How can I multiply/double (or just increase) voltage in a DV 5v curcuit ??? Answered
ok i have the following parts to ue for this: (all leftovers from former project..)
1x mosfet IRF510 power transistor 5,6A 100V
9x 2N3904 amplifier transistors 40V 0,2 A .0.625 W
~16x 1uF capacitors 50V
~99x recifier diodes 1A 50V
~35x 2k resistors 0.25 W
the idea is to charge a battery pack consisting of 4x 1,2-1,25V = 4,8-5V 3000mah AA nimh batteries using my 5v usb wall charger that has 1A output!
i tried connecting the battery pack directly to + and - and 'i think' its starting to charge but after 1-2 hours at full rate (5v 1a) it should be at least 50% charged (3 hours would be full charge -> 5W x 3 = 15W), but if i connect them they last for about 2 -3 minutes and then empty again!!
so after this im concerned that i might need at lest 6V-10V to achieve the desired effect !!
-> charge 15W NIMH batterpack with wall charger (nokia ac-60e.. 1-1,5A) i nless than 3 hours (as like a phone would need !!)
therefore i need a cuirciut (ONLY DC) to double my 5V OUTPUT to 10V (yiou shouldnt apply more than twice the curent of a batter pack)
or ideally 6-7 V but i dont know if thats possible without a swiching IC or more different resistors.. so just doubling would be nice at the moment!!