this is my first instructable.

PORTABLE AMPLIFIER 10W USING 9V 1100mAH BATERRY

, so please rate it :)

mine work great

PORTABLE AMPLIFIER 10W USING 9V 1100mAH BATERRY

, so please rate it :)

mine work great

R1 : 6 Ohm

R2 : 220 Ohm

R4 : 10 KOhm pontesiometer

C1 : 2200 uF / 25V

C2 : 470 uF / 16V

C3 : 470 uF / 16V

C4 : 100 nF

IC1 : TDA 2003

Heatsink for TDA 2003

Female jack: 2

male jack :1

9v 1100mAH battery

case

PCB

swicth

R2 : 220 Ohm

R4 : 10 KOhm pontesiometer

C1 : 2200 uF / 25V

C2 : 470 uF / 16V

C3 : 470 uF / 16V

C4 : 100 nF

IC1 : TDA 2003

Heatsink for TDA 2003

Female jack: 2

male jack :1

9v 1100mAH battery

case

PCB

swicth

nice one<br> but <br>1-did you built the circuit on any simulation software?or just did it directly on the board<br>2-also that is this circuit from the datasheet? if not how did you manage to make it directly? please reply

1. no. i got this circuit from electronic-lab.com.<br>2. usually the circuit also can be found in the datasheet.<br><br>sorry for late reply

Before constructing this i would like to ask a few questions.<br>1)Will this work with a 12v power source?<br>2)Can i use an AC power source with this amp?

sorry for late reply..<br>1. yes you can use 12v DC power source.<br>2. if you want to use 12v AC power source you have to use bridge diode. to convert from AC to DC.<br>but if you want to use 220v or 110v (or higher than 18v) you have to use an Adaptor. to convert from AC 220v or 110v to DC 12v.<br><br>to get more information. search on google TDA2003

Capacitor C3 is 470nf

can i use TDA 2030 transistor for that diagram??? plsss i need an immediately answer for that........

maybe work, but i've not try it if you are looking for the datasheet u can visit <a href="http://alldatasheet.com">http://alldatasheet.com</a><br>

What for case do you use and why do you not a speaker in your case.<br />

i use cassette box.<br /> because i want to listen on my headphone.<br /> <br /> thanks for your respond :)<br /> <br /> I'm sorry too long reply<br />

Can you put a better photo in how to wire to the jacks because or tell me how to wire the jacks because they have 3 contacts and on the IN and OUT are just 2 or tell me if is a mono amplifier.. please respond someone!<br /> <br />

yeah, this is mono amplifier. and i only have stereo jack<br /> <br /> thanks for your respond :)<br /> <br /> I'm sorry too long reply

Nice guide but i think your math is wrong.
In order for this to be a 10W amplifier, that 9V battery would have to be putting out 1.1 Amp, which im sure a 9V battery is incapable of delivering.
Also the fact that the amplifier isnt going to be 100% efficient. :P
I did a google search and found a couple people saying that a 9V battery can provide 150mA for around 3 hours, which would make this a 1.35W amplifier.
Unless im missing something here (?)
on a side note, could you post the schematic if you have it?

I think 10 watts is the max that the chip can handle, were you to have a really loud input, and using the maximum voltages for the power supply.

yes i can,
R1 : 6 Ohm
R2 : 220 Ohm
R4 : 10 KOhm pontesiometer
C1 : 2200 uF / 25V
C2 : 470 uF / 16V
C3 : 470 uF / 16V
C4 : 100 nF
IC1 : TDA 2003

oops down is DC -
:)

yeah but, now i used 9.6V 1A battery.<br/>sorry i don't have the schematic, i got it from <br/><br/><a rel="nofollow" href="http://www.electronics-lab.com/projects/audio/016/">http://www.electronics-lab.com/projects/audio/016/</a><br/><br/>maybe later i want to make the schematic<br/><br/>

Watts as applied to audio aren't the same, but I'm not going to try to explain it because I can't remember well enough myself.
L

ok, i figured as much, ill go do a search on google for it.

I did once - a lot of maths in it if I remember...
L

rms Power = V<sup>2 / 2R</sup><br/>where V is the peak voltage and R is the resistance of the speaker.<br/>so.... Prms = 81 / 8 (for a 4ohm speaker) = 10.125 Watts<br/><br/>rms Current = I / root(2) where I is the peak current<br/>peak current = V/R = 9/4 = 2.25 A (for 4 ohms)<br/>so... Irms = 2.25 / root(2) = 1.59 A<br/><br/>I think he has done his calculations right but is just using the wrong power supply. Obviously a 9V battery will not be able to source that amount of current for any length of time so if you try to turn up the volume to a point where the amp would be putting out 10Watts the sound will probably be very distorted because it can't deliver the power<br/><br/>Take a look at the datasheet for the amp anyways it's targeted at a car amp and a car battery can put out hundreds of amps.<br/>But theres nothing wrong with using it as a portable battery powered amp, you just wont get the volume you would if using it in a car<br/><br/>Datasheet >> <a rel="nofollow" href="http://www.st.com/stonline/products/literature/ds/1449.pdf">http://www.st.com/stonline/products/literature/ds/1449.pdf</a><br/><br/>Anyways nice instructable !<br/>But a circuit diagram would be helpful for people who like to make their own PCBs or breadboard it first.<br/>

rms Power has come out wrong in my last comment.<br/><br/>should be = (V<sup>2) / 2R</sup><br/>

OMG !
(Voltage squared) divided by (2 x R)

i am trying to mack somthing like this cant u find a pair of head phones cut off the buds a replace them with a speaker????

A little error: the( +DC )to down on schematics is really (-DC).Great Instructable ,essential idea !I like!

haha oops, - DC is down, you are right
thanks

Looking at the datasheet (http://www.st.com/stonline/products/literature/ds/1449.pdf) page 4 figure 3. Max output power with 9v power supply (lets think that battery's voltage is constant 9v) is 2-4.5W, when using load between 4ohm and 1.6ohm<br/><br/>Lets pretend there isn't any voltage drops:<br/> 9V = +4.5V and -4.5V.<br/>P = U<sup>2 / R, 4.5V / sgrt(2) = 3.2V</sup><br/>3.2V <sup>2 / 4ohm = 2.6W </sup><br/><br/>Same with 18V power supply<br/><br/>18V = +9V and -9V<br/>9V/sgrt(2) = 6.4V<br/>6.4V<sup>2 / 4ohm = 10.2W </sup><br/><br/>Little rounded numbers, but will do.<br/><br/>Someone correct me if I'm wrong with those calculations, but datasheet has "real" values on diagram.<br/>

thanks for your opinion :)

Anyway, your amplifier looks good and seems like it's size is perfect for portable applications.

thanks