Hey its about time i post some thing and since i got a ss coaster i figured id try it out the station is almost done and all i need is a curve part to it (pics will be up around 4)
Topic by knexsuperbuilderfreak 9 years ago | last reply 9 years ago
I have a a AOS Safety respirator with P100 cartrideges and i think it is time to replace the cartridges, i have used it for hobbies when airbrushing, lathe working, fiberglass sanding, and enamel spray painting. How do i tell when the cartridges need to be replaced? Also i was wondering, would it be possible to convert it to a forced air respirator, by taking an old pair of cartridges and cutting out all the filters and stuff and attaching to air hoses, one to each cartridge and using dryer duct alluminum tape to make it air tight. Then attaching some type of fan to it, or attach it to the houses a/c vent? Would this work?
Question by snowluck2345 9 years ago | last reply 9 years ago
Hi, im looking for some help with a physics/engineering type problem. Im looking for the most effective method of tranfering a mechanical force from one direction to another. For example if i had a 1" horizontal rod struck on its east face which then begins to travel westward on a fixed horizontal track, im looking for a method of transfering the energy (not sure if thats the right word) in the opposite direction. A few important factors are that the rod which is struck does need to travel around 4 inches on the fixed rail, and any vertical movement needs to be kept to a minimum. Below is one of my early ideas, serves little pupose as the mechinism is too large but gives you the jist of what im talking about.
Question by Squibo 9 years ago | last reply 9 years ago
Hi All, I do understand we all keep creating new electrnoic tools/gadgets everday. But anyone had tried to create a tool which can measure force / intensity of human punch. It is fun to measure your punch force among friends. also if help us to improve your boxing strength. Please share your thoughts on it. Thanks
Topic by VinitV 1 year ago
i want to throw a 30-40 kg opponent robot in a robowar in air! i wanna lainch it in air, that is the attack strtegy am using...please help me to find th e force required to do that. thanks in advance!
Question by sarathjulius 9 years ago | last reply 9 years ago
Hi,I am trying to figure out maximum linear force I can produce with an electric motor through use of lead screw and nut. I have come up with an equation which seems correct but resulting forces are way higher than my intuition believes is correct.I tackled the problem from the perspective of energies:F' * p = M/r * 2*π*rlinear force * thread pitch = torque / radius [M/r = force at radius] * circumference of lead screwF = 2*π*M/p * (1-k) //k stands for coefficient of friction between lead screw and nut)Radius falls out of equation, which seems fine as force is provided by torque, which is radius agnostic. I used a 7€ stepper for source of torque which can provide 0.42 Nm of torque and a lead screw with 8 mm pitch and 4 mm radius, I assumed 15% losses. My equation tells me that such system can provide 280 N of force, which seems wayyy too much for a cheap motor.I have attached a python code that calculates linear force in case it helpsCan someone tell me if my equation is either correct or flawed?
Topic by ptkrf 7 months ago | last reply 7 months ago
Hello :D i am trying to find a episode of the television series Spy-force- Episode 41 ( i think), named "the trail" (or something similar) if anyone knows where i can find this or can give me a link,etc, please post thanks AAG
Question by AussieAnglerGal 6 years ago | last reply 6 years ago
I'm looking to make a "floating" model by insetting NdFeB rare-earth magnets with same poles facing so they repel. Now, magnet selling places specify the "pull" a magnet might have, say 1.2kg. What I would like to know is if the repel is equal in magnitude as the pull if two similar magnets are placed with same poles facing, is the force exerted 1.2kg and so I could float 1.2kg of stuff? Also, does stacking magnets double the attractive or repelling force, i.e. do two 1.2kg magnets stuck together lift 2.4kg of stuff, negating the small difference in distance of one magnet from the object? Is there a way to calculate the distance between two opposing magnets with a force applied. Does it follow the inverse cube rule? And if the stacking does work, do I also need an equal number of magnets on the other side for repelling, i.e. a stack of two 1.2kg magnets repels 2.4kg with one 1.2kg on the other side, or not? Does the magnet on the other side have to be the same force? Lots of questions but hoping someone can shed some light on this as I've not been able to find anything about it :-(
Topic by chiok 10 years ago | last reply 3 years ago
The problem is that almost no one has enough room inside to shoot a knex gun unless it's a total peice of ....you get the point. But, by going outside there are many other vaiables that effect how far a gun can shoot (eg. Wind direction/ speed, trees and other obstruction, etc.) Also power as in "can shoot through can" or "through 3 sheets of hard cardboard" can also be misconstrude in the way that range from the can is a main factor, point blank range is not always the most powerful range, often 1-3 inches away has exponentially higher power. What needs to happen is a tool be built (out of K'nex, what else?) that is not only easy to use but impossible to mess up, it should be able to give 100% accurate reading for all types of guns from the weakest to the most powerful. Also in terms of different types of ammo, rod size shouldn't matter( thats what she said) the only thing that should matter in terms of ammo is whether it is deer slug, rod, sligshot/ catapult rod(a rod with something the can grab the elastic), or other and specify what that is.Range is all to often streched beyond reality by saying it can shoot 200 yards, when really it might be able to shoot 50 yards tops when pointed strait but 200 yards if it is pointed strait at the sky. We need to bulid a target that you shoot from maybe 5 feet away and something mesures force, be it cardboard, or cans, or plywood, maybe even something that leaves a dent in it and you can mesure the depth of the dent to tell you how much force (eg. 1/2"=1, 1"=2, 1 1/2"=3, etc.)Also one last idea if you would prefer to stick to range outside, is that you divide the range in feet, by the number of cardboard sheets(or other medium)the gun can shoot trough at point blank range (say it shoots 63 feet, and through 4 sheets of thick, corrugated cardboard the equation would be F= 63/4= 15.75, so your force rating would be 15.75)These are only some ideas to get all of you thinking about a standard in K'nex gun power.-TheXenk
Topic by TheXenk 10 years ago | last reply 10 years ago
Oh yeah. Bill Gates didn't go to work today.He doesn't work for Microsoft anymore....Even if you're not a Microsoft fan, you have to admit, without Mr. Gates, where would the computer industry be? Where would we be?Flash back time:Ah, yes, I remember my very first personal computer... It was a Hewlett-Packard (not an "hp" ;-) with a MONSTER-sized monitor that took up a good 3/4 of my desk, a clunky keyboard and a "ball" mouse. It was running the latest OS: Windows 95. And get this: we were the first people on our street to get this new thing called the "World Wide Web" - whatever that meant. Our Service Provider? MSN, of course! Man, with my new computer (okay, in truth, it was a hand-me-down from Dad), I was the coolest 6-year-old in kindergarten. I had it made.Yeah, MS has made a a few mistakes...*cough*Vista*cough* (doesn't that go without being said?), but Gates and his company really did shift the industry into gear, and they aren't stopping any time soon.So, gentlemen, I ask you to join me as I tip my hat to Mr. Gates. Without him, I don't know who I would be.
Topic by Labot2001 10 years ago | last reply 10 years ago
I think it's pretty sad if you can suddenly not look at secondary pictures, or some pages of an instructable, without being logged in, if this pathetic behaviour continues I will have to un-register and stop visiting.
Topic by Whatnot 10 years ago | last reply 8 years ago
Does magnetic force affect how much energy is multiplied by per section in a voltage multiplier like the one in this instructables: https://www.instructables.com/id/Build-a-Variable-High-Voltage-Power-Supply/ ? I was thinking of making this multiplier and to make it a bit more variable to make a voltage multiplier (electro-magnets around the capacitors) like the ac voltage muliplier on sparkbandbuzz.com
Question by pmk222 6 years ago | last reply 6 years ago
Is it possible in the technological day and age to force a computer controlled automatic transmission to start in a higher gear like second. About 90% of people will never need this, however out on the farm in a big diesel truck with 800lbs of torque you need it. By starting in a higher gear it allows us to get through snow much better and this becomes extremely difficult with an automatic transmission. Sure we can set the highest gear it will go into, but we can't lug through the snow and mud like we would like to. Do any of you know of a chip out there already, or one you can make that will let you pick and chose your lowest gear.
Question by jj.inc 6 years ago | last reply 6 years ago
Great news! Autodesk and MakerBot Industries are working together to take personal design and manufacturing to the next level. Now you can simplify the process of printing your 123D designs directly to a MakerBot Replicator. Soon, you’ll be able to purchase MakerBot 3D printers through 123Dapp.com. If you sign up for a 123D Premium membership today, you’ll also receive a special discount that you can apply towards the purchase of a MakerBot 3D printer.
Topic by kazmataz 6 years ago | last reply 6 years ago
I am repairing broken locking mechanism in the door of a dishwasher. Of course there will be a bit of force involved when pressing the handle and the dishwasher will heat the water which can melt the glue. What's your opinion? Should i use it??
Question by Karletto555 9 years ago | last reply 8 years ago
I am hoping to create a circuit that will variably control the speed of a motor through pressure. If I were to wire up one of these http://www.adafruit.com/products/1075 , simply as the switch between a small motor and a power source around 5v, would it work to simply turn the motor off at rest and vary the speed with pressure? Is there a way to use this resistor as a "switch" without using an Arduino or other micro controller? Any help is appreciated. Thanks!
Topic by Flashflint 4 years ago | last reply 4 years ago
He even resulted to physical force. She is really mad about it but i don't know what i should do. i am never bad, i think i set a good stage for myself, i behave and all around him, but it's getting on my nerves.
Question by PyroMaster007 10 years ago | last reply 9 years ago
As reported in Physics World today, a team of Swiss and Dutch physicists have developed a novel tip for an atomic force microscope (AFM) using a single carbon monoxide molecule. The tip is stable enough to image individual atoms and bonds within molecules.The first image below is from the group's AFM of a single pentacene (C22H14) molecule on a copper (Cu(111)) substrate. The second picture shows the conventional chemical structure diagram (the vertices are carbon, and one hydrogen hangs off of each exterior corner), and the third is a "ball" model, with carbon atoms in black and hydrogen in white. As discussed in the article, the whole molecule is just 1.4 nm long, with a spacing of 0.14 nm between adjacent carbon atoms.The paper is out in today's Science, but it's pay-per-view.
Topic by kelseymh 9 years ago | last reply 8 years ago
Dear All.. If two coil A and B without iron core same as (size) dimension and but coil A winding with 28 gauge and coil B with 32 gauge magnet wire Please help me to know : What is name coil more force for attract a piece of ion metal. Many Thank you Best regards lam
Question by lam 3 years ago | last reply 3 years ago
I am new to posting questions in forums so please forgive me if I break any rules. I am trying to build a simple parallel circuit to light up 24 LED's with a simple battery pack with 2 AA batteries. I would the lights to come on when a baby touches 1 or more of the 4 Force Resistive Sensors that I will be using. I would appreciate any guidance with building this circuit, any any schematics that would help. I have limited electrical/electronic knowledge. Thanks for your help guys. Cherrick Gordon - The babymaster.
Topic by babymaster 6 years ago | last reply 6 years ago
I am a quadriplegic and paralysed from the shoulders down. I am working on a project to allow me to control a go kart. I have limited use of my arms which should allow me to control the steering but I am trying to get another degree of freedom to control acceleration and/or braking One of the ideas is to use a piezoelectric type force transducer in the mouth to control and acceleration via an arduino or similar. The transducer would detect bite force and it would be converted into control signals for the throttle and/or brake. It would be embedded in a gumshield and it would be acceptable to have a cable coming from the front of it to the control System. I am wondering has anyone worked on such a project and could anyone point me in the right direction please. The gumshield may end up looking something like the image here.
Topic by greenonyx 5 years ago | last reply 5 years ago
.The French administration is slowly replacing Microsoft's products by open sources solutions.It started few years ago, 2005, with OpenOffice, then with Mozilla.And now, the French Gendarmerie (paramilitary forces) plans to replace Windows XP by Unbuntu Linux.http://afp.google.com/article/ALeqM5iU4Lq7tOR_WVOJLZ3IeRaIH03x6wThere are three reasons behind the move [...]. The first is to diversify suppliers and reduce the force's reliance on one company, the second is to give the Gendarmerie mastery of the operating system and the third is cost [...]The move away from licensed products is saving the gendarmerie about seven million euros (10.3 million dollars) a year for all its PCs.The 70,000 desktops of the French Gendarmerie should be 100% Linux by 2013-2014.This is, again, a proof that Linux solutions became mature enough to compete with Microsoft Windows.Dell now sells computers with Linux instead of Windows.OLPC and EEEPC use Linux.Several administrations around the world are seriously planning to move to Linux and Open-Source.Is this is the beginning of a new era ? How many administrations around the world will abandon Microsoft too ?How long before buying a computer with Linux sounds like a serious option for a majority of consumers ?I wonder if Microsoft really feel worried about that ... =o)
Topic by chooseausername 11 years ago | last reply 10 years ago
Hello! I am making a prototype of a force sensitive resistor, and i am using, to old 97%kobber coins, metal sheet and a tiny piece of conductive foam that i got from a tv-repair shop. The setup is not very good, but its a start, and i am planning the next move for better results... Now... I want some decent understanding of how the readings work, and why I get these results.. First test, are written with black, and and as you can see it, has the same amount of space between 0-1kg and 1-2kg, but 2-3 and 3-4 changes to a very small space? Why is that? Second question is, that i have used the x10, to read larger forces. 0-2,5kg and 2,5-5kg has same amount of space. Will the space decrease too, when getting further up the scale too? - I know the conductive foam has its limits too, but just to be clear of my readings. Thanks in advance! I hope you can see the readings on the picture..!
Topic by L33boy 4 years ago | last reply 4 years ago
There are a lot of people out there that find magnetism fascinating but have no clue what it is and how it really works and I'm one of them!
Question by jakemaur 8 years ago | last reply 8 years ago
I would like to build a "force lightning" glove. Purely for show, no arcing over great distances, not looking to "throw" the lightning, just have it crackle around the hand and between the fingers. Any suggestions where to start would be greatly appreciated.
Question by seabeejojo 8 years ago | last reply 1 year ago
I am sorry for my very difficult question. I would like to make an inexpensive Atomic Force Microscope. Can you help me? Thanks.
Question by VPA 10 years ago | last reply 4 years ago
Hi, I'm helping a team of students make a brake-assist device for a two-wheeled walker. We were wondering if there are mechanical brakes out there that apply a force proportional to the speed. A circular damper, is how we would describe it, I think. Or something like a gas shock (the things on screen doors and car trunks) but with a circular motion rather than a linear stroke. Anyone have any ideas? Anything that's commercially available, small, and somewhat inexpensive is fair game. Bonus points for things that can be made by hand.. Thanks!
Topic by _mattb 9 years ago | last reply 9 years ago
I am building a camera rig, and I would like to be able to accomplish very fluid movements with it. I have seen all kinds of existing camera rigs, but they all seem relatively static in one way or another. Simple bi-directional movement is alright, but something capable of vertical, horizontal and rotational movement would be preferable. If you push downwards, the camera moves upwards - that kind of thing. Even a material that is semi-flexible would work, as a rod to attach the camera to that would provide some sort of resistance, and a position to snap back to. I'm not looking for the whole design, just a starting point if anyone has any ideas about something that already exists that sounds like what I'm saying.
Question by epizeuxis 5 years ago | last reply 5 years ago
Question by PKTraceur 10 years ago | last reply 10 years ago
Hey guy! Sharir1701 here and I just want to start off by saying that I'm not back into Knex warfare, but I have something to show you. About a year and a half ago, I posted this forum topic. There I explained why, in my opinion, just adding more rubber bands to a gun will not actually produce an overall better gun (past a certain, low point). I'm not getting back into that discussion, but I simply wanted to share something regarding that. Don't ask me how or why (I don't know, myself), but a few days ago I suddenly remembered that old assumption I made. Being a perfectionist, I hate leaving things unfinished or unexplained (particularly math and physics related inquiries). Back when I posted that topic, I had little to no formal Physics knowledge, and the beginnings of an understanding in mathematics. Now, I have a much broader understanding, much more knowledge, and an ability to explain and evaluate what I once couldn't. Anyway, what I'm trying to say is, back then, I didn't have the tools to prove my claims. I firmly believed in them, but I couldn't confirm them. It's nothing complicated, but, like I said, just something I'd like to share. I also want to point out that, although I personally don't enjoy spending days upon days perfecting a little plastic mechanism for firing (mostly) non-aerodynamic plastic projectiles, anymore, there still is a warm spot in my heart for the craft I once loved. More to the point - this is a small article just showing something I did in a few minutes the other day, that helps me to better understand how a Knex gun works. I hope that in writing this, more people that are still building guns, will think about more accurately calculating certain things about their guns to help improve their performance and hopefully produce more efficient guns. The final note I have is that I'm about to show you equations, all of which can be plugged with real, measurable numbers, to calculate to a high degree of accuracy, the forces at play. This means you can actually calculate the most efficient layout for a gun, and also that in designing your next, you will be able to use these equations, and many others, to find optimal solutions to your problems. So, what's all this fuss about? Well, basically, I just proved with a few, painfully easy equations that my conjecture about the forces in a gun, working on the pin, is true. I'll just get to it: First, Hooke's Law states that the force necessary to change the length of a spring or a (tense) rubber band is F=K*dX, where F is the force, dX is the distance you want to change, and K is a constant number, that each rubber band (or spring) has. You can quite easily measure both of these. For rubber bands connected parallel to each other (assuming they are the same type of rubber band, which ever is your chosen standard), this equation becomes F=K*dX*N, where N is the number of rubber bands used. dX and K are both constant in the regards of the pull of a pin on a standard Knex pin gun. Therefor, the amount of force required to cock a pin (pull it back to it's full length) is linearly correlated to the number of bands you put on your gun. Next, if we examine Newton's equation of work and energy, W=dE=F*dX, where W is the work, dE is the change in energy in your system (input from an external force, i.e. your hand), F is the force applied along a length of movement, and dX is that length. Let us define the base position of the pin (not cocked, minimum tension on the rubber bands, fully in the barrel, etc.) as having 0 energy. This then means that the work applied to the pin by cocking it is equal to all the potential energy it has. From this, plugging in the force, we get Ep=K*(dX)^2*N. Let us assume a perfect world, where we neglect the effects of friction and air resistance, and assume all the momentum of the pin is transferred into the bullet as it fires (I will briefly mention in the end, why everything we're neglecting here just strengthens my claim in reality, but let's continue for now). After being released (in other words, shot), the maximum velocity the pin reaches right before the end of it's journey can be found using the equation for kinetic energy Ek=1/2*M*(Vmax)^2, using the fact that (again, neglecting energy wasted as heat due to friction) the energy is conserved, as no external force is working on the system, which then means that Ep,start=Ek,end => K*(dX)^2*N=1/2*M*(Vmax)^2 => Vmax = sqrt(2*K*(dX)^2/M) * sqrt(N). The first sqrt term in the final equation is all one big constant (again, K is the ratio associated with the rubber band, dX is the distance the pin travels, and M is the mass of the pin), meaning we can conclude that (C for constant) Vmax=C*sqrt(N). Finally, force applied by a moving, massive object can be calculated using Newton's second law, F=dP/dT (P is the pin's momentum, T is the time it takes for the pin to go from velocity Vmax to 0, transferring all it's energy into the gun and the bullet, but as I said, let us assume all of it goes into the bullet), or F=M*dV/dT (M, mass of the pin, dV is the difference in velocity, Vmax-0, which is simply Vmax. This is because P=M*V, which means dP=M*dV, ignoring relativity). So, F=M*C/dT*sqrt(N). The time varies slightly, but insignificantly, so let us assume it is a constant. So that's it. The force exerted by the pin on the bullet is some constant (calculatable, as mentioned and as shown), times the sqrt of N, the number of rubber bands on the gun. So there you go. Just a little something I did out of the blue the other day and thought I would share a proof of my conjecture from what feels like eons ago. I hope you enjoyed. Finally, I would like to tell you guys, perhaps as a little tease, since I'm not sure if I will ever upload it, but I have made 1 more gun after I stopped posting. I have already slightly teased about it in my user info. I guess I'll tell you guys what it is if I'm already posting something here again :) Possibly my most enjoyable, most well received, and quite innovative gun of all time? The REMPAR-2. I built the REMPAR-3 (I was also going to call it S5 when I thought about posting it). In a brief summary, it's a pump action, chambering (or bolt action as I and many others falsely used to call it), magazine fed rifle, that's only 5 layers thick all over, except one tiny area where it's 8 layers thick (1.5 extra on either side), as a reinforcement, not necessary if you use less rubber bands. Oh, actually, there's another small necessary area where it's 7 layers thick, but it's tiny and doesn't make the gun look bulky at all, and who cares. Plus, the one is around the pump, which looks quite natural, and the other is "disguised" as a detachable sight (not really detachable) that also looks fine. It also looked fairly good for a gun that I made, it used (if I remember correctly) a grand total of 0 broken pieces, which is a big accomplishment for me (the mag has some broken white rods, but fuck off), and it worked flawlessly, reaching ranges over 80ft and being able to go at 2-4 rounds per second, depending on your skill level with it. In other words, I could shoot 4rps; My girlfriend, with no experience or practice, could do 2rps, which says something about the gun's comfortability and ease of use in my opinion. It shot blue rods up to an accuracy of about 5x5cm (2x2in) over 30ft, which is amazing for a Knex gun, and it was truly super comfortable. It wasn't even long at all, which is saying a lot, looking at some other people's attempts at 5-wide pump actions (I may also be guilty of an attempt several years ago). Being quite short and only 5 wide, it is also quite light. I'm sorry, I just really liked this gun, I think it was truly my best creation ever (of course, the S3 is by far the most innovative gun I've made, but it's mostly a concept gun, not meant for real effectiveness). I may post it in the future, but I'll make no promises. I suppose I won't leave you guys completely hanging and take a picture of it. Oh yes, there's also a neat, fun little thing I did, originally because I saw no other option, but then I actually really loved it. I'm talking about the mag-lock. It locks automatically (there's a band on it, but it ripped a long time ago, so...) and the mag cannot fall out. Then you pull on it with your middle finger, similar to a trigger, and the mag just drops right out. Love it :)
Topic by Sharir1701 4 years ago | last reply 4 years ago
Question by PKTraceur 10 years ago | last reply 9 years ago
Today, I had a clear out of the workshop (Okay, shed) and found this peculiar tool. It's being lingering around for years now, and I've never been able to figure out exactly what it is and where it came from. The orange thing pushes down and locks, and when it is at the bottom a tiny metal rod appears and dissapears again at the end of the white nozzle. It holds in place until you press the orange button, at which point it fires the orange thing out at a fairly high speed, and it stops when it reaches the end of the blue channel. If you cover over the nozzle, it fires very slowly, so it probably sucks air from there. Does anybody know what this tool is?
Question by Ikkalebob 6 years ago | last reply 6 years ago
What kind of bulbs can be forced? Can they be forced in water, or does the bulb need soil?
Question by porcupinemamma 10 years ago | last reply 9 years ago
you have an unlimited power source. now is it possible to create enough force at the right "degree" that would be repelled by the earth instead of attracted.. so like a floating magnet. but its strong enough to lift large objects..... like maybe a human?
Question by fireball9919 7 years ago | last reply 7 years ago
Can anyone explain what is happening here! http://news.cnet.com/8301-17938_105-57604823-1/science-trumps-the-force-to-create-a-real-life-lightsaber/
Question by artworker 5 years ago | last reply 5 years ago
Question by kazpro 8 years ago | last reply 6 years ago
Ok, basically, i made a online multiplayer server for sta sa mp, and i was wondering if i could make it run in the system tray so i wouldnt have to worry about accidentally clicking it or something like that.. PLEASE HELP ME! i am running windows xp sp3. THANKZ!!!!!!!!!
Question by sci4me 8 years ago | last reply 8 years ago
What happens when an unstoppable force meets an immovable object? theoretically?
Question by the_mad_man 9 years ago | last reply 5 years ago
Are the lateral forces and lateral slip angles same for rear wheels and front wheel in a front (one wheel) steered rear drive vehicle?
Question by SachinK114 2 years ago | last reply 2 years ago
Question by mberg 8 years ago | last reply 8 years ago
What is/is there an equation to figure the speed a projectile travels, based on the PSI or force applied? What would this force be? k/h | fps | m/h | m/min. | k/min.|
Question by PKTraceur 10 years ago | last reply 9 years ago