it, thank you for your information and all the help, i used this for my college project!! </p><p>https://www.youtube.com/watch?v=rdPWNb-70tQ</p>

<p>Where is the ferrite toroid in this schematic? Also, where does the second ultra-fast diode go? It's not in the schematic. Lastly, do we need the filter cap or is it not really necessary?</p>

<p>Hello can you give me the steps of the circuit and the value of the components thanks</p>

can you please give me the steps to make this , I'm lost

Hey, whats the range you achieved? Cause my circuit works but the efficiency drops extremely fast to 0% at a distance of 4 inches or so. Do you know what I could have done wrong?

<p>One drawback to wireless chargers is that they don't achieve great distances. I'm not sure what the maximum distance is for this project, but 4 inches sounds about right.</p>

<p>Great project!Thumbs Up! :)</p>

<p>I have just made this circuit and I ran into a problem.When I connected the circuit to the power supply the wires melted. Any ideea on why that happend?</p>

<p>how can i simulate wireless power circuit please help me ..............</p>

<p>how can in simulate the circuit of transmitter and receiving circuit</p>

<p>about how much does this cost to make total?</p>

<p>a vital information is missing from this project...WHAT IS THE INDUCTANCE VALUE OF THE 3 X 3 CENTER TAP COIL....</p><p>you said the coil oscillates at 50khz</p>

Hey,can this charger will work for other phone

<p>I think you can always replace the usb cable? since USB generally tend to be 5V I dont see any reason why you should not be able to? </p>

<p>in which node have to check the square wave output at transmitter.</p>

<p>what is the resonant frequency</p>

<p>Hey! What's diameter of the primary and secondary coils? I made those circuits, but I have only 0.7 A on the receiver. </p>

<p>can make to laptop wireless charger..?<br>bcoz i want to do final project for IT Networking can anyone help me</p>