# BJT under saturation condition?? Answered

Under saturation condition base current is very large that voltage across Base-emitter junction of  silicon based BJT is more than 0.7 volt. In this condition the voltage at collector (Vc) is 0.2 volt.

By kirchoff's voltage law Vc=Vce( imagine emitter is directly grounded)
Vce =Vcb+Vbe.

If Vbe>0.7volt how Vce=0.2volt?
As Vce includes Vbe, it must also be more than 0.7 volt.
But it is 0.2 volt wich is less that 0.7 volt.
How?

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## Discussions

Doesn't understand how the transistor - or perhaps resistance/current and voltage work together.

Most people want to look at BJT's as voltage operated devices because that's what their used to.

If the BJT is saturated then it's current Ice will be maximized (that's what saturated means) - so it's apparent resistance is low. (high current = low resistance - otherwise there would be a lot of heat)

So the voltage Vce will be low

(You can't measure a voltage across a short circuit)

(See 2nd down in the list on the right.)

Consider 3 points C,B,E in a straight line such that distance between C and E is same sum of the distance between C anb B +distance between B and E.
(i.e) CE=CB+BE

where CE is distance between C and E
BE is distance between B and E
CB is distance between C and B

If CE =0.2 metre , how BE=0.7 metre. BE must be less than CE na?

will CB be negative????????