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I need help in understanding faradays law? Answered

So this is where i was trying to understand his law, http://www.6pie.com/faradayslaw.php, the part that i got stuck was on where it says, "Lets figure 5 turns per second, that gives us 300 RPM. If we do a good blade design we might be able to get 300 RPM in 3 to 5 mile winds.

5 turns per second gives us one turn every .2 seconds
seconds = .2"

I am trying to apply this to a bike and want to know how to get past this step to getting Δt of the formula.

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steveastroukBest Answer (author)2012-07-29

5 turns per second = 1/5 seconds per turn ....0.2 seconds per turn.

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diabloboy (author)steveastrouk2012-07-29

ok that makes me understand how you get 0.2 but how does that relate to 300 rpm?

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steveastrouk (author)diabloboy2012-07-29

What do you mean "relate to" ?

Something spinning at 300 RPM is spinning once every 0.2 seconds. Or 5 revolutions per second, or 60*5 revolutions (300 RPM) or 60/0.2 = 300 RPM.

Steve

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canucksgirl (author)2012-07-28

I didn't look at your link but the part that you quoted seems just like simple math to me...

5 turns per second. 60 seconds per minute. 5 X 60 = 300.... or 300 RPM (Revolutions per minute).

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diabloboy (author)canucksgirl2012-07-28

You perhaps told me the rpm but i dont think thats how you get rpm due to this tutorial I've found(http://www.ehow.com/how_6088311_calculate-rpm.html) however i need to know how to get Δt of the formula in which the Δt of the example equals 0.2 (Δt=0.2).

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canucksgirl (author)diabloboy2012-07-29

This is probably the simplest answer I could find for you...

Faraday's Law: V = -NΔφ/Δt . Here N is the number of loops, Δφ is the change in flux, and Δt is the time required for the change.

So the "time required" for one full turn in the example is 0.2
(5 turns per second gives us one turn every .2 seconds)

How you determine what your number is depends on the RPM you have.

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diabloboy (author)canucksgirl2012-07-29

so if rpm is known, how is the formula represented Δt= ?/rpm or Δt=rpm * ?

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diabloboy (author)steveastrouk2012-07-29

both of them still work but thanks you two :).

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canucksgirl (author)diabloboy2012-07-29

No problem. Just don't forget to click one of the blue button's (Steve's). It will mark your question as "answered" and then people like us will stop posting comments. lol :-)

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diabloboy (author)canucksgirl2012-07-29

Okie doke :) wish i was able to mark you both but if you insist:)

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canucksgirl (author)steveastrouk2012-07-29

Doh! That looks much better than my sad attempt at an equation at 2am... o_0

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steveastrouk (author)canucksgirl2012-07-29

I just cut and pasted.....
GoodNIGHT.

Steve

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canucksgirl (author)steveastrouk2012-07-29

I wish I could....

Sciatic nerve pain... can't lay down to go to sleep. Got the laptop with me on the couch with an ice pack. 

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steveastrouk (author)canucksgirl2012-07-29

OW. Sorry to hear that.

Steve

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canucksgirl (author)steveastrouk2012-07-29

Thanks.

BTW... I sent a reply. I think the filters got it... *sigh*

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canucksgirl (author)diabloboy2012-07-29

In the example, they've explained that...

They figured out they could get 300 RPM (revolutions per minute)

300 divided by 60 seconds in a minute = 5 full revolutions per second.

But you want the time it takes for ONE full revolution (not 5).

So 1/5 of a second = 0.2 seconds. (The time it takes to complete ONE full revolution).

As an equation, I think you need something like this: Δt = 1/ (RPM/60)

Δt = 1(second) divided by the RPM divided by 60

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steveastrouk (author)canucksgirl2012-07-29

Δt = 1/ (RPM/60)

= Δt = 60/RPM, by definition.

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diabloboy (author)canucksgirl2012-07-29

thank you thats what i was looking for and seems about right

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canucksgirl (author)diabloboy2012-07-29

I'd go with Steve's equation.... (and give him the best answer credit). ;-)

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canucksgirl (author)diabloboy2012-07-29

You're welcome.

Don't forget to click one the blue buttons so that it marks your question as "answered" on the main page. :-)

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