A Simple Current Amplifier

by robot1398

28K149

Intro: A Simple Current Amplifier

a amplifier of current . when we touch the wires it glows but without the circuit it will not glow brightly.you can make it on a pref board or without it i am making it with a pref board.

STEP 1: Things Required

things required-
1] 560 ohm resistor
2] NPN transisor
3] led
4]9v battery
5] battery snap

STEP 2: The LED

you can use a diffused led if you want much of a glow . if you want a beam of light use a water clear type.

STEP 3: The Circuit Digram

solder the circuit with the circuit digram.

STEP 4: All Done!!!

you have made your current amplifier.
touch the both touch wires and the led glows brightly
without the circuit it will be very dim.

STEP 5: Update

solder a 100k resistor between the base of the transistor and the touch pad

10 Comments

vina1991 8 years ago

its a current amplifier?

MechackM 8 years ago

I want to amplify current from as low as 21ma to 750ma using a 5volt battery. Please assist me

ReallyMoanViolin 9 years ago

This is the current amplifier?? this is only a switch transistor.

Gernerakos 11 years ago

Is any PNP transistors work with it? I'm using a bd 241c.

samalert 11 years ago

I tried making music sync LEd but the strip am using dont blink with great intensity they get max of 5v where they need 12v

Now what i need is your circuitry to amplify the current.

Can you please let me know if i can use yours to get max of 12v also what type of transistor or resistor to use to safeguard my LED strip and not burn my CAR

robot1398 11 years ago

any npn transistor will do I uses bc547

Rockser11 13 years ago

thanks, im building an ipod base out of a coke can and this will be very helpful

simmer65 13 years ago

Be prepared to burn up your transistor if you try this circuit. My NPN transistors have a max Base-Emitter voltage (Vbe) of 6 volts. This circuit will send way too much current through the base.

If you want the LED to glow, remove the transistor and reduce the resistor. You will get about a 2v drop across the LED and 7v across the battery. To achieve a 50mA current (the brightness of an LED is determined by the current through it), use the equation V=IR or 7 = .05 * R......R=140 ohms.

zazenergy 13 years ago

This is a good, simple experiment for an electronics enthusiast. Thanks for sharing!