First the charger went, then the batteries died, and then before I could buy replacements the company then switched to the 18V format and dropped all product support for the 14.4V line.
I purchased a new 18 Volt drill from another manufacturer in protest but it really wasnââ¬â¢t as good as my old one, the chuck slips when drilling and the drill clutch doesnââ¬â¢t seem to handle torque well.
So how to resuscitate my old tools cheaply?
I had two 18V batteries and chargers from other tools and when I jumped them to the 14.4V tools they seemed to run okay. The challenge then was to convert a 14.4V battery into an adaptor.
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i had a ryobi and i dropped it off a 6 foot ladder onto the sidewalk and it smashed into a billion peices. now i only buy high quality tools.
You are right though, amp rating is simply what is available, it's up to the load to pull what it requires. Too many amps won't damage anything unless the voltage isn't fixed. Some (cheap) stuff can increase voltage when the current requirement exceeds it's amp rating, which could damage a device, but it's unlikely.
The voltage output of a car battery can vary slightly, up to 14 or 15 volts. It would only be this extra voltage that may damage the drill.
The problem you had could be the wiring. The motor may have drawn more current than it's wiring could handle.
If we connect an electric motor, a small one, it will allow just a fraction of an Ampere to flow through it, say 250 milliamps or so; because the small wire that is used in the windings will present a comparatively large RESISTANCE of about 48 Ohms. BUT if we connect a much larger motor, like the Starter Motor of a car, the same 12 V battery will flow a large current, maybe 150 Amperes! because this motor presents a much lower resistance, of around 0.08 Ohms... (its windings are made with a much larger wire gage, just look at the diameter of the car battery cables!).
POWER is the result of multiplying applied voltage times current, so that a WATT is produced or dissipated when a current of one Ampere flows pushed by one Volt. Therefore, power can be calculated from the following simple relations:
I = V / R, V = I x R, R = V / I... P = V x I or P = (V) squared / R
In the case of our friend FINTON above, the small motor must have been defective, most probably having some shorted windings. This resulted in a too small resistance that caused that the large capacity 12 V car battery able to deliver several amperes and quickly burned the poor small motor. If the motor would have been in good condition, it would run perfectly under the light load meant for it. At the same time, that small defective motor would turn at partial speed when connected to an smaller voltage battery (say, a common 9V alcaline cell), but that small battery would be incapable of sustaining its output voltage when connected to the partially shorted motor, thus not being cappable of burning it!
Now, most DC (direct current) electric motors can be fed with a higher voltage, above the nominal one it was designed to handle, but it is a matter of how heavy will it be loaded when operated. See, the motor presents an electrical load that DEPENDS on the MECHANICAL load it has to move, so that if lightly loaded, common electrical motors certainly can handle say 1.5 times the nominal voltage, if the mechanical load is not far above the design one. Present day Model Airplane hobbyists use motors designed for say, 12 Volts, with battery packs that can sustain almost double that voltage, but they use it wisely, using the maximum power for brief periods of seconds, like for Take-Off or maneuvers, backing off the electronic throttle to avoid burning the motor. As this INSTRUCTABLE says, it is "safe" to assume that a Cordless Hand Drill meant for "12 V" nominal, can be perfectly run with a 14.4 V pack. It will turn faster and will be capable of more power output, BUT WILL ALSO OVERHEAT more quickly if the same Load is applied, so keep this in mind and avoid loading it too much. BTW, rechargeable cells have an actual voltage that is NOT the nominal one under load, so that the 12V pack is assembled from 10 1.2 V nominal cells, that maintain close to 1.0 volt under load each wired in series, and the 14.4 V pack has 12 such cells, thus achieving only 12V under load. This applies to Nickel based cells. Lithium cells have 3.7 to 3.8 nominal Volts, so that one can perfecly use a pack of three to four Lithium-Ion or Lithium Polymer cells for that drill, saving a lot of weight and bulk, but then would need a special charger designed for Lithium cells, and also apply ALL the cautions of using Lithium cells! Good Luck. amclaussen.-
Still haven't got around to trying your idea with resistance... :[
The ozone smell is most likely due to overheating the motor brushes. Do it too much and you'll burn out the commutator, ruining the motor. Depending on how nice a motor it has, you may be able to replace the brushes with higher quality ones that won't overheat so easy.
As for drills and blades, using ones made for AC powered drills will always be fine for battery powered ones. AC drills pretty much always run at higher RPM's than battery.
As for "order of magnitude", this phrase has a specific mathematical meaning of "ten times". Using it to mean anything else will mean that people misunderstand you. Using it mean "one step up" is like saying run when you mean crawl.
On over voltage operation, I am running an 18 V drill on 24 volts and it is spry, but I watch for overheating and understand the commutator might go out quicker.
The drill is still running fine on 18V and I've posted a second hack on how to build an adaptor for the newer type of 18V batteries that I got with another set...enjoy and keep on experimenting!
in a vehicle the part that uses the most current is the starter which is a high power dc motor, vehicle batteries have a spec called the CCA or cold cranking amps thats the current it can put out when starting the car. usually car batteries have a CCA rating of 300-400A. thats why the mechanics use such a heavy cable for jump starting your vehicle from another battery (the thick cables have very low resistance to allow for the large current to flow, else instead of starting your vehicle the cables would be burning)
1 W/hr = 1 V * 1 A/hr