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# Button cell batteries. Answered

Well, my mom knew (somehow) that I needed some button cell batteries for some experiments. (Mwuahaha)

Well, she went and got me some, but I don't know the power for any of these.

Can anybody tell me?

List:

AG1
AG3
AG4
AG10
AG12
AG13

And if this helps, they have numbers next to them saying: (in order of above)
364
392
377
389
386
357

Please help, thanks!

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## Comments

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Get a multimeter, you can pick one up on the cheap at your local hardware store. The two black and red leads at the bottom of the picture are part of it, it's the best I can do.

My dad has one, but it's different... It doesn't show the numbers and stuff, it is like the gas thing in your car, showing how many miles you go. How much do the ones cost for the digital numbers?

Not much. I'm not sure off the top of my head, but I'm sure you can get one discount at a hardware store or online for pretty cheap - less than \$20.

Forgot to add: Almost all button cells are 1.5 volts or similar, most if not all of yours are probably 1.5V

I have TONS of 675. they are 1.4

AG1 - 1.5 v AG3 & AG4- 1.55 v AG10 & AG12 & AG13 - 1.5 Essentially, they are all 1.5 v but just different sizes

So if I were to put two of them together, it would be 3v, then add in a 100 ohm resistor with an LED light, and I can do that "Awesome led cube" Instructable? (The featured one. Right now. On the homepage.)

Look.

That is an interesting piece. Yes, two batteries in series will add the voltages. Two of them in parallel would give you only 1.5 volts, but would double the amperage.

in series you might not even need a resistor because of internal resistance. To measure it short it out and measure amps, use ohms forumla

Cool! So I can use the AG10 (1.5 v), but both of them stacked up, connected to the LED, connected to the switch of my choice, and the LED won't burn out as quickly as normal?

I couldn't find amperage ratings for those cells, so I personally don't know.

Moving onto you... I'll probably just put in a 100 ohm resistor anyways.

most likely, I'd still measure the internal resistance, that's why throwies work so well

I'll probably just put in a 100 ohm resistor anyways.

So then I would need probably a 200 ohm resistor?