I need help with this statics question, because it seems easy enough but I know I am not doing something correctly. Look at the picture and use it along with the question, which says; Four forces and a couple act on the beam. The vector sum of the forces is zero, and the sum of the moments about the left end of the beam is zero. What are the forces Ax, Ay, and B? Ax is of no importance, it can be anything because it does not affect the moment because it line of action intersects the point of rotation, so i don't care about it. So it would seem to me that the 800N force multiplied by the 4m, gives 3200Nm plus the 200Nm from the couple makes 3400Nm, and since it has to be counteracted by B, it would be divided by 7m which equals 485.7Nm. But what is Ay? It seems to me it can be anything, as long as B is adjusted accordingly to account for it, but I think I need an actual value. Is Ay suppose to be part of the couple, because if it is it would have a value of 25N which would factor into the 800N because that force lies on the same place where the other portion of the couple would be. So would 25N be Ay because it says in the question that 4 forces (800N, Ax, Ay, B) AND A COUPLE, which it makes me think that Ay isn't part of the couple?