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Electronic Box Lock Help!? Answered

OK so I would like to use a solenoid to unlock a box from the inside, problem is the electronic circuit I designed inside the box operates on 3 vdc and as far as I can tell most solenoids operate on a voltage of 6-24 vdc. Is there any way to make a simple driver circuit for a solenoid so it can operate on 3 vdc? 

Below is a copy of the box's circuit so far. I would like the solenoid to be in parallel with the "puzzle solved LED."

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steveastroukBest Answer (author)2012-01-30

There's no reason why this couldn't work with 6V. You also MUST PUT A RESISTOR IN SERIES WITH THE LEDs.

Steve

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TXTCLA55 (author)steveastrouk2012-01-30

OK, thanks. what Ohm rating should the resistor be? The LEDs draw about 3 volts.

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steveastrouk (author)TXTCLA552012-01-30

Things don't "draw" volts, they "draw" current...How many milliamps do they need to light up.

That's quite a high voltage for yellow/green leds. I would have expected more like 1.8V, and around 20mA of forward current. On 6V, 150 Ohms should work OK

Steve

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TXTCLA55 (author)steveastrouk2012-01-30

OK Thanks Steve, I'll give it a try.

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Re-design (author)2012-01-30

It looks to me like you could unlock it just bu turning all of the switches to on.

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TXTCLA55 (author)Re-design2012-01-30

Yea its is possible to open it by flipping all switches. I've built in a key slot so that it will only turn on if a certain key is inserted.

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Re-design (author)TXTCLA552012-01-30

Turn some of the switches so that up is off and some so that up is on and then you have to know the combination to open it up.

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TXTCLA55 (author)Re-design2012-01-30

Ah I see, good idea, I am not sure if I can do it though,,,Some of the wires connecting the switches are tight as it is.

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