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PB = push button switchTB = TEST POINT
OMG!!!!!! sorry :(i mean Series
yes you cam make .22uF by placing capacitors in parallel but NOT SIMPLEif c1 is .33uF and c2 is 1uFTotal capacitance = c1c2/c1+c2= 0.24812 uF
yes! but not safe
1) try to find sum from old electronics2) use 100 Ohm 5W3) need more informations?
Grate bro :)
Thank you for your positive feedback :) that's my trademark ;)
$28 for this circuit?!!!!!! I Can't Believe Iti just need 5$ for make this item
yes if you are Donald Trump ;)
a man made a working and good looking circuit without any type of formal education in electronics is a bravery ????YES I AM BRAVE :)vina
Thank you for your positive feedback :)
i said you can,not you must.when the extra battery is fully charged i will disconnect it from the circuiti am not a "fit it forget it" man every day i check the batters :)
YES! that is electronics;) just like a tiny transistor that changed the world of electronics
Thank you for your first positive feedback :)do to some technical and time limitations i can't add more videos and details
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Thank you for your positive feedback :)Yes you can !!!
DIY AUTOMATIC SOLAR CHARGE ...View Instructable »
any thing under 4Kw :)beware!! not use with any device that use an IR remote
it's a switch.you can replace any ordinary switch with this IR switch
put 5 volt hear :)
+ve means positive. usually a red or white wire & -ve means negative. usually a black wire.use a multimeter to ensure the polarityIR REMOTE CONTROLLED SWITCH - 5 VDCAUTOMATIC WATER LEVEL CONTROLLER - 12VDCAUTOMATIC NIGHT LIGHT - 12VDC
Yes You Can!TSOP1838 and 1738 are same.18 series comes with small size package
hello kavish laxkarits a god idea :)but success of this device is heavily dependent on the current that can produced by the solar panel .if the solar panel can't produce more than 700 mAh current this device will become useless if solar panel can produce 700mAh you will take 4 to 6 Hr to fully charge a 3000mAh battery.you can avoid this by replacing that linear regulator with a buck converter like DC-DC Converter Step Down buck Power Supply Moduleit will convert 12v 700mA to 5v 1A (theoretically)
OK i got it. that's the problem.a MOSFET without heatsink just like you put it in a oven. you must use a heat sink to cool down the MOSFET (just like my design or better)IRF540 and IRFZ44 are have very high temperature range up to 175 cbut IRF630 only have 150c.that's why IRF540 survive the second test.you can use IRF540 for light loads.but IRFZ44 can handle more loadup to 60W in your case
heating MOSFET is not a big problem but check all connections one again.these are main error indications i find in my test1) one MOSFET is hotter than other one2) output load is blinking(if load is light)3) transformer became very hotIFPZ44 is better than IRF630 and 540
Ah means ampere-houra 6Ah battery can give 1A current for 6hourse
if you want to light up a 15w bulb you need at lest 15w inputthat means you need an input of 12v at 1.4A(12 x 1.4 = 16.8W)100% is a jock.that means you need at lest 12v 2A input for get 15W outputuse a 12v 6Ah battery for your project like me
NO just because both are used for different purposes
Q3:yes, may be.water is not a poor conductor of electricity.the impurity and minerals are give the conductivity to water.may be filtered water can't conduct the tiny current given by the circuit.update:now i am trying to use a safer version of AWLC without touching water with probes or wires sooz i will fins a soilution
sorry buddy.i don't know how to wire up a Submersible Pump jut because i cant find submersible pump near to my home.may be a local electrician can help you to wire up
i am sorry from the bottom of my heart :( i am busy with "call of duty" ( not the game.i mean the job)Q1 :i think, maybe there is an issue.the the circuit detect very minute current in the water.so maybe WLC get confused.try a test yourself :)Q2:yes.you can use same PS for 2 circuits f your power supply use same voltage and plenty of current .but in your case,you are going use 5v 1A power supply to power up 9V Indicator and 12v AWLC same time how is this possible?
thank you for trying my circuit :)
this circuit only use 30 mA at idle stage and 250~300mA at full load(relay is on)so you can use 12v 500mA power supply.avoid using LEDs as indicator, they need 30mA current or use 1A power supply.
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